The first step is to make Weather a factor. Then the levels would be displayed
in the strip labels.
The second step would be to change the level values to the actual strings
you want to see.
> tmp <- data.frame(Weather=1:3, x=rnorm(3), y=rnorm(3))
> xyplot(y ~ x | Weather, data=tmp)
> tmp$Weathe
G'day Scott,
On Fri, 13 Nov 2009 09:52:43 -0700
Scott MacDonald wrote:
> I am trying to load an hdf5 file into R and running into some
> problems.
It's a while that I used hdf5 files and that package in R, but:
> This builds fine. The library seems to load without issue, but no
> data is retu
please read the 'Details' section of ?require
To suppress messages during the loading of packages use
'suppressPackageStartupMessages': this will suppress all messages
from R itself but not necessarily all those from package authors.
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609
Hello.
I've been working an a binding between OCaml and R (i.e. calling R from
OCaml, mostly). See below for a taste of it.
I'm currently wondering how to load a given R package silently. I tried
require(xts, quietly = TRUE)
but I still get some ugly output. Is it possible to squeeze
On Fri, Nov 13, 2009 at 8:05 PM, Christian Lederer
wrote:
> Hi,
>
> i am working on a biosignal package which has a data set package
> as dependency (e.g. for the examples).
> This data set package will include patient data.
> Of course, the patients will be asked for their informed
> consent, and
Besides the much more compact and probably more efficient approach of
using permutation, here is another method:
expand.grid(rep(list(c(1:3)), 3))[
lapply(
apply(
expand.grid(rep(list(c(1:3)), 3)), 1, unique),
length) ==3 , ]
On Nov 13, 2009, at 4:02 A
Hi,
i am working on a biosignal package which has a data set package
as dependency (e.g. for the examples).
This data set package will include patient data.
Of course, the patients will be asked for their informed
consent, and the data will be anonymized.
I am not sure about the appropriate licen
Thank you David for the clarification. You are absolutely right.
Best,
Jorge
On Fri, Nov 13, 2009 at 9:30 PM, David Winsemius <> wrote:
>
> On Nov 13, 2009, at 7:46 PM, Jorge Ivan Velez wrote:
>
> Hi Rachel,
>>
>> Here is a suggestion:
>>
>> index <- sample(100)
>> mysample <- gly[index, ]
>>
On Friday 13 November 2009 07:17:28 am Jgabriel wrote:
> I can't fully answer all these questions, but I'll do my best - There
> have not been any updates of Windows, and I did not update R during
> the period, although I did reinstall it after the problem started.
> There have been no changes to N
Hi folks,
i have to deal with data sets, which have a column with UTC seconds
and a second column containing the timezone.
However this timezone is not always valid in R, e.g. misspelled.
Unfortunately, the date/time functions like ISOdatetime or as.POSIXlt
silently accept invalid timezone argumen
I was reminded that the attachments were blocked by the list, so I
send these links again:
http://yihui.name/en/wp-content/uploads/2009/11/Sweave2.Rnw
http://yihui.name/en/wp-content/uploads/2009/11/Sweave2.r
http://yihui.name/en/wp-content/uploads/2009/11/Sweave2.pdf
Regards,
Yihui
--
Yihui Xie
I found the examples of how to change the code for each refactoring
activity. Are there tools that can help automate this process?
On Fri, Nov 13, 2009 at 9:16 PM, milton ruser wrote:
> Hi Peng,
>
> If that information is preliminary, so I guess you
> have a more clear problem and may be you are
Hi Peng,
If that information is preliminary, so I guess you
have a more clear problem and may be you are able to
state a minimally reproducible code/example with
what you really need.
Bests
milton
On Fri, Nov 13, 2009 at 9:30 PM, Peng Yu wrote:
> I'm wondering if there are some tips for ref
On Nov 13, 2009, at 11:19 AM, soeren.vo...@eawag.ch wrote:
Hello
a <- c("Mama", "Papa", "Papa; Mama", "", "Sammy; Mama; Papa")
a <- strsplit(a, "; ")
mama <- rep(F, length(a))
mama[sapply(a, function(x) { sum(x=="Mama") }, simplify=T) > 0] <- T
papa <- rep(F, length(a))
papa[sapply(a, function
On Fri, 13-Nov-2009 at 03:13PM +, Giulio Di Giovanni wrote:
|>
|>
|>
|> Dear all,
|>
|>
|>
|> I cannot figure out how to solve a small problem (well, not for me), surely
somebody can help me in few seconds.
|>
|>
|>
|> I have a series of strings in a vector X of the type "xxx",
Hi Michael,
I have a dirty solution as attached to use png() for Sweave.
HTH.
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609 Web: http://yihui.name
Department of Statistics, Iowa State University
3211 Snedecor Hall, Ames, IA
On Fri, Nov 13, 2009 at 10:02 AM, Michael Friendly wrote:
> In a p
On Nov 13, 2009, at 7:46 PM, Jorge Ivan Velez wrote:
Hi Rachel,
Here is a suggestion:
index <- sample(100)
mysample <- gly[index, ]
mysample
I doubt that was what he was hoping to get (which would be a
permutation of 1:100 rather than a subsample).
try:
samp <- gly[ sample(nrow(gly), 1
I'm wondering if there are some tips for refactoring in R. I found the
following website, which is still preliminary. Is there any program
that can help me do refactoring in R?
http://www.r-developer.org/projects/show/refactoring
__
R-help@r-project.org
On Nov 13, 2009, at 2:32 PM, frenchcr wrote:
hello folks,
Im trying to clean out a large file with data i dont need.
The column im manipulating in the file is called "legal status"
Their are three kinds of rows i want to remove.
Those that have "Private", "Private (Op", or "Unknown" in the
l
?sprintf
?format
# or the function format passes arguments to:
?formatC
library(ggplot2)
?comma
--
David
On Nov 13, 2009, at 5:00 PM, Anderson, Chris wrote:
I create a lot of plots with a dollar amount as the y-axis. How do I
change the formatting so comma and $ are in place. Like $1000,0
Hi Rachel,
Here is a suggestion:
index <- sample(100)
mysample <- gly[index, ]
mysample
See ?sample for more information.
HTH,
Jorge
On Fri, Nov 13, 2009 at 5:20 PM, Hayes, Rachel M <> wrote:
> Hi All,
>
>
>
> I want to take a simple random sample from a large dataset, gly, but I'm
> getting
I can't really help you with your problem, but maybe
importing with use.value.labels=FALSE will at least
get rid of the 'duplicated levels' warnings.
-Peter Ehlers
Paul Johnson wrote:
My students are working with several SPSS dataset provided by the
European Social Survey. If you register your
?subset
- Original message -
From: "frenchcr"
To: r-help@r-project.org
Date: Fri, 13 Nov 2009 11:32:35 -0800 (PST)
Subject: [R] cleanse columns and unwanted rows
hello folks,
Im trying to clean out a large file with data i dont need.
The column im manipulating in the file is called
In R for Macintosh, there is a Preferences setting that will do this.
You can also drag and drop a file onto the R icon and I believe it
will change the working directory to the directory that contains the
file.
On unix-like systems, using the command line, it's whatever directory
you start R
Alright, here's the update: the IT guy insists that the RAM is not the
problem. RAM, according to him, is "pretty black and white". There
should be enough RAM on the system for the function to work, and he
was the one who installed the extra RAM in the first place. Could
there be another RAM issue
Hi,
splitting is a good idea..it kills a loop...I keep forgetting this.
I have to try out a bit, whether it covers it all, I'll let you know but
thanks for a start.
It is not really analysing, but exploring the data. I have some plots with
sevendigits points and some things are weird and I try t
hello folks,
Im trying to clean out a large file with data i dont need.
The column im manipulating in the file is called "legal status"
Their are three kinds of rows i want to remove.
Those that have "Private", "Private (Op", or "Unknown" in the legal_status
column.
I wrote this code but it sy
Jerome Chong gmail.com> writes:
>
> Greetings,
>
> What I want to do is to perform regression the data set to get a
> revenue function, and use that revenue function to find the maximum
> point (maybe with some constraints applied).
> The regressed revenue function would most likely be in a qua
Hello everyone,
I was wondering if anyone knows of an R package which will extract the
standardised effect size (r) and 95% confidence intervals for a single
continuous predictor in a mixed-effects model. For example, I have
model<-lme(damage~car+depth+wet,random=~1|id,data=data)
I need to fin
Dear Sir or Madam:
I am Shaojuan Liao, the 3rd year Ph.D. student from Econ Department,
Virginia Tech.
I don't know whether it is appropriate to ask you questions on the
command pgmm. But I don't know how to deal with the case where all X are
exogenous and all T time periods' X can be used a
I create a lot of plots with a dollar amount as the y-axis. How do I change the
formatting so comma and $ are in place. Like $1000,000 or to use common dollar
abbreviations like 100K?
Chris Anderson
Data Analyst
Medical Affairs
wk: 925-677-4870
cell: 707-315-8486
Fax:925-677-4670
This elect
Prof. Ripley kindly pointed out to me that the "digits" parameter in
text.tree() is intended to work on numeric labels. The values that I
wanted to modify are not labels (at least not the ones so controlled),
nor are they numeric.
I have since figured out how to do what I want. The values I wa
I would like to analyze XML data from MLB's website. I do the following
steps:
library(XML)
dat<-"http://gd2.mlb.com/components/game/mlb/year_2007/month_05/day_02/gid_2007_05_02_arimlb_lanmlb_1/inning/inning_1.xml";
example<- xmlTreeParse(dat, useInternalNodes=T)
ex<-xpathApply(example, "//inning
Hi useRs,
I'm trying to fit a basic AR(2) model with the 'ar' function. And when
I try to check the value of the coefficients, I could not find the
same value as the 'ar' function.
Here is my example:
myserie <- c(212, 205, 210, 213, 217, 222, 216, 218, 220, 212, 215, 236)
#plot(myserie, t
Rachel,
The first thing to do when a function gives you trouble is
to look at its help page. In the case of sample(), you will
find that it requires a *vector* input. Is your gly a vector?
-Peter Ehlers
Hayes, Rachel M wrote:
Hi All,
I want to take a simple random sample from a large dat
My students are working with several SPSS dataset provided by the
European Social Survey. If you register your name, you can download it
too. This is the 2004 data, for example:
http://ess.nsd.uib.no/ess/round2/
I cannot give you the European Survey dataset, but you can download it
for free if yo
Hi All,
I want to take a simple random sample from a large dataset, gly, but I'm
getting an error message. Any help?
dim(gly)
[1] 112371 37
> s1 <- sample(gly,100)
Error in `[.data.frame`(x, .Internal(sample(length(x), size, replace, :
cannot take a sample larger than the popul
Hello,
Can anyone explain why the following message appears for the function
model.tables, where se=T? In the V&R MASS text, p.285 the se=T option works
for a split plot example that seems similar to my operation. But the
model.tables documentation, in the Arguments section for "se", states
I am using tree() in some classification work, and have been trying to
suppress the number of significant digits shown in the output plot.
There is a "digits" parameter that can be used in text.tree(), but I
can't seem to make it have any effect. Here is some example code to
illustrate what I m
ok thanks guys for the help, indeed I assumed there was an explanation thank
you duncan for giving it!
--
View this message in context:
http://old.nabble.com/Simple-if-else-statement-problem-tp26340336p26343665.html
Sent from the R help mailing list archive at Nabble.com.
_
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of
> soeren.vo...@eawag.ch
> Sent: Friday, November 13, 2009 12:24 PM
> To: r-help@r-project.org
> Subject: [R] when use which()
>
> Hello:
>
> # some code to assign with and wit
On Wed, 11 Nov 2009, David Winsemius wrote:
On Nov 11, 2009, at 7:45 PM, Mauricio Calvao wrote:
When I try:
fit_mod <- lm(y~x,weights=1/error^2)
I get
Warning message:
In lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) :
extra arguments weigths are just disregarded.
(Ac
Hello:
# some code to assign with and without "which"
q <- 1:20; q[c(9, 12, 14)] <- NA
r <- 1:20; r[c(8:9, 12:15)] <- NA
s <- 1:20; s[c(8:9, 12:15)] <- NA
r[q < 16] <- 0
s[which(q < 16)] <- 0
r;s # both: 0 0 0 0 0 0 0 0 NA 0 0 NA 0 NA 0 16 17 18 19 20
r <- 1:20; r[c(8:9, 12:15)] <- NA
On Fri, 13 Nov 2009, milton ruser wrote:
Hi Ana, you did again :-)
require(fortunes)
fortune("dog")
Firstly, don't call your matrix 'matrix'. Would you call your dog 'dog'?
Anyway, it might clash with the function 'matrix'.
-- Barry Rowlingson
R-help (October 2004)
if you call your dat
Hi Ana, you did again :-)
> require(fortunes)
> fortune("dog")
Firstly, don't call your matrix 'matrix'. Would you call your dog 'dog'?
Anyway, it might clash with the function 'matrix'.
-- Barry Rowlingson
R-help (October 2004)
if you call your data "data" you will crach data() function.
anna_l wrote:
Ok Jim it worked, thank you! it´s funny because it worked with the first
syntax in some cases...
No, it did not. R doesn't randomly work in different
ways on different days.
-Peter Ehlers
anna_l wrote:
Hello, I am getting an error with the following code:
if( P2 > P1)
+ {
You can try something about like this:
foo <- function() {
unlink("file3.txt")
file.rename("file2.txt", "file3.txt")
file.rename("file1.txt", "file2.txt")
sink("file1.txt")
cat("test file1")
sink()
}
On Fri, Nov 13, 2009 at 5:20 PM, Don MacQueen
I am wondering if there is a CRAN package that includes a utility
function that will "rotate" file names, in the same sense that
operating systems sometimes rotate log files. Or maybe there's
something in base R.
That is, we have a set of file names, say file1, file2, file3, and
when the func
[Going through some old and from what I see unanswered messages]
R can or cannot response immediately depending on the underlying C
sources. If the underlying source code is written carefully enough,
there are more or less regular checks for events such as this one.
If you are using some contri
Hi Knut,
Try
sum(subset(df, row1 == 3 & row2 == 2)[,1])
and
nrow(subset( df, row1 == 3 & row2 == 2) )
HTH,
Jorge
On Fri, Nov 13, 2009 at 1:59 PM, Knut Krueger <> wrote:
> Hi to all
> is there any construct to sum
> data=data.frame(row1=c(1,1,3,1,2,3,2,2,1,3,4,5,2,3,2,1) ,
>
Try this:
sum(data[with(data, row1 == 3 & row2 == 2),1])
and
sum(with(data, row1 == 3 & row2 == 2))
On Fri, Nov 13, 2009 at 4:59 PM, Knut Krueger wrote:
> Hi to all
> is there any construct to sum
> data=data.frame(row1=c(1,1,3,1,2,3,2,2,1,3,4,5,2,3,2,1) ,
> row2=c(2,2
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Hadley Wickham
> Sent: Friday, November 13, 2009 5:34 AM
> To: r-help
> Subject: [R] Escaping regular expressions
>
> Hi all,
>
> Is there a method for escaping strings to be us
[Going through some old and from what I see unanswered messages
No, you cannot have a cycle in Imports / Depends / LinkingTo
otherwise you will run into an "the chicken or the egg" problem:
That declaration means that the other packages must be loadable on
installation, for example.
You can tr
Hi to all
is there any construct to sum
data=data.frame(row1=c(1,1,3,1,2,3,2,2,1,3,4,5,2,3,2,1) ,
row2=c(2,2,1,1,1,2,1,2,1,1,1,1,2,2,2,1) )
Means I would like to get all y of row1 if in row2 of the data.frame is
an x
f.e row1=3 and row2=2
so I would like to get 6
And is
[Going through some old and from what I see unanswered messages
This was a bug in the installer that nobody reported during the test
phases (alpha / beta / release candidate). So please try out new R
releases in order to help finding such bugs before release.
The installer cannot be tested ea
[Going through some old and from what I see unanswered messages
Hard to tell what is going on without telling us the data. Works with
the examples, so may be related to one of the objects scicomp5.model1,
pred, T, or auc.
> PLEASE do read the posting guide
http://www.R-project.org/posting-g
Dear Wolfgang Viechtbauer and R users,
I have few questions regarding the development of the package 'metafor.
As you suggested , I post to the R-help mailing list.
I read you're planning an extension of this method to the multivariate case.
I think it would be a useful tool.
I'm currently perf
On 11/13/2009 11:41 AM, Thomas Unternaehrer wrote:
I need some random numbers in my C program. Here a small example:
#include
void rand (int* n)
{
int len = *n;
for (int i = 0; i < len; i++)
Rprintf("%1.5f
[Going through some old and from what I see unanswered messages
See Writing R Extensions: The contents of subdirectory ./inst will be
copied to top level during package installation (i.e. also for making
binary packages).
Best wishes,
Uwe Ligges
morp...@comcast.net wrote:
My OS is Windows
On 11/13/2009 12:54 PM, anna_l wrote:
Ok Jim it worked, thank you! it´s funny because it worked with the first
syntax in some cases...
If R knows the whole thing is incomplete, it will accept an else on its
own line. If the first 4 lines make a complete statement, R will
evaluate it, and not
On Fri, Nov 13, 2009 at 11:49 AM, Sam Albers wrote:
> No problem not use my data. For future reference, would it have been easier
> to attach a .csv file and then include the appropriate read.csv command? I
> realized that the easier one makes it to help, the easier it is to get a
> response.
>
>
Ups... I've overlooked that part. Thanks a lot for the fast response!
On Fri, Nov 13, 2009 at 6:05 PM, Duncan Murdoch wrote:
> On 11/13/2009 11:41 AM, Thomas Unternaehrer wrote:
>
>> I need some random numbers in my C program. Here a small example:
>>
>>
>> //
Thanks all.
"%in%" is what i need.
2009/11/13 jim holtman
> I think you want to use '%in%' instead of '=='. Try debugging (or
> understanding) what is happening by evaluating the subexpressions of
> the compares you have in your original posting. Also take a look at
> the 'recycling' of argum
Mark,
It looks like removeWords removed "the" in all instances except when
"the" was the first word in your text. Maybe there is a parameter that
needs to be set? I couldn't find anything on the help page.
Here's an example of what I am seeing using the "crude" dataset
#function re
Jgabriel wrote:
I can't fully answer all these questions, but I'll do my best - There
have not been any updates of Windows, and I did not update R during
the period, although I did reinstall it after the problem started.
There have been no changes to Norton or any other software that uses
syste
You can use aggregate to get this too:
aggregate(table.users[,c('UserName', 'Machine')], table.users['Date'],
function(x)length(unique(x)))
On Fri, Nov 13, 2009 at 3:01 PM, Jabez Wilson wrote:
> Thanks, that's helpful because I can see the individuals and how many times
> they accessed:
> The '
Ok Jim it worked, thank you! it´s funny because it worked with the first
syntax in some cases...
anna_l wrote:
>
> Hello, I am getting an error with the following code:
> if( P2 > P1)
> + {
> + P<-P2
> + }
>> else
> Erro: unexpected 'else' in "else"
>> {
> + P<-P1
> + }
>
> I checked the synta
Did you make the changes before or after starting the device:
library(lattice)
## before doesn't change the settings on the device:
trellis.par.set(plot.symbol = list(col = "red"))
trellis.device(pdf, file = "tmp.pdf")
xyplot(1 ~ 1)
dev.off()
## after does
trellis.device(pdf, file = "tmp.pdf")
tr
Anna,
I think the else needs to be on the same line
as the curly bracket like this "} else".
P1 <- 1
P2 <- 2
if( P2 > P1)
{
P<-P2
} else
{
P<-P1
}
Good luck,
Jim
anna_l wrote:
Hello, I am getting an error with the following code:
if( P2 > P1)
+ {
+ P<-P2
+ }
else
Erro: unexpe
align the else with the curly brackets
if (yes){
be happy
}else{
complain
}
b
On Nov 13, 2009, at 3:33 PM, anna_l wrote:
Hello, I am getting an error with the following code:
if( P2 > P1)
+ {
+ P<-P2
+ }
else
Erro: unexpected 'else' in "else"
{
+ P<-P1
+ }
I checked the syntax so I don´
Hi all,
I've got some problems when changing the trellis settings for the lattice
plots. The plots look exactly as I want them to when calling show.settings() as
well as when plotting them in the graphical window. But when printing to a pdf
file, none of the settings are used!? Does anyone
Hello, I am getting an error with the following code:
if( P2 > P1)
+ {
+ P<-P2
+ }
> else
Erro: unexpected 'else' in "else"
> {
+ P<-P1
+ }
I checked the syntax so I don´t understand, I have other if else statements
with the same syntax working. Thanks in advance
--
View this message in context:
Hello All,
I have downloaded and untarred R 2.10.0 onto my SUN UNIX machine. When I
run ./configure, it runs through a series of questions and stops at this
(and I get this when I try the make command):
checking for iconv.h... yes
checking for iconv... in libiconv
checking whether iconv accept
I can't fully answer all these questions, but I'll do my best - There
have not been any updates of Windows, and I did not update R during
the period, although I did reinstall it after the problem started.
There have been no changes to Norton or any other software that uses
system resources in that
Thanks, that's helpful because I can see the individuals and how many times
they accessed:
The 'plyr' solution of Karl Ove Hufthammer gives me the exact summary
statistics that I'm looking for.
Jab
--- On Fri, 13/11/09, markle...@verizon.net wrote:
From: markle...@verizon.net
Subject: Re:
Hello All,
I just signed up to this list, so I apologize if this question has been
asked before.
I am trying to load an hdf5 file into R and running into some problems. Here
are the steps I took to configure my environment:
* R 2.10.0 (x64) on Mac OS X 10.6
* hdf5 1.8.3 installed via mac
> Hello R list,
>>
>> This is a question for anyone who has used the by() command. I would like
>> to
>> perform a regression on a data frame by several factors. Using by() I
>> think
>> that I have able to perform this using the following:
>>
>> lm.r <- by(master, list(Sectionf=Sectionf, startd=s
Sam,
Thanks for the example. Removing stop words after the DocumentTermMatrix has
been created works fine if one is working with single words, but what if one
is creating a dtm of possible combinations of words? Wouldn't one want to
remove them from the corpus?
Mark
Mark W. Kimpel MD ** Neuroin
Hello, I am trying to save some changes I have done on the Rprofile.site
under vista and it doesn´t let me save the file saying that it can´t create
the following file (Rprofile.site) and that I should check the pathfile or
the file name.
--
View this message in context:
http://old.nabble.com
I need some random numbers in my C program. Here a small example:
#include
void rand (int* n)
{
int len = *n;
for (int i = 0; i < len; i++)
Rprintf("%1.5f ", unif_rand());
}
dyn.load("rand.dll")
.C("rand",
On Fri, Nov 13, 2009 at 9:53 AM, Peng Yu wrote:
> library(some_library_name)
Try
help(package = some_library_name)
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the pos
The maintainer's email address is listed in the package
documentation... as I think is the case with all CRAN packages.
-Ista
On Fri, Nov 13, 2009 at 11:20 AM, amor Gandhi wrote:
> Thank you for your reply.
>
> The only contact address of the maintainer is
> http://www-stat.stanford.edu/~tibs/SA
Thank you for your reply.
The only contact address of the maintainer is
http://www-stat.stanford.edu/~tibs/SAM
However, one find no contact when one visit this page.
I am not a mathematician, therefore, it is strange for me to get probability
bigger that 1, if it is like that should I trust
Hello
a <- c("Mama", "Papa", "Papa; Mama", "", "Sammy; Mama; Papa")
a <- strsplit(a, "; ")
mama <- rep(F, length(a))
mama[sapply(a, function(x) { sum(x=="Mama") }, simplify=T) > 0] <- T
papa <- rep(F, length(a))
papa[sapply(a, function(x) { sum(x=="Papa") }, simplify=T) > 0] <- T
# ... more varia
On Fri, 13 Nov 2009, Michael Friendly wrote:
In a package I'm working on there is a vignette with a number of graphs that
result in huge .pdf files, so
the .pdf for the vignette is around 17 Mb. If these graphs are converted to
.png, and the .tex file
is compiled with pdflatex, the resulting
On 11/13/2009 04:53 PM, Peng Yu wrote:
library(some_library_name)
Suppose I load a library.
You mean "package" right ? A library is a set of packages
I'm wondering what command I should use to
list all the functions, classes and variables defined in the library.
Check ?ls :
> ls( "packag
Hello
The "Craddock-Flood Test" is recommended for large tables with small
degrees of freedom and low-frequency cells. Is there an R procedure
and/or package which does the test?
Thank you for your help!
Sören Vogel
--
Sören Vogel, Dipl.-Psych. (Univ.), PhD-Student, Eawag, Dept. SIAM
http
In a package I'm working on there is a vignette with a number of graphs
that result in huge .pdf files, so
the .pdf for the vignette is around 17 Mb. If these graphs are
converted to .png, and the .tex file
is compiled with pdflatex, the resulting .pdf is ~1 Mb.
I'm reluctant to put the .Rnw f
library(some_library_name)
Suppose I load a library. I'm wondering what command I should use to
list all the functions, classes and variables defined in the library.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEAS
Dear Users,
I have corrected the errors. Many thanks.
For this error,
> [1] "put.var.ncdf: warning: you asked to write 1440 values, but the passed
> data array has 37440 entries!"
I added start= c(1,1,1), count=c(length(lons),length(lats),length(nt)) in the
put.var.ncdf function.
so put.var.n
Do you want to replace the whole word or the whole string? If the
latter, use
sub("^Ig.*", "0", x)
(Matching is greedy, so .* matches are many characters as possible,
here the rest of the string.)
If 'whole word', we need a precise definition of word, but
sub("^Ig\\w*", "0", x)
is one con
Jim, Dennis,
Once again, thanks for all your suggestions. After developing a more R-like
version of the script I terminated the running one after 976 (of 1697) reports
had been processed. At that point, the script had been running for approx.
33.5 hours! Here is the new version:
library(fileha
Isn't this more straightforward?
w <- grep("^Ig", vec)
vec[w] <- "0"
Regards, Adai
Giulio Di Giovanni wrote:
Dear all,
I cannot figure out how to solve a small problem (well, not for me), surely
somebody can help me in few seconds.
I have a series of strings in a vector X of t
Here are two ways:
> s <- c("xxx", "yyy", "zzz", "IgA", "IgG", "kkk", "IgM", "aaa")
>
> sub("^Ig.*", "0", s)
[1] "xxx" "yyy" "zzz" "0" "0" "kkk" "0" "aaa"
>
> replace(s, grepl("^Ig", s), "0")
[1] "xxx" "yyy" "zzz" "0" "0" "kkk" "0" "aaa"
On Fri, Nov 13, 2009 at 10:13 AM, Giulio Di Gi
On Nov 13, 2009, at 9:13 AM, Giulio Di Giovanni wrote:
Dear all,
I cannot figure out how to solve a small problem (well, not for me),
surely somebody can help me in few seconds.
I have a series of strings in a vector X of the type "xxx", "yyy",
"zzz", "IgA", "IgG", "kkk", "IgM", "
Dear all,
I cannot figure out how to solve a small problem (well, not for me), surely
somebody can help me in few seconds.
I have a series of strings in a vector X of the type "xxx", "yyy", "zzz",
"IgA", "IgG", "kkk", "IgM", "aaa".
I want to substitute every ENTIRE string beginning
Hi everybody,
probably a really stupid question. I updated to 2.10 recently and was
surprised that the help function comes in a different format, i.e. in
the "old-style" as single pages for each function. I know I can use the
html format in a browser, but would prefer the "in-between" format w
\w+ will match one or more word characters and \s* will match 0 or
more spacing characters so if this must the described text must be the
complete expression then:
grepl("^\\w+\\s*\\(\\s*\\w+\\s*\\)$", x)
or if its ok for other text to appear before and after as long as the
indicated text is amon
This is not minimal (it will escape every non-word character) but is
short and the needlessly escaped ones should do no harm (though you
might want to double check that assumption on a few examples):
gsub("(\\W)", "\\1", x)
On Fri, Nov 13, 2009 at 8:33 AM, Hadley Wickham wrote:
> Hi all,
>
>
.Rprofile is executed everytime you start up R
On Fri, Nov 13, 2009 at 8:34 AM, anna_l wrote:
>
> Hello, I am using setwd() to change the working directory but I have to enter
> it everytime I open R, is there a way to set this permanently as a working
> directory? Thanx =^D
>
> --
> View this me
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