Hi Milton,
The matrix can be generated using
p = matrix(1:50, nrow=5)
If I just use levelplot(p), it gives me a graph that is vertical. How
can I rotate it so it becomes horizontal?
I cannot do
q = t(p); levelplot(q)
because this is representing a map from a piece of land, transposing
the data
Dear R helpers,
I am trying to understand how to use the independence_test function in
the coin package. I think I suffer from a misunderstanding about what
the package does. Either that or I do not understand how to use it
properly. Specifically, I cannot understand if I can test independence
of a
Hi everyone,
I wonder if there already exists any R packages containing all the
data sets for the book "The Statistical Sleuth"
(http://www.proaxis.com/~panorama/home.htm; also available at StatLib
http://lib.stat.cmu.edu/datasets/sleuth).
I'm writing an R package with a friend for one of our sta
I can define a list containing NULL elements:
> myList <- list("aaa",NULL,TRUE)
> names(myList) <- c("first","second","third")
> myList
$first
[1] "aaa"
$second
NULL
$third
[1] TRUE
> length(myList)
[1] 3
However, if I assign NULL to any of the list element then such
element is deleted from the
Hi Kang,
Could you send a reproducible sample-code?
Bests
miltinho
On Sat, Oct 24, 2009 at 11:32 PM, Kang Min wrote:
> Hi all,
>
> I have a matrix with 5 rows and 10 columns, which represent the grids
> on a rectangular map.
> I used the code below to plot, but it gives me the map with the 1
Michael -
It sounds like there something different in the
parts of the data you're not including. If another
poster's suggestion of specifying analysis variables
instead of id variables doesn't work, and you can send
me the data set, I'd be happy to take a look.
Hi all,
I have a matrix with 5 rows and 10 columns, which represent the grids
on a rectangular map.
I used the code below to plot, but it gives me the map with the 10
columns as y-axis, and the 5 rows as the x-axis, and the (0,0) point
is at the usual bottom left hand corner. My map starts with th
On Sat, 2009-10-24 at 18:47 +0200, Uwe Ligges wrote:
>
> Ross Boylan wrote:
> > I notice that the intervals package indicates a dependence on R >=
> > 2.9.0. Is there some feature of R 2.9 that intervals depends on, or
> > might it work with R 2.7.1, which I am running?
>
>
> Don't know, but yo
Hello:
Is there an easy way to fit a correlated hazard model in R?
Basically, I have two events of interest for each individual, and I suspect
there is some
correlation involved. I want to be able to fit two separate hazard models,
allowing for possible
correlation. In addition, some of the covar
Johannes Graumann wrote:
> Thanks for your input. If I understand correctly, XPath requires the whole
> document to be resident in memory. That is not an option given the size of
> documents I'm facing ... I'll go with the standard streaming implementation
> of
> the XML package and see how f
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi,
I'm doing some basic operations on large sparse matrices, for example
getting a row.
it takes close to 30 seconds on a 3Ghz machine, and shots the memory
usage up to the sky.
I suspect there are dense intermediary steps (which, if true would
defe
Johannes Graumann wrote:
> Hi,
>
> I had heard that Expat is was faster. Your mail actually made me go check
> google for some comparisons and that does not seem the case ... do you have
> any insight into this?
A couple of points..
i) At this point, I don't have any data about which of libx
At 04:53 PM 10/24/2009, R_help Help wrote:
Hi - I ran into a problem when the argument to gamma function is
large. Says, if I do the following:
> gamma(17000)
[1] Inf
Warning message:
value out of range in 'gammafn'
Is there anyway to get around this or other implementation? Thank you.
-rc
T
Use the lgamma function.
> log(gamma(170))
[1] 701.4373
> lgamma(170)
[1] 701.4373
>
In typical uses of gamma(), they are multiplied or divided
by other gamma() values, bringing the final result into the
range of double precision numbers.
Also, look at beta(), which does those divisions of gamm
Hi - I ran into a problem when the argument to gamma function is
large. Says, if I do the following:
> gamma(17000)
[1] Inf
Warning message:
value out of range in 'gammafn'
Is there anyway to get around this or other implementation? Thank you.
-rc
__
On 24-Oct-09 20:28:04, Barry Rowlingson wrote:
> On Sat, Oct 24, 2009 at 9:09 PM, Marius Hofert wrote:
>> Dear R-Users,
>>
>> I have the following problem: I would like to create a postscript
>> file containing an r-plot with the string "\\vartheta" in it
>> (reason: this is later converted to th
Thank you very much. I am a newcomer to R and your quick response is very
much appreciated. I obviously have more reading to do.
pk
HBaize wrote:
>
>
> What I think you are missing is that you didn't change ddd. The ifelse
> statement does not assign values to the ddd object. To change dd
On Sat, Oct 24, 2009 at 9:09 PM, Marius Hofert wrote:
> Dear R-Users,
>
> I have the following problem: I would like to create a postscript file
> containing an r-plot with the string "\\vartheta" in it (reason: this is
> later converted to the TeX-string "\vartheta" and a vartheta is printed in
>
Uwe Ligges-3 wrote:
>
>
> Whole table? Each variable against every other variable? Or something
> else? Do you think that makes sense?
> Anyway, you can calculate all combinations of 2 unique columns and
> iterate over them.
>
> Uwe Ligges
>
In the variable X2 I have encoded men and women
Have a look at:
map("county", fill=TRUE , col=palette() , resolution=0, lty=0)
HTH,
Ray Brownrigg
Anthony Damico wrote:
I'm working with the nationwide county maps data, and trying to remove the
internal county boundary lines. The only map() function parameter that I've
found that gets me anyw
forestra wrote:
>
> Hello to everybody,
>
> I need to know the Smoothing Parameter to obtain Home Range of an animal
> through the Area Kernel. I have 200 locations with x and y. How can I
> obtain the Smoothing Parameter with R for LSCV, CV and Href method???
>
>
We're sorry, but this is
Dear R-Users,
I have the following problem: I would like to create a postscript file
containing an r-plot with the string "\\vartheta" in it (reason: this
is later converted to the TeX-string "\vartheta" and a vartheta is
printed in the figure). In the minimal example below, the problem is
If you don't want the county boundaries, then don't use the county map. There
is the state database that does not have county information.
If you want the counties different colors, but no dividing lines, then you may
want to try the maptools and sp packages (shapefiles for the states/counties
I'm working with the nationwide county maps data, and trying to remove the
internal county boundary lines. The only map() function parameter that I've
found that gets me anywhere close to my desired result leaves small white
segments on parts of the map. I believe this is due to the low resolutio
You probably have other id variables in featureData. Try specifying
the measured variables instead of the id variable(s). See
?melt.data.frame
for details.
-Ista
On Sat, Oct 24, 2009 at 1:58 PM, Michael Jones wrote:
> If I make the data from smaller:
>
> featureDataHead = head(featureData)
>
Also, to further clarify. When you source or batch file R scripts, objects
are only printed to the screen if you use a print function. That is why the
result of the ifelse does not appear.
Your original example would have shown the expected result of the ifelse if
it had read:
print(ifelse ( d
Hi Joh.
What particular aspects of expat do you want that libxml2 and
the XML package currently cannot provide?
The early versions of the XML package (for the first few years)
could support expat and libxml2 as the C++/C-level parsers.
However, the support for expat was not maintained, so while
pking wrote:
When I run this code from an R-script:
ddd = 360 + round ( atan2(-u,-v) / d2r )
print(class(ddd))
print(ddd)
ifelse ( ddd>360, ddd-360, ddd )
print(ddd)
I get this output:
[1] "numeric"
[1] 461 213 238 249 251
[1] 461 213 238 249 2
If I make the data from smaller:
featureDataHead = head(featureData)
featureDataHead = featureDataHead[ , 1:4]
melt(featureDataHead,id.var='feature',variable_name='cell.line')
It works fine
On Sat, Oct 24, 2009 at 1:54 PM, Michael Jones wrote:
> Thanks Phil,
>
> That worked great for the t
Thanks Phil,
That worked great for the test case below but when I tried it on a
really big data.frame I get the error
$ melt(featureData,id.var='feature',variable_name='cell.line')
Error in data.frame(ids, x, data[, x]) :
arguments imply differing number of rows: 1312, 1, 0
featureData has the
When I run this code from an R-script:
ddd = 360 + round ( atan2(-u,-v) / d2r )
print(class(ddd))
print(ddd)
ifelse ( ddd>360, ddd-360, ddd )
print(ddd)
I get this output:
[1] "numeric"
[1] 461 213 238 249 251
[1] 461 213 238 249 251
Why does ifel
Hi,
How can I make the result of the following lines "TRUE"?
> install.packages("XML")
> library(XML)
> supportsExpat()
[1] FALSE
I'm on linux, looked into the actual package, but don't seem to be able to
wrap my head around how to compile this in ...
Any pointers are welcome,
Thanks Joh
What I think you are missing is that you didn't change ddd. The ifelse
statement does not assign values to the ddd object. To change ddd it would
read:
ddd <- ifelse ( ddd>360, ddd-360, ddd )
So when you enter "print(ddd)" you get the content of the original object,
which has not changed.
Wha
makhija.sange...@gmail.com wrote:
Following is my query:
1. Removing Inf from one column of dataframe.
2. out of 10 available dates, count how many times a security is present.
(repeat for each security)
3. Out of dates, the security is present, I want to read latest status of
market cap.
4.
1. You forgot to give a *reproducible* example as the posting guide asks
you to do.
2. Both packages you mentioned are BioConductor packages. Note that the
BioConductor project has its own mailing list.
Best wishes,
Uwe Ligges
Wendy Chen wrote:
Hi all,
I have loaded the LIMMA and Biobas
Ross Boylan wrote:
I notice that the intervals package indicates a dependence on R >=
2.9.0. Is there some feature of R 2.9 that intervals depends on, or
might it work with R 2.7.1, which I am running?
Don't know, but you could try - bus don't expect the results are valid.
The maintainer p
Robin, see below my inserted comments.
Robin Hankin wrote:
Hello Dimitris
thanks for this. It works! I guess I was fixated on the dollar sign.
I must confess that I don't really understand any of the error
messages below. Can anyone help me interpret them?
rksh
Dimitris Rizopoulos wr
I think it would be much easier to use grid-graphics for your task.
It's made for such things.
This is a good introduction:
Paul Murrell. The grid graphics package. R News, 2(2):14-19, June 2002
Tom
__
R-help@r-project.org mailing list
https://stat.
Hi Peng,
Try
lapply(L, paste, collapse="")
$x
[1] "ab"
$y
[1] "ab"
HTH,
Jorge
On Sat, Oct 24, 2009 at 12:02 PM, Peng Yu <> wrote:
> I use lapply to apply a function to the list 'L'. But of course, the
> list names in 'X' is not maintained. I'm wondering if there is a
> function that can mai
I use lapply to apply a function to the list 'L'. But of course, the
list names in 'X' is not maintained. I'm wondering if there is a
function that can maintain the list names as well as apply the
function.
$ Rscript lapply.R
> L=list(x=c('a','b'), y=c('a','b'))
> L
$x
[1] "a" "b"
$y
[1] "a" "b"
Ning Ma wrote:
Hi everybody,
I use par(mfrow=c(2,2)) to draw 4 sub figures. The default white space
between columns is a litte large. Is there any parameters to control
it?
There is no white space between it - except for the margins of the
separate plots that can be controlled with par("ma
Perhaps functional data analysis would be of interest. See, for
example, package fda.
Kingsford
On Fri, Oct 23, 2009 at 4:46 PM, Dylan Beaudette
wrote:
> Hi,
>
> I have fit a series of ols() models, by group, in this manner:
>
> l <- ols(y ~ rcs(x, 4))
>
> ... where the series of 'x' values in
Iurie Malai wrote:
Hi,
I have a data set:
Dataset
X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 X11 X12 X13 X14 X15 X16 X17
1 user1 m 22 19 28 24 12 18 9 7 4 5 4 7 5 7 9
2 user2 f 25 19 23 18 18 15 6 8 6 6 7 10 7 7 7
3 user3 f 28 21 24 18 15 12 10 6 7 9
Noah Silverman wrote:
Hi,
I have a process using svm from the e1071 library.
It's called a *package* which is probably installed in a *library* of
packages.
it works.
I want to try using the KSVM library instead. The same data used wiht
e1071 gives me an error with KSVM.
I guess y
It is so dramatical. Thank Gabor Grothendieck . I got it.
Gabor Grothendieck wrote:
>
> Google for
> CRANberries aggregates
> and check first hit.
>
> On Sat, Oct 24, 2009 at 4:44 AM, bbslover wrote:
>>
>> there are many R packages, yesterday, 2031 but today 2033 packages. how
>> can I
>> kown
Hi everybody,
I use par(mfrow=c(2,2)) to draw 4 sub figures. The default white space
between columns is a litte large. Is there any parameters to control
it?
Thanks in advance!
Ma
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listi
Erich Neuwirth wrote:
> I am running R as an invisible subprocess in another program (RExcel).
> Using try I can catch errors and print the errors produced by an R
> statement.
> Is there a way to know if running a statement caused a warning message?
> last.warning gives me the last warning, but I
Hello,
Adding to Thomas' email, you could also use package colbycol which
allows you to load into R files that a simple read.table cannot cope
with, study columns independently, select those you are more interested
in and, finally, set up a dataframe with just the columns you are
interested in.
I
Dylan Beaudette wrote:
On Friday 23 October 2009, Frank E Harrell Jr wrote:
Dylan Beaudette wrote:
Hi,
I have fit a series of ols() models, by group, in this manner:
l <- ols(y ~ rcs(x, 4))
... where the series of 'x' values in each group is the same, however
knots are not always identical b
At 12:36 23/10/2009, Tord Snäll wrote:
Dear all,
A question related to the following has been
asked on R-help before, but I could not find any
answer to it. Input will be much appreciated.
The vignette explains this, and much more. I
found it extremely instructive both for its
intended purp
Medha Atre gmail.com> writes:
>
> Hi,
>
> I found the reason. By default it puts a condition for x >= 0. Is
> there a way to get rid of this condition?
The constraints x >= 0 are used in most linear programming realizations.
Some bounds from below are needed. The trick to circumvent the restr
Samiul Hasan wrote:
Hi
I have estimated a hazard function using a kernel based method. Now i have
to generate a random variate that follows this hazard function. Does any one
know method I should use to generate the variate.
Thanks
Samiul
As far as I remember, the relation that you need is tha
Google for
CRANberries aggregates
and check first hit.
On Sat, Oct 24, 2009 at 4:44 AM, bbslover wrote:
>
> there are many R packages, yesterday, 2031 but today 2033 packages. how can I
> kown which package is added, or updated?
> --
> View this message in context:
> http://www.nabble.com/how-ca
there are many R packages, yesterday, 2031 but today 2033 packages. how can I
kown which package is added, or updated?
--
View this message in context:
http://www.nabble.com/how-can-I-kown-which-package-is-added%2C-or-updated--tp26037150p26037150.html
Sent from the R help mailing list archive at
thank you Don MacQueen , I will try it.
Don MacQueen wrote:
>
> At 4:57 AM -0700 10/23/09, bbslover wrote:
>>Steve Lianoglou-6 wrote:
>>>
>>> Hi,
>>>
>>> On Oct 22, 2009, at 2:35 PM, bbslover wrote:
>>>
Usage
data(gasoline)
Format
A data frame with 60 observations on t
I have try it, past can add to wanted letter, but can not past the colume
names. May be I should learn it hard.
Don MacQueen wrote:
>
> At 4:57 AM -0700 10/23/09, bbslover wrote:
>>Steve Lianoglou-6 wrote:
>>>
>>> Hi,
>>>
>>> On Oct 22, 2009, at 2:35 PM, bbslover wrote:
>>>
Usage
d
Hi
I have estimated a hazard function using a kernel based method. Now i have
to generate a random variate that follows this hazard function. Does any one
know method I should use to generate the variate.
Thanks
Samiul
--
View this message in context:
http://www.nabble.com/Generate-random-varia
Hello to everybody,
I need to know the Smoothing Parameter to obtain Home Range of an animal
through the Area Kernel. I have 200 locations with x and y. How can I obtain
the Smoothing Parameter with R for LSCV, CV and Href method???
Thank you.
--
View this message in context:
http://www.
Erich Neuwirth wrote:
I am running R as an invisible subprocess in another program (RExcel).
Using try I can catch errors and print the errors produced by an R
statement.
Is there a way to know if running a statement caused a warning message?
last.warning gives me the last warning, but I do not h
I am running R as an invisible subprocess in another program (RExcel).
Using try I can catch errors and print the errors produced by an R
statement.
Is there a way to know if running a statement caused a warning message?
last.warning gives me the last warning, but I do not have any indication
what
On 10/24/2009 09:00 AM, Lasse Kliemann wrote:
Is there a way to have the distance between label and axis
adjusted automatically? This is interesting in particular for the
y-axis, when it is not known in beforehand how many digits the
numbers will have. It may happen then, that numbers and label
o
On 20.10.2009 09:35 (UTC+2), christiaan pauw wrote:
Hi everybody
I am trying to install RPsSQL and get the following error message:
As far as I know package RPgSQL is outdated. The newer package
RPostgreSQL works with R-2.9.0 and greater. So it seems to be a good
time to update your R version
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