On Fri, Sep 18, 2009 at 8:12 AM, Schalk Heunis
wrote:
> Marcio
> Looking at the script (not much explanation re your intention), I think
> there is a couple of problems:
> 1. Not sure if the attached was supposed to be working code, but the
> assignment operator is <- not <=
> 2. The functions sho
On Sep 18, 2009, at 1:03 AM, premmad wrote:
I'm relatively new to R .I tried converting the datetime column with
values
like 01apr1985:00:00:00.000 using strptime(datetime,"%d%b%Y).Could
anyone
help me in this regard .Please reply ASAP i need .
You will need to give us a more complete s
Marcio
Looking at the script (not much explanation re your intention), I think
there is a couple of problems:
1. Not sure if the attached was supposed to be working code, but the
assignment operator is <- not <=
2. The functions should be defined OUTSIDE the loop, otherwise you are
redefining the f
Hi R users,
I have a script composing of more than 1000 lines and would like suppress
the R codes from the console when executing the script (to reduce the
physical processing time)
I have tried options(echo=T) but no luck..
*Q1. Are there any way of suppressing the commands in the R console?*
That doesn't change the fact that the maximum is still 10.
On Thu, Sep 17, 2009 at 11:40 PM, pragathichi wrote:
>
> Sorry i made a mistake in the example my Quadradic constraint is
> X3^2-3.6 * X3 >= 0
>
> Gabor Grothendieck wrote:
>>
>> The 2nd constraint holds trivially and the 1st constraint i
Is there a way to have R return the line number in a script when it errors out?
I call my script like:
$ R --vanilla < script.R > output.txt
I seem to remember a long discussion about this at some point, but I can't
remember the outcome.
Tx
__
R-
Thank you for your reply! Yes, I am using the svm and I do not have new data
(how do you create new data?), all I have these 12 samples which I want to
classify (predict) these into two group so that I do have six sample in each
group?
Many thanks,
Samuel
--- On Thu, 9/17/09, Steve Lianoglou
I'm relatively new to R .I tried converting the datetime column with values
like 01apr1985:00:00:00.000 using strptime(datetime,"%d%b%Y).Could anyone
help me in this regard .Please reply ASAP i need .
--
View this message in context:
http://www.nabble.com/Datetime-conversion-tp25503138p25503138
I am new in R and i am having trouble here. I´ve already searched in the list
but hasn´t helped
When i run this script above i get the message "Error in gen[j, i] :
incorrect number of dimensions". However gen is 1000x200 (ind x loc) and so
is g
could anybody help me
for (i in 1 : loc) { #l
Sorry i made a mistake in the example my Quadradic constraint is
X3^2-3.6 * X3 >= 0
Gabor Grothendieck wrote:
>
> The 2nd constraint holds trivially and the 1st constraint implies that the
> maximum is 10. The solution is not unique and any values of the
> variables satisfying the 1st constrai
Hi listers,
First I programmed the calcul of a empirical distribution function given by:
F_hat(y)=(1/n)*Sum[Ind(yi<=y)]
I checked the ecdf function and I found out how does it works...
A modification of the function would be:
n<-6
x<-c(10,12,7,7,5,4)
vals<-unique(x)
edf<-cumsum(tabulate(match(x,
Hi Jarno
You've only told us half the story. You didn't show how you
i) performed the original query
ii) retrieved the URL you used in subsequent queries
But I can suggest two possible problems.
a) specifying the cookiejar option tells libcurl where to write the
cookies that the particular
This describes the way in which categorical variables are coded in
the model. In this case, we see "treatment" coding,
although this can go by different names in textbooks (for example, reference
cell coding).
attr(,"assign")
[1] 0 1 2 2
means that the first column of the model matrix corresponds
Ivan,
On 17 September 2009 at 21:22, Ivan Adzhubey wrote:
| Attempt to install R 2.9.2 on Ubuntu 9.04 results in errors:
|
| $ sudo apt-get install r-base
| Reading package lists... Done
| Building dependency tree
| Reading state information... Done
| Some packages could not be installed. This m
Hi,
Attempt to install R 2.9.2 on Ubuntu 9.04 results in errors:
$ sudo apt-get install r-base
Reading package lists... Done
Building dependency tree
Reading state information... Done
Some packages could not be installed. This may mean that you have
requested an impossible situation or if you are
Dear All,
I am running an ANOVA model with three factors: FEATURE (3 levels),
GROUP (5 levels), and PATIENT (2 levels), where PATIENT is nested
within GROUP.
fit <- lm(ABUNDANCE ~ FEATURE + GROUP + FEATURE:GROUP + GROUP/PATIENT,
example)
However, the design is not balanced: PATIENT1 in
Using strapply() from the gsubfn package, apply the
pattern (2nd arg) to string (1st arg). The matches
to the back references (i.e. the portions of the pattern
in parens) are passed to separate arguments of the
These arguments are date, offset and year respectively.
Then the function
calculates t
read Support Vector Machines in R http://www.jstatsoft.org/v15/i09/paper
On Thu, Sep 17, 2009 at 4:39 AM, Samuel Okoye wrote:
> Hello,
>
> I have 12 sample each sample has got 1000 observation, i.e I have a matrix X
> with 1000 rows and 12 columns!
>
> m <- svm(t(X))
> p <- predict (m)
>
> Can a
There is a 1-1 correspondance between your n-sets
consisting of m possible element types (0 through m-1
in your example) and the number of n-subsets of a (n+m-1)-set.
E.g., your example had m=3 and n=3 and subtracting
1:3 from each column of combn(3+3-1,3) gives your result:
> t(combn(3+3-1, 3)-(
Dear Dan,
On Thu, Sep 17, 2009 at 5:31 PM, Erik Iverson wrote:
> Dan,
>
> Still maybe a bit ugly, but no looping...
>
>> unique(as.data.frame(t(apply(expand.grid(0:2, 0:2, 0:2), 1, sort
The prob package provides a convenience wrapper for (essentially)
Erik's solution:
library(prob)
urnsamp
Thanks a lot for your great suggestions!
Dimitri
On Thu, Sep 17, 2009 at 5:48 PM, David Winsemius wrote:
>
> On Sep 17, 2009, at 5:17 PM, Dimitri Liakhovitski wrote:
>
>> Hello, dear R-ers!
>>
>> I have a data frame:
>>
>> x<-data.frame(a=c(4,2,4,1,3,4),b=c(1,3,4,1,5,0),c=c(NA,2,5,3,4,NA),d=rep(N
On Sep 17, 2009, at 1:39 PM, Topi, Corrado wrote:
Dear R list,
is it possible to define a new family (and a new link function) for
gam in gam package? How?
I read the help for gam, family, gam.model, make.link but I did not
find a solution.
Wood provides an example for negbin with alte
On Sep 17, 2009, at 5:17 PM, Dimitri Liakhovitski wrote:
Hello, dear R-ers!
I have a data frame:
x<-data.frame(a=c(4,2,4,1,3,4),b=c(1,3,4,1,5,0),c=c(NA,
2,5,3,4,NA),d=rep(NA,6),e=rep(NA,6))
x
When x$a==1, I would like to replace NAs in columns d and e with 8 and
9, respectively
When x$a !=
Hi,
On Sep 17, 2009, at 5:34 PM, Samuel Okoye wrote:
Thank you for your reply! Yes, I am using the svm and I do not have
new data (how do you create new data?), all I have these 12 samples
which I want to classify (predict) these into two group so that I do
have six sample in each group?
Try this
x[(row(x[1]) %in% 2:5) & x$a==1,4:5] <- c(8,9)
x[(row(x[1]) %in% 2:5) & x$a!=1,4:5] <- c(101,102)
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 11:17 PM, Dimitri Liakhovitski wrote:
> Hello, dear R-ers!
>
> I have a data frame:
>
> x<-data.frame(a=c(4,2,4,1,3,4),b=c(1,3,4,1,5,0),c=c(NA,2,
Dan,
Still maybe a bit ugly, but no looping...
> unique(as.data.frame(t(apply(expand.grid(0:2, 0:2, 0:2), 1, sort
V1 V2 V3
1 0 0 0
2 0 0 1
3 0 0 2
5 0 1 1
6 0 1 2
9 0 2 2
14 1 1 1
15 1 1 2
18 1 2 2
27 2 2 2
Best,
Erik
> -Original Message-
> F
Hello, dear R-ers!
I have a data frame:
x<-data.frame(a=c(4,2,4,1,3,4),b=c(1,3,4,1,5,0),c=c(NA,2,5,3,4,NA),d=rep(NA,6),e=rep(NA,6))
x
When x$a==1, I would like to replace NAs in columns d and e with 8 and
9, respectively
When x$a != 1, I would like to replace NAs in columns d and e 101 and
1022,
On Sep 17, 2009, at 11:13 AM, Peng Yu wrote:
Hi,
I don't understand what the meaning of the following lines returned by
model.matrix(). Can somebody help me understand it? What can they be
used for?
attr(,"assign")
[1] 0 1 2 2
attr(,"contrasts")
attr(,"contrasts")$A
[1] "contr.treatment"
att
Hi,
I am trying to generate all unordered combinations of a set of
numbers / characters, and I can only find a (very) clumsy way of doing
this using expand.grid. For example, all unordered combinations of
the numbers 0, 1, 2 are:
0, 0, 0
0, 0, 1
0, 0, 2
0, 1, 1
0, 1, 2
0, 2, 2
1, 1, 1
1, 1, 2
1,
On Sep 17, 2009, at 3:23 PM, Peng Yu wrote:
Hi,
The first line has less elements than the rest of
'rownames_colnames.write.table.xls'. I am wondering if there is a way
to print an additional '\t' at the beginning of the first line.
$ Rscript write.table.R
x=matrix(1:20,nc=2)
rownames(x)=lett
Marcio Resende wrote:
>
> Good Mourning,
> I have a function to generate a matrix as I show part of it;
>
> g[j,i]<-if (gen[j,i]==0) al1[i,1]+al1[i,1] else ...
>
> However i would like that this function occurred with a probability P and
> that another function (another formula to generate g
Hi,
The first line has less elements than the rest of
'rownames_colnames.write.table.xls'. I am wondering if there is a way
to print an additional '\t' at the beginning of the first line.
$ Rscript write.table.R
> x=matrix(1:20,nc=2)
> rownames(x)=letters[1:10]
> colnames(x)=letters[1:2]
> write.
Steve Jaffe wrote:
>
> Sorry if this is somewhere in the fine manuals but I've been unable to
> locate it.
>
> Does dyn.load use a search path or does it just look in the current
> directory for non-fully-qualified filenames? If there is a search path,
> what is it?
>
> Thanks for your help
>
On Sep 17, 2009, at 2:06 PM, (Ted Harding) wrote:
On 17-Sep-09 17:28:16, Noah Silverman wrote:
Hi,
I'm not sure of the correct nomenclature or function for what
I'm trying to do.
I'm interested in calculated a logistic regression on a binary
dependent variable (True,False).
There are a few w
Ted,
Thanks for the reply.
For the example, I'm not looking to predict "THE winner", but to find
the best probabilities of winning.
It would seem that the process of iterating through possible
coefficients would be the same as a standard GLM, the "evalation" part
as you work through them wo
On Sep 17, 2009, at 11:25 AM, esawdust wrote:
I've been trying to understand the as.Date functionality and I have
a date
and time stamp field that looks like this:
"Tue Sep 15 09:22:09 -0600 2009"
and I need to turn it into an R Date object for analysis.
Simple date conversions I have do
Sorry if this is somewhere in the fine manuals but I've been unable to locate
it.
Does dyn.load use a search path or does it just look in the current
directory for non-fully-qualified filenames? If there is a search path, what
is it?
Thanks for your help
--
View this message in context:
http:/
On 17-Sep-09 17:28:16, Noah Silverman wrote:
> Hi,
> I'm not sure of the correct nomenclature or function for what
> I'm trying to do.
>
> I'm interested in calculated a logistic regression on a binary
> dependent variable (True,False).
>
> There are a few ways to easily do this in R. Both SVM an
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
If you are really serious about your variables being ordinal, you
should analyze them using polychoric correlations. See polycor package
by John Fox.
On Thu, Sep 17, 2009 at 10:52 AM, Mark Difford wrote:
>>> I have used the dudi.mix method from the ade4 package, but when I do the
>>> $index it sh
On 9/17/2009 9:16 AM, Uwe Ligges wrote:
_ wrote:
Hi all,
I installed the library inline to my default R-enviroment
(c:\Programme\R.. )
downloaded and installed RTools from
http://www.murdoch-sutherland.com/Rtools/
to c:\Rtools.
Path variable is set right (with respect to order) but I get sti
Dear R list,
is it possible to define a new family (and a new link function) for gam
in gam package? How?
I read the help for gam, family, gam.model, make.link but I did not find
a solution.
Regards
--
Corrado Topi
Area 18,Department of Biology
University of York, York, YO10 5YW, UK
Phone:
Hi Thierry,
I tried the code suggested below, but it didn't work fully. The ribbon
showed up correctly for first and last days, but the days in between
appeared to be ignored. I tried other ways of feeding geom_ribbon the
summary stats but my ways didn't work either.
Thanks for trying to help
Can I run a lack-of-fit test using R? How do I do that?
Thank you
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org
Hi,
I'm not sure of the correct nomenclature or function for what I'm trying
to do.
I'm interested in calculated a logistic regression on a binary dependent
variable (True,False).
There are a few ways to easily do this in R. Both SVM and GLM work easily.
The part that I want to add is "gr
That's a reasonable request that I have
planned for whenever I revise it.
However, I'm not going to be doing that
for some time yet (unit of time is somewhere
in the months to years range).
If someone is keen to do that, I can make
the LyX file available to them.
Patrick Burns
patr...@burns-st
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Thomas Lumley
> Sent: Thursday, September 17, 2009 6:59 AM
> To: William Revelle
> Cc: r-h...@stat.math.ethz.ch
> Subject: Re: [R] Fastest Way to Divide Elements of Row With Its R
On Thu, Sep 17, 2009 at 9:11 AM, Subodh Acharya wrote:
> Hi everyone,I have a data daily data (x) for 10 years starting from
> 04-01-1995 to 03-31-2005.
> I was able to get the yearly sum for the ten years using
> aggregate(x, years, sum).
> But this gave me the yearly sum for 1995 (Apr- Dec); 199
Try either of these which convert to year and qtr and then
shift the qtr by one. The resulting series is labeled by
the year in which the series dates start. Use
as.integer(...) + 1 if you prefer to label by ending year.
library(zoo)
# test data
DF <- data.frame(date = Sys.Date() + 1:1000, value
Graham Etherington wrote:
>
> Hi,
> Using Ape, I have constructed an object of class "phylo", using the
> method 'nj' (lets call the object 'tree_ja').
> I also have a given subset of 'tree_ja' in a vector (lets call the
> vector 'subspecies').
> What I want to do, is construct a nj tree - pl
RS27 wrote:
>
> Hi,
> I am trying to add multiple variance structures such as the first example
> below:
>
> vf1 <- varComb(varIdent(form = ~1|Sex), varPower())
>
> However my code below will not work can anybody please advise me?
>
> VFcomb<-varComb(varExp(form=~depcptwithextybf),varFixed(f
Hey, check this link: http://www.burns-stat.com/pages/Tutor/R_inferno.pdf
Greetings
Víctor
De: r-help-boun...@r-project.org en nombre de Peng Yu
Enviado el: jue 17/09/2009 10:43
Para: r-h...@stat.math.ethz.ch
Asunto: [R] r-inferno.pdf with detailed table of c
Subodh
Assuming the data is ordered by date then you can define
fin.years = (0:(10*12-1)) %/% 12
then use aggregate:
aggregate(x, list(fin.years),sum)
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 6:11 PM, Subodh Acharya wrote:
> Hi everyone,I have a data daily data (x) for 10 years starting from
I wrote a post on the Revolutions blog a little while back discussing
the difference between the two (and the history of the <- operator).
You can find it on blog.revolution-computing.com at:
http://bit.ly/3YWw3R
# David Smith
On Wed, Sep 16, 2009 at 7:58 PM, Peng Yu wrote:
> Hi,
>
> I was told
Hi everyone,I have a data daily data (x) for 10 years starting from
04-01-1995 to 03-31-2005.
I was able to get the yearly sum for the ten years using
aggregate(x, years, sum).
But this gave me the yearly sum for 1995 (Apr- Dec); 1996 (Jan-Dec)
-2005 (Jan-Mar).
But I want to get the aggrega
Hi
r-help-boun...@r-project.org napsal dne 17.09.2009 04:14:24:
> Hi,
>
> I want to construct a data.frame 'y' by using x$x and x$y. I think
> that there might be better ways to do it (because, for example, we can
> use a_matrix[3:5,] to extract certain rows, where 'a_matrix' is a
> matrix). Can
Gábor Csárdi wrote:
> Dear All,
>
> maybe this is something obvious, I seem to be incapable of
> understanding how S4 works.
>
> So, in package 'A' I defined a "summary" method for my class:
>
> setMethod("summary", signature(object="ListHyperGResult"),
> function(object, pvalue=pvalue
Hi,
I am trying to add multiple variance structures such as the first example
below:
vf1 <- varComb(varIdent(form = ~1|Sex), varPower())
However my code below will not work can anybody please advise me?
VFcomb<-varComb(varExp(form=~depcptwithextybf),varFixed(form=~FebNAO))
also if you have two
Hi
I do not know rma but from help page boxplot requires as input a formula,
list (only some list of numerics), data frame or numeric vector. I am not
sure if your object is one of these. If not you need to convert it to
object which is acceptable for boxplot.
Regards
Petr
r-help-boun...@r-p
P. Branco wrote:
>> I have used the dudi.mix method from the ade4 package, but when I do the
>> $index it shows
>> me that R has considered my variables as quantitative.
>> What should I do?
You should make sure that they are encoded as ordered factors, which has
nothing to do with ade4's dud
Hello!
I am trying with this question again:
I would like to test few distributional assumptions for some behavioral
response data. There are few theories about true distribution of those
data, like: normal, lognormal, gamma, ex-Gaussian
(exponential-Gaussian), Wald (inverse Gaussian) etc. The
Assuming storage is not a problem, first generate two matrices, one by each
method, call these A and B. Then if dim(A) = dim(B) = c(m,n) and k = m*n
z <- rbinom(k,1, .7)
result <- A*z + B*(1-z)
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-p
Dear R users,
I would like to optimize a linear approximation of a quadratic function
using lpSolve. My code runs without any error or warning message but the
constraints that I set don't seem to work properly.
Nevertheless, I am certain that my code is somewhere wrong.
I would like to solve th
Marcio
Define two functions, e.g.
f1<-function(i,j) i+j
f2<-function(i,j) i-j
then call them based on the probability e.g. 0.7
f <- if(runif(1)>0.7) f1 else f2
f(1,1)
or more compact
(if(runif(1)>0.7) f1 else f2)(1,1)
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 5:10 PM, Marcio Resende wrote:
>
>
Hi,
I don't find a r-inferno.pdf that has detailed table of contents and
bookmarks. If it is possible, can somebody help generated one and post
it on line?
Regards,
Peng
__
R-help@r-project.org mailing list
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A quick question about stableFit() in the fBasics package. Is it
possible to constrain the gamma and delta parameters and only estimate
the alpha and beta parameters? I tried:
##
set.seed(1953)
r = rstable(n = 1000, alpha = 1.9, beta = 0.3)
stableFit(r, gamma=1, delta=0, type=c("q"
Hi,
On Sep 17, 2009, at 7:39 AM, Samuel Okoye wrote:
Hello,
I have 12 sample each sample has got 1000 observation, i.e I have a
matrix X with 1000 rows and 12 columns!
m <- svm(t(X))
p <- predict (m)
Can anyone tell me how to use svmtrain() in R!
I guess you're using the svm in the e107
I've been trying to understand the as.Date functionality and I have a date
and time stamp field that looks like this:
"Tue Sep 15 09:22:09 -0600 2009"
and I need to turn it into an R Date object for analysis.
Simple date conversions I have down, no problem:
> adate = c("7/30/1959")
> as.Date(a
Hi all,
I need to automate a process in order to prepare a a big loop in the future
but I have a problem with the *command function*
First I fit a model with lm
>
model1<-lm(data2[,2]~data2[,1]+I(data2[,1]^2)+I(data2[,1]^3)+I(data2[,1]^4))
I extract the coefficients to build the polynomial.
c
Good Mourning,
I have a function to generate a matrix as I show part of it;
g[j,i]<-if (gen[j,i]==0) al1[i,1]+al1[i,1] else ...
However i would like that this function occurred with a probability P and
that another function (another formula to generate g matrix) with
probability P-1
That´s it,
Dear Tinn-R users,
I've a basic question: I don't understand how to configure Tinn-R to "hint"
about the required elements in a certain code, e.g. when typing "mean("
a box would pop-up just above the code informing that "(x, trim = 0, na.rm =
FALSE, ...) is the required info which must be
Hello,
I have 12 sample each sample has got 1000 observation, i.e I have a matrix X
with 1000 rows and 12 columns!
m <- svm(t(X))
p <- predict (m)
Can anyone tell me how to use svmtrain() in R!
Many Yhanks,
Samuel
[[alternative HTML version deleted]]
___
Hi,
I want to do a pca using a set of variables which are ordered. I have used
the dudi.mix method from the ade4 package, but when I do the $index it shows
me that R has considered my variables as quantitative.
What should I do?
--
View this message in context:
http://www.nabble.com/How-to-do-
The validate.rpart function in the rms package will handle the rpart
part of this. It makes sure that the tree is re-built from scratch for
each re-sample. It estimates MSE and Somers' Dxy (twice (ROC area -.5)).
Frank
jamesmcc wrote:
Greetings tree and forest coders-
I'm interested in com
Hi,
I don't understand what the meaning of the following lines returned by
model.matrix(). Can somebody help me understand it? What can they be
used for?
attr(,"assign")
[1] 0 1 2 2
attr(,"contrasts")
attr(,"contrasts")$A
[1] "contr.treatment"
attr(,"contrasts")$B
[1] "contr.treatment"
Regards,
Greetings tree and forest coders-
I'm interested in comparing randomforests and regression tree/ bagging tree
models. I'd like to propose a basis for doing this, get feedback, and
document this here. I kept it in this thread since that makes sense.
In this case I think it's appropriate to compar
Try placing the column names into labCol and the rownames into labRow
e.g.heatmap.2(mat,dendrogram=c("none"),
Rowv=F, Colv=F, labRow = seq(-7.5,7.5,by=5), labCol=seq(-3,3,by=2))
Schalk Heunis
On Thu, Sep 17, 2009 at 3:53 PM, bioinformatics_guy wrote:
>
> Schalk,
>
> Thats a great function! The o
Dear All,
maybe this is something obvious, I seem to be incapable of
understanding how S4 works.
So, in package 'A' I defined a "summary" method for my class:
setMethod("summary", signature(object="ListHyperGResult"),
function(object, pvalue=pvalueCutoff(object), categorySize=NULL) {
Or:
replicate(5, 1:10)
On Thu, Sep 17, 2009 at 11:02 AM, Peng Yu wrote:
> Hi,
>
> I can use the following code to generate a matrix, each column of
> which is 'x'. But I have to specify '5' twice in the second command. I
> am wondering if there is a better way to do it.
>
>> x=1:10
>> matrix(rep
On 09/17/2009 04:02 PM, Peng Yu wrote:
Hi,
I can use the following code to generate a matrix, each column of
which is 'x'. But I have to specify '5' twice in the second command. I
am wondering if there is a better way to do it.
x=1:10
matrix(rep(x,5),nc=5)
t(matrix(rep(x,5),nc=5))
Regards,
On 09/17/2009 04:02 PM, Peng Yu wrote:
Hi,
I can use the following code to generate a matrix, each column of
which is 'x'. But I have to specify '5' twice in the second command. I
am wondering if there is a better way to do it.
x=1:10
matrix(rep(x,5),nc=5)
t(matrix(rep(x,5),nc=5))
Regards,
Hi,
I can use the following code to generate a matrix, each column of
which is 'x'. But I have to specify '5' twice in the second command. I
am wondering if there is a better way to do it.
> x=1:10
> matrix(rep(x,5),nc=5)
> t(matrix(rep(x,5),nc=5))
Regards,
Peng
On Thu, 17 Sep 2009, William Revelle wrote:
At 2:40 PM +0900 9/17/09, Gundala Viswanath wrote:
I have a data frame (dat). What I want to do is for each row,
divide each row with the sum of its row.
The number of row can be large > 1million.
Is there a faster way than doing it this way?
datno
On Thu, 17 Sep 2009, [ISO-8859-1] Noela Sánchez wrote:
Hi all,
I need to automate a process in order to prepare a a big loop in the future
but I have a problem with the *command function*
First I fit a model with lm
model1<-lm(data2[,2]~data2[,1]+I(data2[,1]^2)+I(data2[,1]^3)+I(data2[,1]^
Schalk,
Thats a great function! The only question is, is it as flexible as
heatmap.2?
I figured out how to get it from rearranging the rows and columns but I
can't figure out how to label the rows and columns? What I like about the
heatmap.2 is that it gives a grid and histogram of the heatmap
On Thu, 17 Sep 2009, Peng Yu wrote:
Hi,
Suppose 'x' is a vector of length n and 'y' is a vector of length m, I
am wondering what the time complexity of 'match(x,y)' is. Is it n
times m?
match() hashes the second argument then does hash lookups for the first
argument (the source is in src/mai
try running it on a grid within "system.time()"
And the answer will be revealed.
Tal
On Thu, Sep 17, 2009 at 3:15 PM, Peng Yu wrote:
> Hi,
>
> Suppose 'x' is a vector of length n and 'y' is a vector of length m, I
> am wondering what the time complexity of 'match(x,y)' is. Is it n
> times m
Hi bioinformatics_guy
I think you are looking for the "image" function:
image(mat)
The heatmap.2 function does hierarchical clustering on rows and columns and
then orders the rows and columns according to the results of the clustering.
Image simply plots the matrix.
HTH
Schalk Heunis
On Thu, S
On Sep 17, 2009, at 8:58 AM, Richardson, Patrick wrote:
This was working a few weeks ago, but perhaps the package has been
updated since then.
model.1 <- lrm(response ~ p_value, data=c_abl_oncogene_1_RTK)
When I run the following command . . . .
prediction.1 <- predict(model.1, type=c("fitt
_ wrote:
Hi all,
I installed the library inline to my default R-enviroment
(c:\Programme\R.. )
downloaded and installed RTools from
http://www.murdoch-sutherland.com/Rtools/
to c:\Rtools.
Path variable is set right (with respect to order) but I get still the
error message
from my R
Error i
Hi,
Using Ape, I have constructed an object of class "phylo", using the
method 'nj' (lets call the object 'tree_ja').
I also have a given subset of 'tree_ja' in a vector (lets call the
vector 'subspecies').
What I want to do, is construct a nj tree - plot(tree_ja) - but have the
species in vect
On Sep 17, 2009, at 4:31 AM, Philipp Pagel wrote:
On Thu, Sep 17, 2009 at 10:08:57AM +0200, Philipp Pagel wrote:
is it possible to convert latex code to pdf in R (like a
latex-program would do it)?
Is there a package that comes with this capabilities?
My problem is that I want to generate t
This was working a few weeks ago, but perhaps the package has been updated
since then.
model.1 <- lrm(response ~ p_value, data=c_abl_oncogene_1_RTK)
When I run the following command . . . .
prediction.1 <- predict(model.1, type=c("fitted"))
I get the following error message. . . .
Error in predi
> Dear all,
> I want to directly write the loglike function of poisson- lognormal
> regression and then estimate the parameters. the response (Y)is count
> and I have two explanatory variable (x1:nominal) and (x2:continiuouse).
> which package in R can be used ?.How can input the data and write the
I have a file of the following form
-11 -10 -9 -8
-10 -9 -8 NA
-9 -7NA NA
-8NA NA NA
So basically a NxN matrix of log scores. I want to get a heatmap of these
log scores but I'm having a problem.
I'm using the following code
library(gplots)
data=read.table("filein.txt",header=
Hi,
Suppose 'x' is a vector of length n and 'y' is a vector of length m, I
am wondering what the time complexity of 'match(x,y)' is. Is it n
times m?
Regards,
Peng
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
The 2nd constraint holds trivially and the 1st constraint implies that the
maximum is 10. The solution is not unique and any values of the
variables satisfying the 1st constraint are optimum. No software
needed.
On Thu, Sep 17, 2009 at 4:19 AM, pragathichi wrote:
>
> Can someone suggest which p
Try this after read the data file:
dat[is.na(dat[,5]),5] <- '-'
On Thu, Sep 17, 2009 at 3:33 AM, Gundala Viswanath wrote:
> I have a data file that looks like this.
>
> __DATA__
> D7KAR5Z02F447V 176 G 0.22
> D7KAR5Z02J3WLG 94 A 1.05 29
> D7KAR5Z02F4K6L 198 a 0.13
> D7KAR5Z02J4SYO 6
Hi!
I've performed a Google Scholar Search using a query, let's say "Frank
Harrell", and parsed the links to the EndNote references from the resulting
HTML code. Now I'd like to download all the references automatically. For
this, I have tried to use RCurl, but I can't seem to get it working: I
al
I've had similar problems. See:
http://article.gmane.org/gmane.comp.lang.r.rosuda.devel/747
Although a bit out of date, there is a page on GUIs for R at
these two links:
http://www.sciviews.org/_rgui/
http://wiki.r-project.org/rwiki/doku.php?id=guis:guis
On Thu, Sep 17, 2009 at 5:58 AM, David You
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