On Sep 23, 2009, at 6:42 PM, Peng Yu wrote:
On Wed, Sep 23, 2009 at 5:16 PM, David Winsemius > wrote:
On Sep 23, 2009, at 5:58 PM, Peng Yu wrote:
Hi,
I have the following matrix, which is printed %e format (in C's
way).
I am wondering how make it be printed in %f format (in C's way)?
?
Hi all,
I have got two datasets, one of them is rainfall data and the other one is
groundwater level data.
I would like to see whether there is a correlation between these two
datasets and if there is, to what extent they are correlated.
My stats background is limited, therefore any advice on w
Webb Sprague gmail.com> writes:
>
> >> xtabs(~wkhp, x, exclude=NULL, na.action=na.pass)
> > wkhp
> > 20 30 40 45 60
> > 1 1 10 1 3 4
now this doesn't even work
> table(wtf, exclude=NULL)
wtf
[0,10) [10,20) [20,30) [30,40) [40,50) [50,60) [60,70)
hi
sorry if this has been discussed before, but I'm wondering why the scaled
Schoenfeld residuals do not follow the defining formula for obtaining them
from the ordinary Schoenfeld residuals, but are instead offset by the
estimated parameter values.
e.g.
library(survival)
attach(ovarian)
sv<-Sur
Hi,
I've been trying to set the directory for choose.files as follows:
[R2.9.0 running on XP]
setwd("C:/Documents and Settings/2/Data")
getwd()
infile2 = choose.files(filters = Filters[c("txt","All"),], caption =
"Choose ECD datafile")
#<...do a bunch of stuff...>
It appears the working dir
Hi,
Is there a way I can plot the median as well as the quantiles in the actual
boxplot using the "boxplot" command?
Thanks
--
View this message in context:
http://www.nabble.com/Box-plot-tp25531261p25531261.html
Sent from the R help mailing list archive at Nabble.com.
___
I have the following code that aligns the two graphs.
Problem is that in .pdf it gives me it x-axis (0-100) is broken down
into 0-20, 20-40..and so on.
I wonder if there is for it to display the x-axis (and y-axis) in more
detail than that.
I'd appreciate your input --
pdf(file="VECTOR & ICA ALIGN
Mitchell Maltenfort gmail.com> writes:
>
> I saw http://cran.r-project.org/doc/FAQ/R-FAQ.html#R-Web-Interfaces
> and I'm still not sure yet which platform (Linux, Windows, etc.) I'll
> be working on -- and no, it's not under my control to pick.
>
> I was wondering if anyone out there had good a
Hi, I have 2 questions:
Question 1:
I define 2 variables: "a", "b":
> a<-rbinom(4,10,0.8)
output:
[1] 9 7 8 8
> b<-rbinom(2,6,0.7)
output:
[1] 4 5
if I write:
> write.table(a, file = "filename", etc. etc. )
it save only the values of variable "a".
There is a way to save in a .txt file
R -helpers
i have been trying to do this problem without must success,i managed to do a
graph for x, but it is not what i want to define. I have also been able to do
simple rendom sample. If possible can someone help here is the code for the
graph pleae help
data.frame(ID=c(1,2,3),mu=c(1
Jean lobry wrote:
I think that it's a good idea, although I have rarely made use
of pch > 20.
This reminds me to pass on a very belated thank-you to the
developer(s) who implemented the formula version for stripchart,
which I had promised to do myself quite a long time ago.
Thanks, folks!
Peter
Typical, spotted a very stupid typo in my code after posting, and when
corrected I have solved my own problem. Sorry for bothering everyone.
Line below should have read:
optimise(f = nbinopt, interval = c(0,100), maximum=FALSE, tol=0.01)
Samuel Dennis wrote:
>
> optimise(f = nbin063, interval =
I would like to know how to determine the best value of a particular
parameter in a generic function.
My function is:
nbin <- function(k,Dt) {
R <- Dt / (k + Dt)
q <- (k + Dt) / k
Pt <- c(0:7)
for (r in c(0:7)) {
Pt[r+1] <- (factorial(k+r-1)/(factorial(r)*factorial(k-1)))*((R^r)/(q^k)) }
Pt }
Th
On Wed, 23 Sep 2009, Jason Rupert wrote:
Using the following: plot(c(1,1), ylim=c(0, 15), xlim=c(0, 13))
This is not what I expected because I would have expected the origin to be (0, 0), but on the plot it
looks a little different on the plot.
The y axis also appears to extend a little be
Chris Li wrote:
>
> Hi all,
>
> I have got two datasets, one of them is rainfall data and the other one is
> groundwater level data.
>
> I would like to see whether there is a correlation between these two
> datasets and if there is, to what extent they are correlated.
>
> My stats backgroun
This is not a complete answer, but try the following in order
plot(c(1,1), ylim=c(0, 15), xlim=c(0, 13), axes = FALSE)
axis(1)
axis(2)
box()
If you want lines, use abline. Hacking something together can be done
with these commands.
On Sep 24, 9:36 am, Jason Rupert wrote:
> Using the following
use the 'colClasses' argument and you can also set 'nrows'.
b
On Sep 23, 2009, at 8:24 PM, Ping-Hsun Hsieh wrote:
Hi,
I am trying to read a tab-delimited file into R (Ver. 2.8). The
machine I am using is 64bit Linux with 16 GB.
The file is basically a matrix(~600x70) and as large as
Using the following: plot(c(1,1), ylim=c(0, 15), xlim=c(0, 13))
However, it produces the following:
http://n2.nabble.com/Simple-Plot-Axis-Limits-Question-td3703091.html
This is not what I expected because I would have expected the origin to be (0,
0), but on the plot it looks a little different
cls59 wrote:
>
>
> data.file <- paste( set.name, sep='' )
>
> assign( set.name, read.dta( file.name ), envir = .GlobalEnv )
>
>
Opps, those lines should have been:
data.file <- paste( set.name, '.dta', sep='' )
assign( set.name, read.dta( data.file ), envir = .GlobalEnv )
Sor
Rakknar wrote:
>
> Hello. I'm trying to run a series of commands in two different datasets.
> For make it efficient I want to make a loop for it. Until now the only
> command for loops i found it's the for() command it's only for series of
> numbers and not a series of strings, witch it's what
Hi,
I am trying to read a tab-delimited file into R (Ver. 2.8). The machine I am
using is 64bit Linux with 16 GB.
The file is basically a matrix(~600x70) and as large as 3GB.
The read.delim() ran extremely slow (hours) even with a subset of the file (31
MB with 6x70)
I monitored
Eiger wrote:
>
> Hi, I have 2 questions:
>
>
> Question 1:
>
> I define 2 variables: "a", "b":
>
>> a<-rbinom(4,10,0.8)
> output:
> [1] 9 7 8 8
>
>> b<-rbinom(2,6,0.7)
> output:
> [1] 4 5
>
> if I write:
>> write.table(a, file = "filename", etc. etc. )
> it save only the values of va
On Wed, Sep 23, 2009 at 5:16 PM, David Winsemius wrote:
>
> On Sep 23, 2009, at 5:58 PM, Peng Yu wrote:
>
>> Hi,
>>
>> I have the following matrix, which is printed %e format (in C's way).
>> I am wondering how make it be printed in %f format (in C's way)?
>
> ??"printf" # scroll down to base pac
if you want to sample integers in [1, 33K] without replacement:
theSample = sample(33000, 18000)
b
On Sep 23, 2009, at 7:29 PM, phoebe kong wrote:
Hi all,
I would like to generate ~18K random number from range 1 to ~33K.
I was thinking to use round(runif(18000,1,33000)), however the some
Hi all,
I would like to generate ~18K random number from range 1 to ~33K.
I was thinking to use round(runif(18000,1,33000)), however the some random
numbers generated are repeated.
Do you know a better way?
thanks,
phoebe
[[alternative HTML version deleted]]
__
On Sep 23, 2009, at 5:58 PM, Peng Yu wrote:
Hi,
I have the following matrix, which is printed %e format (in C's way).
I am wondering how make it be printed in %f format (in C's way)?
??"printf" # scroll down to base package listings, the C function
?sprintf# the s/r function
Regard
Hi,
I have the following matrix, which is printed %e format (in C's way).
I am wondering how make it be printed in %f format (in C's way)?
Regards,
Peng
> significant_analysis_results[,7:8]
pval(ki-wt) pval(ko-wt)
Nab2 1.913348979e-06 2.731944670e-09
Rasal12.482254110e
On Sep 23, 2009, at 3:51 PM, Andy Choens wrote:
Marc Schwartz wrote:
Using the data that is in the online plot rather than the above, here
is a first go. Note that I am not drawing the background grid in the
barplot or the lines for table below it. These could be added if you
really need them.
Note that the variable below has been generated with cut(), if that matters.
On Wed, Sep 23, 2009 at 2:34 PM, ws wrote:
> Webb Sprague gmail.com> writes:
>
>>
>> >> xtabs(~wkhp, x, exclude=NULL, na.action=na.pass)
>> > wkhp
>> > 20 30 40 45 60
>> > 1 1 10 1 3 4
>
> (For
Webb Sprague gmail.com> writes:
>
> >> xtabs(~wkhp, x, exclude=NULL, na.action=na.pass)
> > wkhp
> > 20 30 40 45 60
> > 1 1 10 1 3 4
(Forgive me for the repost, but I just joined the R list, so maybe this will go
through.)
Now the above doesn't work! See :
> table(
R-helpers
I have been learning a little bit of R. I am simulating and i want to draw a
normal curve for all my variables so that i will see the overlaps and reduce
them, after that i want to draw a gragh of all the values that are in the data
frame to see if it follows a normal distribution al
Thanks Greg. I was also thinking about it after I saw my plots.
Cheers../Murli
-Original Message-
From: Greg Snow [mailto:greg.s...@imail.org]
Sent: Wednesday, September 23, 2009 3:49 PM
To: Nair, Murlidharan T; Henrique Dallazuanna
Cc: r-help@r-project.org
Subject: RE: [R] dotchart to
Because Fortan is a complied language, as opposed to R which is an interpreter,
Fortran is orders of magnitude faster than R
Because R is a high level programming language developed for statistical
analyses, for many problems it is much easier, and faster, to program
statistical analyses wtih R
>
> On 23/09/2009, at 11:26 PM, Christian Schulz wrote:
>
> > Hi,
> >
> >
> > nvars <- 902
> > data <- as.data.frame(matrix(runif(100*nvars),ncol=nvars))
> > colnames(data)[901] <- c('phenotype')
> > colnames(data)[902] <- c('outcome')
>
>
>
> Just ***WHAT*** do you think the ``c( )''
Marc Schwartz wrote:
>Using the data that is in the online plot rather than the above, here
>is a first go. Note that I am not drawing the background grid in the
>barplot or the lines for table below it. These could be added if you
>really need them.
Note: I snipped out the syntax from Marc'
I think that it's a good idea, although I have rarely made use
of pch > 20.
This reminds me to pass on a very belated thank-you to the
developer(s) who implemented the formula version for stripchart,
which I had promised to do myself quite a long time ago.
Thanks, folks!
Peter Ehlers
Hi Peter,
I think that it's a good idea, although I have rarely made use
of pch > 20.
This reminds me to pass on a very belated thank-you to the
developer(s) who implemented the formula version for stripchart,
which I had promised to do myself quite a long time ago.
Thanks, folks!
Peter Ehlers
Jean lobry
Well, it was easy to find: ?barplot and look at all the arguments.
But I agree with Greg that this kind of look is (and should be)
pretty much history. I'm not very fond of barplots with as many
groups as you have. Since your variable X appears to be a
discretized continuous variable, why not use
Guess, I miss the argument when I ?barplot.
Cheers../Murli
-Original Message-
From: Peter Ehlers [mailto:ehl...@ucalgary.ca]
Sent: Wednesday, September 23, 2009 3:56 PM
To: Nair, Murlidharan T
Cc: r-help@r-project.org
Subject: Re: [R] dotchart to barplots
Murli,
Two points:
1. I think
On Sep 23, 2009, at 3:47 PM, Jim Silverton wrote:
Hello,
I have the following data:
gene Actualgroupsreps
11213 12
22123 23
33 2 12
44 12 2 3
51 0 1
Thanks Peter. Where did you find that option? It's really cool
Cheers../Murli
-Original Message-
From: Peter Ehlers [mailto:ehl...@ucalgary.ca]
Sent: Wednesday, September 23, 2009 3:56 PM
To: Nair, Murlidharan T
Cc: r-help@r-project.org
Subject: Re: [R] dotchart to barplots
Murli,
Two
On 23/09/2009, at 11:26 PM, Christian Schulz wrote:
Hi,
nvars <- 902
data <- as.data.frame(matrix(runif(100*nvars),ncol=nvars))
colnames(data)[901] <- c('phenotype')
colnames(data)[902] <- c('outcome')
Just ***WHAT*** do you think the ``c( )'' is doing for you in
the construction
Marc Schwartz-3 wrote:
>
> Using the data that is in the online plot rather than the above, here
> is a first go. Note that I am not drawing the background grid in the
> barplot or the lines for table below it. These could be added if you
> really need them.
>
Note: I snipped out the syn
Murli,
Two points:
1. I think you might want las=1;
2. have a look at the density= argument,
i.e. add density=c(10,20,30,40) to your call.
Peter Ehlers
Henrique Dallazuanna wrote:
Perhaps a white border:
barplot(t(as.matrix(intersect.data[,2:5])),
border = 'white',
beside =
The current recommendation is to not put designs/hash lines/pictures/etc. into
the bars, but to use a single solid color (gray in your case). Back when a
quality graph meant using a pen plotter, hash lines made sense as a way to
distinguish between bars, but quality graphics no longer depend on
The journal wants black and white only :)
-Original Message-
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Wednesday, September 23, 2009 3:41 PM
To: Nair, Murlidharan T
Cc: r-help@r-project.org
Subject: Re: [R] dotchart to barplots
Perhaps a white border:
barplot(t(as.matr
Perhaps a white border:
barplot(t(as.matrix(intersect.data[,2:5])),
border = 'white',
beside = T, horiz = T, legend.text = names(intersect.data)[-1],
names.arg = intersect.data[,1], cex.axis = 0.7, cex.names = 0.7, las=2)
Or you can use the 'col' argument to select fur
Hello,
I have the following data:
gene Actualgroupsreps
11213 12
22123 23
33 2 12
44 12 2 3
51 0 1 1
62 34 2 2
73
What I mean by design is a black and white lines or something that is more
distinguishing than the grey levels?
Thanks for the legends :)
Cheers../Murli
-Original Message-
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Wednesday, September 23, 2009 3:32 PM
To: Nair, Murlidh
Sorry, byt what you mean by 'designs'?
You can add a legend with:
barplot(t(as.matrix(intersect.data[,2:5])),
beside = T, horiz = T, legend.text = names(intersect.data)[-1],
names.arg = intersect.data[,1], cex.axis = 0.7, cex.names = 0.7, las=2)
On Wed, Sep 23, 2009 at 4:26 PM
Ok, I could make it perpendicular by specifying las=2
barplot(t(as.matrix(intersect.data[,2:5])),
beside = T, horiz = T,
names.arg = intersect.data[,1], cex.axis = 0.7, cex.names = 0.7,
las=2)
Still working on the other though.
Cheers../Murli
-Original Message-
Fro
I had tried names.arg=c(intersect.data[,1]) so that was the problem. That
solves part of what need. I there a way to rotate how it is written on the
y-axis? Also, use designs instead of gray scale and making keys for it?
Thanks for chipping in.
Cheers../Murli
-Original Message-
From: H
Dear all,
consider:
###
x <- round(rnorm(50))
stripchart(x, pch = 21, col = "black", bg = "pink", method = "jitter")
points(0.5, 1, pch = 21, col = "black", bg = "pink", cex = 2)
###
Under R 2.9.0 the points produced by stripchart are not colored,
while points() gives the desidered output (mag
Dear Group:
I want to get the loglik of the regresion associated to the estimation of the
unit root test Zivot-Andrews of the package urca. I am new using R, then I
simply tried the next sequence:
> A<-ur.za(var,model="intercept",lag=2)
> logLik(A)
but the result is an error, and I thin
Try this:
barplot(t(as.matrix(intersect.data[,2:5])),
beside = T, horiz = T,
names.arg = intersect.data[,1], cex.axis = 0.7, cex.names = 0.7)
On Wed, Sep 23, 2009 at 4:01 PM, Nair, Murlidharan T wrote:
> Hi,
>
> I am trying to plot the following data so that it can be visuall
Hi,
I am trying to plot the following data so that it can be visually represented
well. I tried the dotchart but I felt it was too spread out. Then I tried the
barplot which is good enough for me. Is there a way to give the labels for the
y-axis as in the dot chart? Also, I feel the grey level
Dear Tobias,
To create the etc subdirectory in the installed package, or in the Windows
binary package .zip file, you need an inst/etc subdirectory in the package
source tree. That is, etc should be a subdirectory of inst. This isn't
peculiar to Rcmdr plug-in packages but is true of any package th
On Wed, 23 Sep 2009, Paul Simonin wrote:
Hello R users,
I have a basic "computer programing" question. I am a student currently taking
a course that uses Fortran as the main programming language, but the
instructors are open to students using any language they are familiar with. I
have used R
Are y and s continuous or is one of them a factor/dummy variable? From the
mle specification I grasp that s is the unit of observation and is
factor-coded. If that is so, then estimating lm(o~y+s) includes a lot of
dummy/factor variables (lots of columns of 0/1 in the X matrix), and then
there coul
I saw http://cran.r-project.org/doc/FAQ/R-FAQ.html#R-Web-Interfaces
and I'm still not sure yet which platform (Linux, Windows, etc.) I'll
be working on -- and no, it's not under my control to pick.
I was wondering if anyone out there had good advice, that would save
me time and stomach acid, on ho
Version 3.18 of the survey package is now percolating through CRAN.
Since the last announcement on this list, in February, the main additions are
- standard errors for survival curves (both Kaplan-Meier and Cox model)
- svyciprop() for confidence intervals on proportions, especially in small
Hi Marcus,
I always use a smaller error tolerance in `integrate' than the default
value. I generally use 1.e-07, whereas the default is only about 1.e-04.
Sometimes you may also need to increase the number of subdivisions from its
default value of 100.
Your problem disappears if you use a smalle
Try this:
plot(tp, dp, type = 'l', ylim = rev(range(dp, na.rm = TRUE)))
On Wed, Sep 23, 2009 at 1:44 PM, FMH wrote:
> Thank you for the code. I found that the coding does not work if there is an
> NA in dp variable. For instance;
>
> #
> dp <- c(1,4,NA,2,5,7,9,8,9,2)
> tp <
Dear Rcmdr users,
I use R-2.9.2, Rcmdr 1.5-1 and the latest Rtools bundle (and the html help
workshop) under Windows XP. I wrote a RcmdrPlugin for some important
functions of Thomas Lumley's "survey" package.
Problem: Package compilation works without displaying any errors. That is
1) "R CMD bui
You can try this also:
is.element(2, x)
On Wed, Sep 23, 2009 at 12:37 PM, Dimitri Liakhovitski wrote:
> Dear R'rs,
>
> is there a function that checks if a given vector contains a certain value.
> E.g., x<-c(1,2,3,4).
> How can I get a TRUE or FALSE for whether x contains a 2?
>
> --
> Dimitri L
Hi there
I'm trying to construct a model of mortality risk in 2D space that
requires numerical integration of a hazard function, for which I'm using
the integrate function. I'm occasionally encountering parameter
combinations that cause integrate to terminate with error "Error in
integrate... the i
Thanks Bryan, sorry for the late reply - I only just noticed this
post. I'm not specifically interested in that sum, but something
related to the sum so this may also be very useful.
Dan
On 18 Sep, 18:24, Bryan Keller wrote:
> The combn solution offered by Bill is great. It struck me that what
maybe you could modify the following to suit your situation (i use
this xPath expression to get links from google):
?htmlTreeParse
?getNodeSet
> library(XML)
> link <-
> 'http://www.google.co.uk/search?hl=en&client=firefox-a&rls=org.mozilla:en-GB:official&hs=2XR&ei=mxa6SojjOeaMjAfJkcDuBQ&sa=X&oi
Hi,
I am trying to fit a simple two-way fixed effect linear model (o ~ y + s
- 1). However, my problem is large (length(o)=79333).
I am already using slm.fit with a dense design matrix (ddm), but still:
fit <- slm.fit(ddm,o)
Error: cannot allocate vector of size 9.1 Gb
Is there a way to redef
Try this,
d <- na.omit(data.frame(tp,dp))
plot(d, t="l", ylim=rev(range(d$dp)))
?na.omit
HTH,
baptiste
2009/9/23 FMH :
> Thank you for the code. I found that the coding does not work if there is an
> NA in dp variable. For instance;
>
> #
> dp <- c(1,4,NA,2,5,7,9,8,9,2)
>
Hi,
I am performing a repeated measures 2-way ANOVA to assess the influence of
plant and leaf on aphid fecundity. Fecundity is measured for each aphid on a
single leaf.
Here is what I typed.
wingless <- reshape(Wingless,
varying =
list(c("d0","d1","d2","d3","d4","d5"
and note that if, instead of zip files, you were using gzip files, you
could:
conn <- gzfile("file.gz", "rt")
theData <- read.table(conn)
close(conn)
b
On Sep 22, 2009, at 11:21 PM, Gabor Grothendieck wrote:
Linux is a type of UNIX so follow the instructions I gave for UNIX.
On Tue, Sep 22
Thank you for the code. I found that the coding does not work if there is an NA
in dp variable. For instance;
#
dp <- c(1,4,NA,2,5,7,9,8,9,2)
tp <- 1:10
plot(tp,dp, type= 'l',ylim=rev(range(dp)))
#
If this is the case, how could we rewrite the coding?
Th
Hello R gurus.
I have been performing hierarchical clustering of gene expression data. I use
the heatmap() function to perform the clustering and overlay classifications by
using the ColSideColors parameter.
In many cases I have various metadata associated with my samples, which leaves
me w
Dear R-help and ROCR developers (Tobias Sing and Oliver Sander) -
I think my first question is generic and could apply to many methods,
which is why I'm directing this initially to R-help as well as Tobias and
Oliver.
Question 1. The plot function in ROCR will average your cross validation
dat
For power studies you need to think about what the data will look like under
the alternative hypothesis. Is the data shifted over a certain amount? (the
most common assumption), or scaled? Or both? Or a completely different shape?
Etc.
My preferred method for power studies in this case is to u
WARNING! Biased opinion.
I'm an old guy who learned programming nearly 50 years ago when FORTRAN (IV)
was it, unless you wanted to write machine language which, being an
engineer, I was less interested in than in getting an answer so I could get
on with things.
I like FORTRAN, but I can't think
Thanks a lot, Jorge!
On Wed, Sep 23, 2009 at 11:42 AM, Jorge Ivan Velez
wrote:
> Hi Dimitri,
> See either ?any, ?"%in%", or ?intersect
> any(x == 2)
> # [1] TRUE
>
> HTH,
> Jorge
>
> On Wed, Sep 23, 2009 at 11:37 AM, Dimitri Liakhovitski <> wrote:
>>
>> Dear R'rs,
>>
>> is there a function that
-- Forwarded message --
From: Charlie Sharpsteen
Date: Wed, Sep 23, 2009 at 8:47 AM
Subject: Re: [R] Fortran vs R
To: Paul Simonin
Cc: r-h...@r-project.or
On Wed, Sep 23, 2009 at 8:13 AM, Paul Simonin wrote:
> Hello R users,
> I have a basic "computer programing" question. I
On 9/23/2009 11:13 AM, Paul Simonin wrote:
Hello R users,
I have a basic "computer programing" question. I am a student
currently taking a course that uses Fortran as the main programming
language, but the instructors are open to students using any language
they are familiar with. I have use
Hi Dimitri,
See either ?any, ?"%in%", or ?intersect
any(x == 2)
# [1] TRUE
HTH,
Jorge
On Wed, Sep 23, 2009 at 11:37 AM, Dimitri Liakhovitski <> wrote:
> Dear R'rs,
>
> is there a function that checks if a given vector contains a certain value.
> E.g., x<-c(1,2,3,4).
> How can I get a TRUE or
Hi Sascha,
Take a look at ?pf
HTH,
Jorge
On Wed, Sep 23, 2009 at 11:34 AM, Sascha Wolfer <> wrote:
> Dear List,
>
> is there an easy and fast way to compute the p value from a given F value
> and given degrees of freedom for an effect and the dfs for the residuals? I
> think of a function like
?any
any(x==2)
Stefano
-Messaggio originale-
Da: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]per conto di Dimitri Liakhovitski
Inviato: mercoledì 23 settembre 2009 17.38
A: R-Help List
Oggetto: [R] Function to check if a vector contains a given value?
Dear R'rs,
i
Dear R'rs,
is there a function that checks if a given vector contains a certain value.
E.g., x<-c(1,2,3,4).
How can I get a TRUE or FALSE for whether x contains a 2?
--
Dimitri Liakhovitski
Ninah.com
dimitri.liakhovit...@ninah.com
__
R-help@r-project.
Dear List,
is there an easy and fast way to compute the p value from a given F
value and given degrees of freedom for an effect and the dfs for the
residuals? I think of a function like this:
compute.p(F.value, numerator.dfs, denominator.dfs)
which returns the p value.
Thanks,
Sascha
___
Hello R users,
I have a basic "computer programing" question. I am a student
currently taking a course that uses Fortran as the main programming
language, but the instructors are open to students using any language
they are familiar with. I have used R previously, and am wondering if
there is
Thanks Petr! It is good to see multiple solutions to the same problem.
Best,
Jude
-Original Message-
From: Petr PIKAL [mailto:petr.pi...@precheza.cz]
Sent: Wednesday, September 23, 2009 10:59 AM
To: Ryan, Jude
Cc: alxmil...@yahoo.it; r-help@r-project.org
Subject: Re: [R] compute differe
Hi
You can use outer. If your data are in data frame test then
DIFF <- as.vector(t(outer(test$val, test$val, "-")))
returns a vector, You just need to add suitable names to rows.
CASE <- as.vector(t(outer(test$ID, test$ID, paste, sep="-")))
data.frame(CASE, DIFF)
will put it together.
Regard
Hi
r-help-boun...@r-project.org napsal dne 23.09.2009 14:49:38:
> On Wed, Sep 23, 2009 at 07:29:30AM -0500, Peng Yu wrote:
> > On Wed, Sep 23, 2009 at 1:24 AM, Peter Dalgaard
> > wrote:
> > > Peng Yu wrote:
> >
> > Is there an operation on a factor to get a subset and keep only the
> > correspo
Alessandro Carletti wrote:
Hi,
I have a problem.
I have a data frame looking like:
ID val
A? .3
B? 1.2
C? 3.4
D? 2.2
E? 2.0
I need to CREATE the following TABLE:
CASE?? DIFF
A-A??? 0
A-B??? -0.9
A-C??? -3.1
A-D??? -1.9
A-E??? -1.7
B-A??? ...
B-B??? ...
B-C
B-D
Resolved. Thanks.
On Wed, Sep 23, 2009 at 9:52 AM, Larry White wrote:
> I have the following data exported as a .txt file on Windows. Everything is
> working fine, except that the the data in the 10th column is treated as a
> factor.
>
> Date Week Time Completed Work_Delta Mean_Delta Balance Tot
Dear Helpers,
usually I try to find the answers on my own, but this one beated me.
I have to use the package Geneland which requires coordinates in
Lambert projection.
I have latitude and longitude (please copy to an .txt and read.table() )
X Y
3458231 5544356
3458263 5544301
3459143 5
What it is telling you is that it can't find the file. This could be
because the file isn't there, or you've got a typo in the file name,
that sort of thing.
In your email, you have split the filename argument between two
lines. I don't know whether this comes from what you did in R, or
wheth
--
Tobias Erik Reiners
Justus Liebig University
IFZ - Department of Animal Ecology
Heinrich-Buff-Ring 26-32
D-35392 Giessen Germany
www.uni-giessen.de/cms/fbz/fb08/biologie/tsz/tieroekologie/mitarbeiter/diplomanden-innen/tobias-erik-reiners
-
Dear R gurus,
I use the above release on my MacPro under Leopard 10.5.8 and I have
no more access to the package manager and the CRAN binary list on
package installer. Error messages in the console are :
Erreur : impossible de trouver la fonction
"package.manager" (impossible to find func
I have the following data exported as a .txt file on Windows. Everything is
working fine, except that the the data in the 10th column is treated as a
factor.
Date Week Time Completed Work_Delta Mean_Delta Balance Total Total_Delta
Work Index Open_Bugs Bug_Delta Bug_Delta2
8/17/2009 4 11.8% 64 64 1
Chuck, thank you, but I am not sure I understood what you meant.
There are a lot of rows in "index" where at least 2 columns have equal
values and a lot of rows where column 1 has 2 and some other column
has 5 - same for 3 in column 1 and 6 in some other column, etc.
Thanks a lot for clarifying!
Di
Why are you using "SANN" for optimizing over a smooth function of a scalar
parameter? Simulated annealing is generally quite slow, and is typically
used for "nasty" functions with multiple bumps and valleys.
Try `optimize' instead.
Ravi.
--
Hello Ashta,
You need to use double blackslashes, liike: "C:\\Documents and
Settings\\ashta\\MyDocuments\\R_data\\rel.dat"
I usually use the following to avoid writing the path:
#select file from a popup window
f <- file.choose()
#read the file. the is Rese for any other arguments e.g.
On Sep 23, 2009, at 8:44 AM, David Winsemius wrote:
On Sep 23, 2009, at 4:54 AM, MKHABELA,SN wrote:
Hi everyone
I want help in graduating the attached rates and checking for
goodness of fit and smoothness using R please help.
females.txt>__
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