Hi,
I am new in R and I don´t know how to sum the product of two elements at the
time in a matrix
X=[ 1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16]
I would like to do (1*5+2*6+3*7+4*8)
I need to do it step by step because I will further put a conditional in the
formula
Sorry, I sent it quickly and forgot to thank in advance
Marcio
Marcio Resende wrote:
>
> hello guys, I need to do a BLUP in the simplest model
> y = Xm + Zg + e
> however I have missing data in the analysis which I can´t consider as
> 0(zero). So I need to generate the matrix X'Z, Z'X and Z'Z
If I have a web log file as follows:
#Software: Microsoft Internet Information Services 5.0
#Version: 1.0
#Date: 2007-12-03 13:50:17
#Fields: date time c-ip cs-username s-ip s-port cs-method cs-uri-stem
cs-uri-query sc-status sc-bytes cs-bytes time-taken cs(User-Agent)
cs(Cookie) cs(Referer)
"2007
hello guys, I need to do a BLUP in the simplest model
y = Xm + Zg + e
however I have missing data in the analysis which I can´t consider as
0(zero). So I need to generate the matrix X'Z, Z'X and Z'Z step by step; I
can´t use
crossprod(x) #neither
X'X <- t(x)%*%x
because I should skip the element
Here's the code that does the job for quartiles (0,25,50,75,100). To get to
your objective of (5,10,25,75,90) is left as an exercise. There are several
well-written introductory books in R, in addition to the freely available
presentations and other online resources. I think you should spend some
Peng Yu wrote:
Hi,
Please see the command with a comment below. I don't find
'A630039F22Rik' in y. But 'A630039F22Rik' is in z. Can somebody let me
know what the problem is?
Most obvious guess is that your factor y has a level that is not
present in data. That is perfectly normal, even desir
Something like
for(i in 1:20){
pdf(sprintf("myplot%d.pdf",i))
# your calculation and plots here
dev.off()
}
If you have 100 plots in total, then you should have 5 graphs in each
single pdf.
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609 Web: http://yihui.name
Department of Statistics, Io
I see. What you meant by "human readable" is to separate the lines and
texts in the graph, and that's why you need a so wide graph. Well, I
guess, as Henrik told you, the graph was indeed generated there, but
your viewer was not able to show it.
I also found Adobe Reader cannot display a document
Hi,
Please see the command with a comment below. I don't find
'A630039F22Rik' in y. But 'A630039F22Rik' is in z. Can somebody let me
know what the problem is?
Regards,
Peng
> str(x)
int [1:365494] 6 7 8 14 15 18 19 21 25 29 ...
> str(y)
Factor w/ 29904 levels "0610005C13Rik",..: 17261 28617 15
On Sep 22, 2009, at 9:50 PM, Weiwei Shi wrote:
Hi there,
I am wondering if there is a function in R to save plots
automatically, like
save() for R objects? I have e.g. 100 plots and I cannot put them in
one pdf
file so I split them, eg into 20 files, but I don't want to save one
file
ea
Sunghee Kim gmail.com> writes:
>
> Dear All,
>
> As you know, glmmADMB package use ML method for estimation.
> Is it possible to use REML estimation method for zero-inflated Poisson
> distribution?
>
> For ML method,
> poi_ML <- glmm.admb(los ~ psihigh + trt.mod + trt.high + psihigh*trt.mod +
Linux is a type of UNIX so follow the instructions I gave for UNIX.
On Tue, Sep 22, 2009 at 10:16 PM, Peng Yu wrote:
> No. My machine is a linux machine.
>
> On Tue, Sep 22, 2009 at 9:02 PM, Gabor Grothendieck
> wrote:
>> If you have the 7z zip utility and are on Windows
>> (or use 7z and grep o
No. My machine is a linux machine.
On Tue, Sep 22, 2009 at 9:02 PM, Gabor Grothendieck
wrote:
> If you have the 7z zip utility and are on Windows
> (or use 7z and grep on UNIX):
>
> DF <- read.csv(pipe("7z x myfile.zip -so | findstr $"))
>
>
> On Tue, Sep 22, 2009 at 9:30 PM, Peng Yu wrote:
>> H
If you have the 7z zip utility and are on Windows
(or use 7z and grep on UNIX):
DF <- read.csv(pipe("7z x myfile.zip -so | findstr $"))
On Tue, Sep 22, 2009 at 9:30 PM, Peng Yu wrote:
> Hi,
>
> Suppose that I have a csv file that is compressed with zip, is there a
> way to read it in R without
On Sep 22, 2009, at 9:37 PM, shuva gupta wrote:
Hi,
Is there any R implementation of the well-known algorithm from the
Operations Research
literature, the Ford-Fulkerson algorithm of maximum flow in networks
with capacities.
Thanks.
http://lmgtfy.com/?q=%22Ford-Fulkerson%22+%22r-project%
Hi there,
I am wondering if there is a function in R to save plots automatically, like
save() for R objects? I have e.g. 100 plots and I cannot put them in one pdf
file so I split them, eg into 20 files, but I don't want to save one file
each time. Can I use a function to do such save.plot as pdf?
Hi,
Is there any R implementation of the well-known algorithm from the Operations
Research
literature, the Ford-Fulkerson algorithm of maximum flow in networks with
capacities.
Thanks.
[[alternative HTML version deleted]]
__
R-help@r-
Hi,
Suppose that I have a csv file that is compressed with zip, is there a
way to read it in R without first decompressing it to a file.
Regards,
Peng
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
Yes.. I got it working for dates. I don't want dates though. :) so I figured
out I could just use timeformat %Y.. except that it freaks out when I go
over year . bah...
so... any tips for what way to go for modifying this? I find it hard to
believe that no one before me had this problem.. mayb
On 09/23/2009 09:24 AM, Lars Skjærven wrote:
Great. Thanks for a quick reply. That will work I guess. Although, can I use
float values instead of dates?
so that the "gantt.info" starts and end values are floats instead of dates?
or will I have to work around this ?
Hi Lars,
Try this for time
On 22/09/2009 8:19 PM, Rolf Turner wrote:
On 23/09/2009, at 12:14 PM, Henrique Dallazuanna wrote:
Try this:
treeName <- "PINE"
write.table(d, file = sprintf("C:/%sheight.txt", treeName))
Why not use the (less esoteric) paste() function?
The printf() family of functions are one of the good
On 23/09/2009, at 12:14 PM, Henrique Dallazuanna wrote:
Try this:
treeName <- "PINE"
write.table(d, file = sprintf("C:/%sheight.txt", treeName))
Why not use the (less esoteric) paste() function?
cheers,
Rolf Turner
##
You can use intersect also:
dat.a[intersect(names(dat.a), names(dat.b))]
On Tue, Sep 22, 2009 at 6:58 PM, Corey Sparks wrote:
> Dear R users,
> I am interested in taking the columns from multiple dataframes, the problem
> is that the different dataframes have different combinations of the same
Try this:
treeName <- "PINE"
write.table(d, file = sprintf("C:/%sheight.txt", treeName))
On Tue, Sep 22, 2009 at 5:29 PM, Marcio Resende
wrote:
>
> After I run my script I save all my output e.g.
>
> write.table(d, file = "C:/PINEheight.txt)
> write.table(v, file = "C:/PINEvolume.txt)
> write.ta
Have you looked at ts() ?
On Tue, Sep 22, 2009 at 5:49 PM, Maggie wrote:
> I was wondering how to correlate two time series in R? I have to
> plotted waver files I need to correlate to one another to see how well
> they align..
>
> Any guidance would be very much appreciated!
>
> ___
On 22/09/2009 4:50 PM, Rakknar wrote:
Hello. I'm trying to run a series of commands in two different datasets. For
make it efficient I want to make a loop for it. Until now the only command
for loops i found it's the for() command it's only for series of numbers and
not a series of strings,
W
I was wondering how to correlate two time series in R? I have to
plotted waver files I need to correlate to one another to see how well
they align..
Any guidance would be very much appreciated!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/m
After I run my script I save all my output e.g.
write.table(d, file = "C:/PINEheight.txt)
write.table(v, file = "C:/PINEvolume.txt)
write.table(v, file = "C:/PINEdiameter.txt)
write.table(v, file = "C:/PINEdensity.txt)
and then I would like to run again with another tree and save again e.g
write
Hi Maggie:
1) plot() combined with lines() may do the job.
2) google "R graph gallery"
bests
milton
On Tue, Sep 22, 2009 at 5:23 PM, Maggie wrote:
> Hello, I need to superimpose two graphs (plotted representations of
> waver files) so I can see how much they align. Is there a quick and
> di
Dear All,
I am wondering about the fitting negative binomial(NB) hurdle model with
random effect using REML estimation method in R.
We can fit regular hurdle model without random effect using ML method as
following.
hurdle(pkg)
But, I couldn't figure out how I can fit NB hurdle model with ra
Dear All,
As you know, glmmADMB package use ML method for estimation.
Is it possible to use REML estimation method for zero-inflated Poisson
distribution?
For ML method,
poi_ML <- glmm.admb(los ~ psihigh + trt.mod + trt.high + psihigh*trt.mod +
psihigh*trt.high + 1, random = ~1, group="site", fam
Hello. I'm trying to run a series of commands in two different datasets. For
make it efficient I want to make a loop for it. Until now the only command
for loops i found it's the for() command it's only for series of numbers and
not a series of strings, witch it's what i'm needing. It would be som
Hello, I need to superimpose two graphs (plotted representations of
waver files) so I can see how much they align. Is there a quick and
dirty way to do it in R?
thanks so much for your help!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/ma
Great. Thanks for a quick reply. That will work I guess. Although, can I use
float values instead of dates?
so that the "gantt.info" starts and end values are floats instead of dates?
or will I have to work around this ?
Thanks again,
Lars
On Tue, Sep 22, 2009 at 2:42 PM, David Winsemius wrote:
>
On Tue, Sep 22, 2009 at 5:00 PM, Uwe Ligges
wrote:
>
>
> Peng Yu wrote:
>>
>> Hi,
>>
>> I want to do ANOVA for nested designs like following. I don't
>> understand why the matrix (t(X) %*% X) is singular. Can somebody help
>> me understand it?
>
>
> Yes:
>
> A=1 is never combined with B=4, B=5, or
But of course, it is always possible to emulate a semi-continuous variable
by introducing a binary variable and use some "big-M" trick. That is, with
a new binary variable b we add the following two conditions:
x3 - 3.6 * b >= 0 and
x3 - 10 * b <= 0 # Big-M trick, here M >= 10
On Sep 22, 2009, at 5:58 PM, Corey Sparks wrote:
Dear R users,
I am interested in taking the columns from multiple dataframes, the
problem is that the different dataframes have different combinations
of the same variable names, here's a simple example:
a<-rep(1:10)
b<-rep(1:10)
c<-rep(21:3
Peng Yu wrote:
Hi,
I want to do ANOVA for nested designs like following. I don't
understand why the matrix (t(X) %*% X) is singular. Can somebody help
me understand it?
Yes:
A=1 is never combined with B=4, B=5, or B=6
A=2 is never combined with B=1, B=2, or B=3
hence you cannot estimate y
Dear R users,
I am interested in taking the columns from multiple dataframes, the
problem is that the different dataframes have different combinations
of the same variable names, here's a simple example:
a<-rep(1:10)
b<-rep(1:10)
c<-rep(21:30)
d<-rep(31:40)
dat.a<-data.frame(a,b,c,d)
names(d
On Sep 22, 2009, at 11:35 AM, Alon Ben-Ari wrote:
Hello I am interested in finding out a method of power analysis
(effect
size and sample size calculation ) using R in non parametric methods?
I am running R 2.8.1 running on linux open SUSE
Any libraries or documentation , I was not bale
Dear all,
it seems that my original diagnosis (using impute together with GeneMeta)
was not correct. Something else is causing the crash (R-console stops
working). I will return for questions (probably at the Bioconductor mailing
list) after I have investigated the problem further.
Thank you
I think you might be looking for a Gantt chart:
http://finzi.psych.upenn.edu/R/library/plotrix/html/gantt.chart.html
On Sep 22, 2009, at 5:14 PM, Lars Skjærven wrote:
Dear R users,
I want to make a barplot with bars that can be non-continuous. An
example
will be the presence and absence of s
On Sep 22, 2009, at 5:07 PM, bamsel wrote:
Any help is very much appreciated. The following is a toy example:
#1. Create a data frame with two named columns (x,y):
DF <- data.frame(cbind(x=1:5, y=6:10))
DF
x y
1 1 6
2 2 7
3 3 8
4 4 9
5 5 10
#2. Define a function to compute the sum o
On 09/23/2009 07:14 AM, Lars Skjærven wrote:
Dear R users,
I want to make a barplot with bars that can be non-continuous. An example
will be the presence and absence of some events over time, e.g. a bunch of
people that are either in the office or not in the office, for some period
of time. I wan
On Tue, 22 Sep 2009, Dimitri Liakhovitski wrote:
Hello, dear R'ers,
index<-expand.grid(1:7,1:4,1:4,1:4,1:4,1:4,1:4,1:4,1:4,1:4,1:4)
In this case, dim(index) is 7,340,032 (!) and 11.
I realize it's huge.
Then, I am trying to get rid of the undesired combinations of columns.
They should not con
Cutting and pasting is probably a bad idea with 2000 lines of code.
You might want to save your 2000 lines to a file and then source it.
e.g.
source('myHugeFile.R')
I think (I don't have a GUI version handy) there's a dropdown menu
option for sourcing files in the File menu of the GUI too if you'
Dear R users,
I want to make a barplot with bars that can be non-continuous. An example
will be the presence and absence of some events over time, e.g. a bunch of
people that are either in the office or not in the office, for some period
of time. I want to visualize this in a bar plot like this:
P
Any help is very much appreciated. The following is a toy example:
> #1. Create a data frame with two named columns (x,y):
> DF <- data.frame(cbind(x=1:5, y=6:10))
> DF
x y
1 1 6
2 2 7
3 3 8
4 4 9
5 5 10
> #2. Define a function to compute the sum of a given column:
> foo.fnc = function
I played around a bit with the original 'lp-solve' program --- i.e., not the
R package but the program to be downloaded from Sourceforge ---, at least
version 5.5.0.15 through its IDE. I was not even able to reproduce the
example on semi-continuous variables in the reference documentation at
Thanks, that completely solves the problem.
On Sep 22, 2009, at 10:27 PM, Gabor Grothendieck wrote:
Try parse(text=...):
f <- function(fo, data, groups) {
g <- do.call("xyplot", list(as.formula(fo),
groups = parse(text = groups), data))
print(g)
}
f("yield ~ va
On 17/09/2009, at 3:39 AM, delic wrote:
I wrote a script that I anticipating seeing a spike at 10Hz with the
function 10* sin(2*pi*10*t).
I can't figure out why my plots do not show spikes at the
frequencies I
expect. Am I doing something wrong or is my expectations wrong?
(a) Is this a
Try parse(text=...):
f <- function(fo, data, groups) {
g <- do.call("xyplot", list(as.formula(fo),
groups = parse(text = groups), data))
print(g)
}
f("yield ~ variety | site", data = barley, groups = "year")
On Tue, Sep 22, 2009 at 4:20 PM, Erich Neuwirth
wrote
Thank you, this works for my example.
On Sep 22, 2009, at 9:17 PM, Gabor Grothendieck wrote:
>
> f <- function(fo, data, groups) {
> g <- do.call("xyplot", list(as.formula(fo), groups = as.name
> (groups), data))
> print(g)
> }
But xyplot allows expressions for the groups parameter a
Hello everyone
I have a problem using the R console. I have written 2000 lines in a notepad,
this lines are commands for reading dbf files. When I paste these lines in the
R console I can only visualize the end of the output, this is because the R
console has a default number of rows which is sm
David, Gabor, and Henriuqe,
Thanks a lot for help!
Another (inelegant) way is to use ts() and then supply the start and end
time. this inelegant way works (I guess at least for equally spaced data.) .
-Sean
On Tue, Sep 22, 2009 at 3:19 PM, David Winsemius wrote:
>
> On Sep 22, 2009, at 3:03 PM
On Sep 22, 2009, at 3:03 PM, Sean Zhang wrote:
Dear R helpers.
I am new to plotting time data using R.
wonder how to convert character time info into date in R.
I searched over the web but did not find answer.
the input character string is something like 03_1993 or 03-1993, so
the
precisio
Try this:
> library(zoo) # as.yearmon
>
> as.yearmon("03_1993", "%m_%Y")
[1] "Mar 1993"
> as.Date(as.yearmon("03_1993", "%m_%Y"))
[1] "1993-03-01"
On Tue, Sep 22, 2009 at 3:03 PM, Sean Zhang wrote:
> Dear R helpers.
>
> I am new to plotting time data using R.
> wonder how to convert character ti
Try this:
f <- function(fo, data, groups) {
g <- do.call("xyplot", list(as.formula(fo), groups = as.name(groups),
data))
print(g)
}
f("yield ~ variety | site", data = barley, groups = "year")
On Tue, Sep 22, 2009 at 3:03 PM, Erich Neuwirth
wrote:
> I need to play games with a
Try this:
strptime(paste(1, c("03_1993")),"%d %m_%Y")
strptime(paste(1, c("03-1993")),"%d %m_%Y")
On Tue, Sep 22, 2009 at 4:03 PM, Sean Zhang wrote:
> Dear R helpers.
>
> I am new to plotting time data using R.
> wonder how to convert character time info into date in R.
> I searched over the web
You *have to* report sessionInfo() when you ask for this kind of help.
It might be that the PNG is actually generated, but it is the viewer
that cannot display it. You can check with other viewers or editors.
You can also try to downscale using ImageMagick, e.g.
convert -geometry 10% large.png
Dear R helpers.
I am new to plotting time data using R.
wonder how to convert character time info into date in R.
I searched over the web but did not find answer.
the input character string is something like 03_1993 or 03-1993, so the
precision is at month level. I tried the following but failed
I need to play games with an expression similar to the following one:
print(xyplot(DepVar ~ Group|Covar, groups=Othergroup,
data=mydf, pch = 18 ,main="Testcase",auto.key = TRUE))
The problem is that the formula argument (the first argument)
an the groups argument are passed over from a
Try e.g. function recode from package car.
2009/9/22 Chris Hane :
> Hello R-users,
> I have a data frame with a factor of ages in 5 year increments, and various
> count data for each age group. I only have this summary information in R at
> the moment.
>
> I want to create a new factor that aggreg
Try asking bioconductor list
http://www.bioconductor.org/docs/postingGuide.html
-Johannes
2009/9/22 Rainer Tischler :
> Dear all,
>
> I have received a microarray data set in standard Affymetrix CEL-format
> consisting of only six samples without any replicates (same organism and
> cell type,
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of YUPU LIANG
> Sent: Tuesday, September 22, 2009 11:24 AM
> To: r-help@r-project.org
> Subject: [R] how to force R to evaluate variable?
>
> Hi,
>
> I want to construct a list as
Henrique Dallazuanna wrote:
Try this:
as.list(c(object_1, object_2))
On Tue, Sep 22, 2009 at 3:23 PM, YUPU LIANG wrote:
Hi,
I want to construct a list as
Lst <- list(name_1=object_1, ..., name_m=object_m)
If name_1 is a variable with value "NAME1", how can I ask R to use
"NAME1" instead
On 9/22/2009 2:23 PM, YUPU LIANG wrote:
Hi,
I want to construct a list as
Lst <- list(name_1=object_1, ..., name_m=object_m)
If name_1 is a variable with value "NAME1", how can I ask R to use
"NAME1" instead of 'name_1' as the name of the list element?
Lst <- list(object_1, ..., object_m)
Try this:
as.list(c(object_1, object_2))
On Tue, Sep 22, 2009 at 3:23 PM, YUPU LIANG wrote:
> Hi,
>
> I want to construct a list as
>
> Lst <- list(name_1=object_1, ..., name_m=object_m)
>
> If name_1 is a variable with value "NAME1", how can I ask R to use
> "NAME1" instead of 'name_1' as the n
Hi,
I want to construct a list as
Lst <- list(name_1=object_1, ..., name_m=object_m)
If name_1 is a variable with value "NAME1", how can I ask R to use
"NAME1" instead of 'name_1' as the name of the list element?
Thanks!
Yupu
[[alternative HTML version deleted]]
_
Hello, dear R'ers,
index<-expand.grid(1:7,1:4,1:4,1:4,1:4,1:4,1:4,1:4,1:4,1:4,1:4)
In this case, dim(index) is 7,340,032 (!) and 11.
I realize it's huge.
Then, I am trying to get rid of the undesired combinations of columns.
They should not contain identical values in any 2 columns.
Also if colu
Well, if you don't care about its width, I'd suggest you use the pdf()
device instead, e.g.
# 200 inches!
pdf("hugeplot.pdf", width = 200, height = 200)
par(mar = rep(0, 4))
plot(rnorm(1), pch = 19)
dev.off()
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609 Web: http://yihui.name
Department o
On Sep 22, 2009, at 1:20 PM, FMH wrote:
Dear All,
Let ab is the combination of matrices a and b.
a <- matrix(c(1,2,3,4), nrow = 2, ncol = 2)
b <- matrix(c(4,3,1,2), nrow = 2, ncol = 2)
ab <- rbind(a, b)
From matrix ab, could someone give some advice on the way to sort
all elements in colu
blahbleh wrote:
Is there a good tutorial or just sample code on how to plot .wav files in R?
I would really appreciate it!
See for example packages tuneR or seewave
Best wishes,
Uwe Ligges
__
R-help@r-project.org mailing list
https://stat.ethz.
Tammy
Try avoid directories with spaces... may be this solve your problem.
Case not, write us again.
bests
milton
On Mon, Sep 21, 2009 at 10:05 AM, Tammy Ma wrote:
>
>
> HI, All R users,
>
> My problem is:
>
> > fn
> [1] "C:/Documents and
> Settings/lma/Desktop/FamilyAEntrepreneurs/Entrepreneu
that helps, thanks. I can put a final line in my batch file that opens a viewer
for the png graph.
I was hoping to find a way to do make it run in the Rgui (picky, I know.) My
graph is clearer in the default graph device that pops up in the Rgui; it's
blurry in the Windows viewer for png files
ab[order(ab[,1]),]
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von FMH
Gesendet: Tuesday, September 22, 2009 1:20 PM
An: r-help@r-project.org
B
Hi,
On Sep 22, 2009, at 1:20 PM, FMH wrote:
Dear All,
Let ab is the combination of matrices a and b.
a <- matrix(c(1,2,3,4), nrow = 2, ncol = 2)
b <- matrix(c(4,3,1,2), nrow = 2, ncol = 2)
ab <- rbind(a, b)
From matrix ab, could someone give some advice on the way to sort
all elements in
Dear All,
Let ab is the combination of matrices a and b.
a <- matrix(c(1,2,3,4), nrow = 2, ncol = 2)
b <- matrix(c(4,3,1,2), nrow = 2, ncol = 2)
ab <- rbind(a, b)
>From matrix ab, could someone give some advice on the way to sort all elements
>in column 2, by the sequence of the elements in c
BATCH is not an R object, and it is not for use in R console. As
Henrik mentioned, you should use it in the command line. Open a
terminal window/command window (depending on your OS), and type "R CMD
BATCH ..." there. If you are using Windows, cd to the 'bin' directory
of R first (or put the 'bin'
Given the DPI=72, do you really need a graph that's wider than 450
inches? Or can you really read a picture that is so wide?
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609 Web: http://yihui.name
Department of Statistics, Iowa State University
3211 Snedecor Hall, Ames, IA
On Tue, Sep 22, 2009
I did not test to see if the design of the data.frame you offered was
valid input to your model, since you did not provide a means to test
it within R. I only meant to say that creating a very long vector with
identical entries should not be necessary if the newdata argument were
constructe
rbind(a, b, c)
another function you might be interested in is cbind.
cheers,
On Tue, Sep 22, 2009 at 9:40 AM, FMH wrote:
> Dear All,
>
> Let a, b and c are three matrices with same no. of column but different no.
> of row.
>
> a <- matrix(1, 1, 2)
> b <- matrix(2, 2, 2)
> c <- matrix(3, 3, 2)
See copyDirectory() in the R.utils package. /hb
On Tue, Sep 22, 2009 at 9:43 AM, Yihui Xie wrote:
> You assigned values to 'fn' and 'dpath' outside the function body and
> use these names as the arguments of your function, so actually 'cyfun'
> does not know what 'fn' and 'path' are. The solution
abc <- rbind(a, b, c)
On Tue, Sep 22, 2009 at 1:40 PM, FMH wrote:
> Dear All,
>
> Let a, b and c are three matrices with same no. of column but different no.
> of row.
>
> a <- matrix(1, 1, 2)
> b <- matrix(2, 2, 2)
> c <- matrix(3, 3, 2)
>
> Could someone help me to combine these matrices toget
is rbind(a,b,c) what you mean?
Daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von FMH
Gesendet: Tuesday, September 22, 2009 12:40 PM
An: r-h
You assigned values to 'fn' and 'dpath' outside the function body and
use these names as the arguments of your function, so actually 'cyfun'
does not know what 'fn' and 'path' are. The solution is to put them in
the arguments as default values:
cyfun <- function(fn = "C:/Documents and
Settings/lma
Dear All,
Let a, b and c are three matrices with same no. of column but different no. of
row.
a <- matrix(1, 1, 2)
b <- matrix(2, 2, 2)
c <- matrix(3, 3, 2)
Could someone help me to combine these matrices together as a single matrix?
Thank you
Fir
__
Try this:
plot(x, y, xlab=expression(x=sqrt(x[0], 4)),ylab=expression(y=sqrt(x[0], 4)))
On Tue, Sep 22, 2009 at 1:07 PM, amor Gandhi wrote:
> Hi all,
>
> I would like to write the following latex code in a plot x=\sqrt[4]{x[0]}
> using
>
> x0 <- rgamma(1000,2,1)
> y0 <- rgamma(100,2,1)
> x <- x
Hi folks,
I am trying to do a clustering and generate a long dendrogram in R on Linux
server:
=
data<-read.table(file="mean_ratio.txt.noheader",row.names=1,sep="\t",quote="\"")
hc<-hclust(dist(data),"ward")
png(file="mean_ratio.txt.noheader.ward.png",bg="white",pointsize=8,width=32767,hei
Dear R users,
Could you help my with the following problem?
I want to repeat a glm analysis with 2 independent variables for all 900
variables (snps) in my data set. So, I want to check whether snp1 has a
different effect on my outcome variable in patients and
controls(phenotype). And repeat that
If I use the following
newdata=data.frame(chemo1=0,
horm1=0,
age1=mean(age1),
grade1=0,
positive1=1,
size1=mean(size1) )
then I get
Error in model.frame.default(Terms, newdata, ...) :
variable lengths differ (found for 'log(tstop + 1)')
In addition: Warning message:
'newdata' had 1 rows b
You probably want to use the source() command in R.
R CMD BATCH is used from the command line - it's rare that people use
it (unless they really know what they are doing).
/Henrik
On Tue, Sep 22, 2009 at 9:01 AM, Manuj Sharma wrote:
> I tried to use BATCH command to run an input file (a simple
Hello R-users,
I have a data frame with a factor of ages in 5 year increments, and various
count data for each age group. I only have this summary information in R at
the moment.
I want to create a new factor that aggregates the age factors if the
existing factors have insufficient counts. Then I
On 9/22/2009 11:04 AM, p...@orbit.umbr.cas.cz wrote:
Hi,
Is is possible to obtain/ get coordinates of the current graphics? I am using
plot function for hclust object and I want to add some additional graphics
but I cannot figure out what ylim and xlim is used for actual ploting of
tree. I know
Hi,
Is is possible to obtain/ get coordinates of the current graphics? I am using
plot function for hclust object and I want to add some additional graphics
but I cannot figure out what ylim and xlim is used for actual ploting of
tree. I know that I can probably used ploting of dendrogram instead
Hi,
I´m using the tkmessageBox widget of package tcltk. I would like to change the
font size of the message. How can I do it?
Thanks in advance,
Srpd
Partilhe as suas memórias com quem quer que deseja. Com quem quer que deseja.
___
Hi all,
I would like to write the following latex code in a plot x=\sqrt[4]{x[0]} using
x0 <- rgamma(1000,2,1)
y0 <- rgamma(100,2,1)
x <- x0^0.25
y <- y0^0.25
plot(x, y,xlab=expression(x=sqrt[4]{x[0]}),ylab=expression(y=sqrt[4]{y[0]}))
Many thanks,
Amor
[[alternative HTML vers
I am not sure if this is the solution you want, but complete.cases
will remove rows that contain any NA values at all from a matrix.
These lines get rid of NA values in my little function:
predmat1 <<- as.matrix(predmat[complete.cases(predmat,respmat),])
respmat1 <<- as.matrix(re
I tried to use BATCH command to run an input file (a simple text file) which
contained a few R commands.
I first saw the BATCH help page using
> ?BATCH
The help page mentioned the Usage as:
Batch Execution of RR CMD BATCH [options] infile [outfile]
The Detailed section mentioned the follow
Try this one line R script:
print(sub(".*=", "", commandArgs()[4]))
Also see the geopt package for fancier handling of arguments.
On Tue, Sep 22, 2009 at 11:47 AM, Peng Yu wrote:
> Hi,
>
> Right now, I hardcode the file name in the script. But when I change
> the script name, I have to change t
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