> "PS" == Phil Spector
> on Tue, 26 May 2009 09:25:26 -0700 (PDT) writes:
PS> Janna -
PS> Another thing that's sometimes useful with a new package
PS> is to run the example function, like
PS> example(TTR)
PS> This will run the examples from the documentation to g
Immaterial, yes, but it is always good to test :) and your solution *is*
faster and it is even faster if you can assume byte strings:
> strings = sprintf('f:/foo/bar//%s.tif', replicate(1000,
paste(sample(letters, 10), collapse='')))
> library(rbenchmark)
> benchmark(columns=c('test', 'elapsed
I am looking for a package to perform harmonic analysis with the goal of
estimating the period of the dominant high frequency component in some
mono-channel signals.
I guess there are presumably a number of CRAN packages allowing for such
analysis. However, my search with keywords was not succe
Hallo Everyone,
I have a problem getting R DCom to work on a MS Server 2003. I am using
Visual Studio 2005 to use some statistical functions from R. I have
installed DCOM 1.3.5. but as soon as the statement iR.Init("R") is executed
I get the following error:
Exception from HRESULT: 0x8004001
I saw a post (https://stat.ethz.ch/pipermail/r-help/2008-January/153086.html)
where you stated you were using R to do some apache log analysis. I was about
to embark on such a project . Is it posted anywhere (or could you drop it to
me ?) I'm sure you are as busy as I am, if your code is op
The email addresses in this message were obscured. If you are
interested, please send email to
arangel at spss dot com.
Regards,
Jon Peck
jkpeck at gmail dot com.
-- Forwarded message --
From: Jon Peck
Date: May 26, 3:40 pm
Subject: Beta Testers Wanted for SPSS Statistics Dev
Did you mean this:
> write.table(t, eol=",\n", row.names=FALSE, col.names=FALSE)
"",
"01001001011011101100",
"1001001011010101",
"1101110100000011",
"000100100101001001011001",
"000101101101101001101001",
You can use readLines to read the data in and then gsub to remove the
characters you don't want and the textConnection to 'read' in the processed
data.
> x <- readLines("/tempxx.txt")
> # show data
> x
[1] "al;skdjf a;lskdjf s;aldkfj asd;lfkj " "_)(*)(*&*(&^
&*(^%*&^%"
[3] "a;lskdfj z,xmcvn -129
Hello,
Much like Charlie Wills a year ago, I am trying to run the APE program
COMPAR.GEE with a model containing a categorical response variable and
a continuous variable.
My command code is :
compar.gee(costusdata$Syndrome ~ costusdata$Stamen, phy = costustree,
family = "binomial")
Hi!
I'm completely confusing myself attempting to solve this one. Is there a
simple way of removing particular ASCII characters from a CSV file using R.
Hopefully something simpler and faster than cycling through each individual
character and comparing them to a list of characters to remove then
POSIXct is intended to represent date/times. You can use format to just
show the times but the dates will still be there:
> format(Sys.time(), "%H:%M:%S%OS")
[1] "18:20:.910"
difftime objects can represent times although perhaps not
conveniently:
> now <- Sys.time()
> now - as.POSIXct(cut(n
Use format,
format(myt, "%H:%M:%S%OS")
--
Curt Seeliger, Data Ranger
Raytheon Information Services - Contractor to ORD
seeliger.c...@epa.gov
541/754-4638
> Thanks, that worked. However, is there is way to just get the time
> and not have the date added? I assume the date is added since POSIX
Thanks for beating me to that, Gabor. The %OS format spec isn't in the
strptime() docs. How else might we have found this for ourselves?
cur
r-help-boun...@r-project.org wrote on 05/26/2009 02:59:20 PM:
> > as.POSIXct(c("06:00:00.100","06:00:01.231"), format = "%H:%M:%S%OS")
> [1] "2009-05-26
Its in the second paragraph after the list of % codes.
On Tue, May 26, 2009 at 6:11 PM, wrote:
>
> Thanks for beating me to that, Gabor. The %OS format spec isn't in the
> strptime() docs. How else might we have found this for ourselves?
>
> cur
>
> r-help-boun...@r-project.org wrote on 05/26/
Hi Benoit,
your problem is not really a problem of lsoda. The reason of the "crash"
is a violation of the statistical assumptions of least squares
regression due to dependency of residual variance on x. Due to this, K1
is varied over a very large range of values until numeric overflow occurs.
Gabor,
Thanks, that worked. However, is there is way to just get the time and not
have the date added? I assume the date is added since POSIX is based on
seconds since 1970. I can't seem to convert the POSIX value to Chron times(),
and Chron won't take fractional seconds. Are there other w
Stefan,
Thanks for the suggestion. Lattice works great. You might also want to check
out the ggplot2 package that Luc suggested. They both seem to provide quite a
few more options than the basic graphics package in R.
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
---
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Jason Rupert
> Sent: Tuesday, May 26, 2009 1:55 PM
> To: Mark Wardle
> Cc: R-help@r-project.org
> Subject: Re: [R] Problem accessing "row number" from subset
> on a dataframe
>
Luc,
Thanks! I was not aware of that package. It looks a lot easier than what I
have been trying to do!
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Tue, 5/26/09, Luc Villandre wrote:
> From: Luc Villandre
> Subject: Re: [R] Creating multiple graphs based on
Try this:
> as.POSIXct(c("06:00:00.100","06:00:01.231"), format = "%H:%M:%S%OS")
[1] "2009-05-26 06:00:00.100 EDT" "2009-05-26 06:00:00.231 EDT"
On Tue, May 26, 2009 at 5:52 PM, Tim Clark wrote:
>
> Dear List,
>
> I am having problems converting a file with fractional seconds to class
> POSIXc
Dear List,
I am having problems converting a file with fractional seconds to class
POSIXct. I have set my options to include digits.secs and my format to just
time, but my output is the current date with my time lacking the fractions of a
second. For example:
options(digits.secs=3)
t<-c("
Since SPSS version 16 in 2007, we have had a free plug-in that allows
R programs to run within SPSS, getting some or all of the active data
and writing results to the SPSS Viewer as plain text or as SPSS pivot
tables and R charts. This can require adding as few as two lines of
code to the R progra
If you want to create that output in a file, then create one long string and
use 'cat' to output; here is an example with the output to the console:
> t <- c(
+ "",
+ "01001001011011101100",
+ "1001001011010101",
+ "1101110100
Hello,
I am trying to use the package "exams" to construct problem sets.
I have constructed an exercise which generates a list of integers and asks
the student to compute the median.
rx is the vector of n numbers
>str(rx)
num [1:16] 21 9 8 18 4 12 17 2 9 7 ...
I want to print out the entire ve
Thanks.
I am sorry that I did not clearly put my question.
I need to output the array like
t <- c(
+ "",
+ "01001001011011101100",
+ "1001001011010101",
+ "1101110100000011",
+ "000100100101001001011001",
+ "
From: Doran, Harold
Date: Tue, 26 May 2009 14:26:53 -0400
The bad news, as others have indicated, is that this list is not for
homework. The good news is that all of this is extremely easy in R!!!
> -Original Message-
> From: r-help-bounces_at_r-project.org
> [mailto:r-help-bounces_a
Ok, if you insist [although it's still unclear why you need this level
of indirection!]
Try ?which
e.g.
> which(airquality$Month==5)
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
23 24 25 26 27 28 29 30 31
> which(airquality$Month==6)
[1] 32 33 34 35 36 37 38 39 40 41 4
?which
e.g.which(airquality$Month == 6)
-- Bert Gunter
Genentech Noclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jason Rupert
Sent: Tuesday, May 26, 2009 1:55 PM
To: Mark Wardle
Cc: R-help@r-project.org
Subje
This is the sort of problem (another related one is the assumptions of the
t-test) that attracts a lot of relatively inefficient argument.
Some basic points
1. If random variables X and Y are uncorrelated (and have finite moments,
but that's a purely technical issue), the distribution of the
Stephen,
No. Currently, AFAIK, there is no such switching algorithm for optimization
in R. John Nash and I are working on a package for integrating various
optimization tools (for smooth, box-constrained optimization) in R. This
will have a function that can run through multiple algorithms.
On Tue, 26 May 2009, Chuck Cleland wrote:
On 5/26/2009 2:53 AM, Karl Knoblick wrote:
Hallo!
I have done a sample size calculation for proportions with EpiR. The input is:
treatment group rate p=0.65
control group rate p=0.50
significance level 0.95
power 0.80
two-sided
ration group 1 and 2: 1.
Mark,
I really apprecaite your response and continue to be amazed by the
responsiveness and support on the R forums.
And, well actually, I would like to get the "row number"(s) and then delete or
not via the row number.
Again, I really appreciate the response...
--- On Tue, 5/26/09, Mark
Although speed is really immaterial here this is likely
to be faster than all shown so far:
sub(".tif", "", basename(metr_list), fixed = TRUE)
It does not allow file names with .tif in the middle
of them since it will delete the first occurrence rather
than the last but such a situation is highly
Is anyone working on an R package for manipulating OWL (Web Ontology
Language), either natively or via an external library?
I don't see anything obviously relevant in CRAN, though of course OWL
functionality could be built up starting with the XML package.
Thanks,
-s
[[alter
Monica Pisica wrote:
> Hi everybody,
>
> Thank you for the suggestions and especially the explanation Waclaw provided
> for his code. Maybe one day i will be able to wrap my head around this.
>
> Thanks again,
>
you're welcome. note that if efficiency is an issue, you'd better have
perl=T
I'm trying to prepare some cross tabs, looking at a number of variables against
a variable "connector" which has 2 values: "OD Passenger" and " Connector".
When I produce a xtabs one way I have observations under "Connector" but
against a different variable "Connector" shows all 0 values.
What
Hi. I may be missing what you're trying to achieve, but...
what about
subset(airquality, airquality$Month!=6)
instead?
You can do arbitrarily complex queries if you wish, combining terms logically.
You don't have to use the subset function. You may find it helpful to
see what the following res
Please,
could you tell me how to enter a mixed or a purely conditional multinomial
logit model in NNET.
I know how to do a multinomial logit in NNET but I don't know how to do
conditional or mixed models using this package.
I do know how to do this with VGAM - but would like to compare my resu
Dear all,
The other day I was reading this post [1] that slightly surprised me:
"To reject the null of no correlation, an hypothsis test based on the
normal distribution. If normality is not the base assumption your
working from then p-values, significance tests and conf. intervals
dont mean much (
Hi,
You might like tk_choose.files from package tcltk. This comes with R but
your system needs to be capable enough:
> capabilities( )["tcktk"]
> require( tcltk )
> tk_choose.files
Romain
Derek Eder wrote:
I am used to using the [R] function choose.files() for interactive file
selection in
I am used to using the [R] function choose.files() for interactive file
selection in MS-Windows.
What is the comparable function in Linux? I expected the function
file.choose() to display similar behavior, i.e., a graphical interface
diplaying a file listing, but all I seem to get is a "text
Here is a demonstration of how to solve your problem :
n <- 30 # You might need more than 6 data points to get good estimates for
3 parameters
x1 <- rnorm(n)
x2 <- runif(n)
x3 <- rbinom(n, size=1, prob=0.4)
A <- cbind(x1, x2, x3) # 30 x 3 matrix of independent variables
b <- c(-1, 0.5, 0.2)
I've seen with other software the capability for the optimizer to switch
algorithms if it is not making progress between iterations. Is this
capability available in optim()?
Thanks,
Stephen Collins, MPP | Analyst
Health & Benefits | Aon Consulting
[[alternative HTML version deleted]]
I would like to use the "row number" information returned from performing a
subset command on a dataframe.
For example, I would like to automatically delete some rows from a dataframe if
they match a criteria. Here is my example below.
data(airquality)
names(airquality)
subset(airquality
The bad news, as others have indicated, is that this list is not for
homework. The good news is that all of this is extremely easy in R!!!
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of abel1682
> Sent: Tuesday, May 26, 2009
See the 'fixed' argument, which allows you to fix ARIMA parameters at
any value, including zero.
On Tue, 26 May 2009, FangTonggen wrote:
Hi,
i am learning R recently and find it very helpful in time series model.
In ARMA model, given (p,q) it can get the estimation of a[i] and
b[j] easily
Hi!
I am a bit new to R.
I am looking for the right function to use for a multiple regression problem
of the form:
y = c1 + x1 + (c2 * x2) - (c3 * x3)
Where c1, c2, and c3 are the desired regression coefficients that are
subject to the following constraints:
0.0 < c2 < 1.0, and
0.0 < c3 < 1.0
y
Hello,
I've started using R few months ago and I really like it.
I need to estimate standard deviation of certain statistics (some
measures of poverty). I found a really simple program, and I just need
to check whether it's OK and really calculates what it's supposed to.
Let's suppose e. g.
Thanks to Dieter Menne and Spencer Graves I started to get my way through
lsoda()
Now I need to use it in with nls() to assess parameters
I have a go with a basic example
dy/dt = K1*conc
I try to assess the value of K1 from a simulated data set with a K1 close to
2.
Here is (I think) the best co
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Marc Schwartz
> Sent: Monday, May 25, 2009 6:52 AM
> To: David Freedman
> Cc: r-help@r-project.org
> Subject: Re: [R] long format - find age when another variable
> is first 'high'
>
>
> On May 25, 2009, a
Thanks guys! expand.grid looks like the thing I need.
Meanwhile, I also came up with an alternative way of doing it using rep and
cbind.
pairwise <- function(a,b) {
aa = rep(a, each=length(b))
cbind(aa,b)
}
On Mon, May 25, 2009 at 9:52 PM, Mike Lawrence wrote:
> expand.grid(i,j)
>
>
Howdy,
Using the scheme in plotmath, I can no longer get the degree symbol
for my on-screen plots, using X11 on OS X. I instead see an upper-
case upsilon (I think). This is reproducible using
"demo(plotmath)". A figure drawn with this faulty symbol produces
correct postscript (i.e. wi
Janna -
Another thing that's sometimes useful with a new package
is to run the example function, like
example(TTR)
This will run the examples from the documentation to give
you a quick idea of what the package can do.
- Phil Spector
Hi everybody,
Thank you for the suggestions and especially the explanation Waclaw provided
for his code. Maybe one day i will be able to wrap my head around this.
Thanks again,
Monica
> Date: Tue, 26 May 2009 15:46:21 +0200
> From: waclaw.marcin.kus
Is this homework?
If so, please read the posting guide and note the part about homework.
Specifically, "Basic statistics and classroom homework: R-help is not
intended for these."
http://www.r-project.org/posting-guide.html
abel1682 wrote:
Hi to all...i'm a new R'user and i have to solve s
http://www.r-project.org/posting-guide.html
"Basic statistics and classroom homework: R-help is not intended for these. "
On Tue, May 26, 2009 at 11:37 AM, abel1682 wrote:
>
> Hi to all...i'm a new R'user and i have to solve some exercies so i ask to
> tou for an help...
>
> 1.) How i can demon
have a read at these pdfs
http://cran.r-project.org/other-docs.html
you are likely to get a bashing for asking people to do your homework for
you!
Simon.
- Original Message -
From: "abel1682"
To:
Sent: Tuesday, May 26, 2009 3:37 PM
Subject: [R] Help me...!!!
Hi to all...i'm
On 5/26/2009 10:25 AM, JannaB wrote:
If I download a package -- how can I explore what it does? For
instance, I downloaded the TTR package of off CRAN -- but how can I
find out what it does? Is there a type of API doc for each package? JB
If you ask for help using ?TTR, you'll get an overview p
With the suggestion of Jim Holtman I have successfully implemented the loop
containing locator() using RGUI by toggling the buffer to OFF. However, I am
using JavaGD and the loop still will not work so the Java graphics window is
apparently buffered and I can't figure out how to turn it off. I r
If I download a package -- how can I explore what it does? For
instance, I downloaded the TTR package of off CRAN -- but how can I
find out what it does? Is there a type of API doc for each package? JB
__
R-help@r-project.org mailing list
https://stat.et
Hi to all...i'm a new R'user and i have to solve some exercies so i ask to
tou for an help...
1.) How i can demonstrate in R that the limit for x-->infinite of
(1+1/x)^x is equal to "e"?
2.) if i have a vector of values how can i create a function that, applied
to my vector, give me "median", "
check out ggplot2:
http://had.co.nz/ggplot2/
particularly:
http://had.co.nz/ggplot2/geom_boxplot.html
On Tue, May 26, 2009 at 10:34 AM, Amit Patel wrote:
>
> Hi
>
> I have a vector of data lets call zz (40 values from 4 samples)
> the data is already in groups, i can even split up the samples us
Farrel Buchinsky-3 wrote:
>
> I have a column in which dates and times are specified thus
> m/d/ HH:MM:SS
> Alas, some entries do not include the time and therefore are only
> m/d/
> so I used read.csv and specified that the relevant column should be read
> as
> is and it remained as a
Hi
r-help-boun...@r-project.org napsal dne 26.05.2009 15:34:25:
>
> Hi
>
> I have a vector of data lets call zz (40 values from 4 samples)
Are you sure it is a vector? Your indexing suggest data frame or matrix.
> the data is already in groups, i can even split up the samples using
>
> SampA
Tim Clark wrote:
Dear List,
I would like to create several graphs of similar data. I have x and y values for several different
individuals (in this case fish). I would like to plot the x and y values for each fish separately.
I can do it using a for loop, but I think I should be using "appl
Monica Pisica wrote:
> Hi everybody,
>
> I have a vector of characters and i would like to extract certain parts. My
> vector is named metr_list:
>
> [1] "F:/Naval_Live_Oaks/2005/data//BE.tif"
> [2] "F:/Naval_Live_Oaks/2005/data//CH.tif"
> [3] "F:/Naval_Live_Oaks/2005/data//CRR.tif"
> [4]
On Tue, May 26, 2009 at 11:17 AM, Luis Ridao Cruz wrote:
> R-help,
>
> I have installed R under Ubuntu and
> I'm very new to a Linux distribution.
>
> To open an empty R session I just type R on the Terminal aplication.
> But how can I open a saved workspace?
> At present I just start R and then l
Try this:
sub(".tif$", "", basename(metr_list))
On Tue, May 26, 2009 at 9:27 AM, Monica Pisica wrote:
>
> Hi everybody,
>
> I have a vector of characters and i would like to extract certain parts. My
> vector is named metr_list:
>
> [1] "F:/Naval_Live_Oaks/2005/data//BE.tif"
> [2] "F:/Naval_Li
They look like file path, so you can make use of basename() first,
then use gsub to strip the suffix.
> x<-c("F:/Naval_Live_Oaks/2005/data//BE.tif","F:/Naval_Live_Oaks/2005/data//CH.tif")
> x2<-sapply(x,basename,USE.NAMES=FALSE)
> gsub("[.].{1,}$","",x2)
[1] "BE" "CH"
Ronggui
2009/5/26 Monica Pi
Hi
I have a vector of data lets call zz (40 values from 4 samples)
the data is already in groups, i can even split up the samples using
SampA <- zz[,2:11]
SampB <- zz[,12:21]
SampC <- zz[,22:31]
SampV <- zz[,32:41]
I would like an output that gives me 4 boxplots on one plot
one boxplot for the
On May 26, 2009, at 3:02 , Frank E Harrell Jr wrote:
Jarle Bjørgeengen wrote:
On May 26, 2009, at 4:37 , Frank E Harrell Jr wrote:
Manuel Morales wrote:
On Mon, 2009-05-25 at 06:22 -0500, Frank E Harrell Jr wrote:
Jarle Bjørgeengen wrote:
On May 24, 2009, at 4:42 , Frank E Harrell Jr wrote
Hi everybody,
I have a vector of characters and i would like to extract certain parts. My
vector is named metr_list:
[1] "F:/Naval_Live_Oaks/2005/data//BE.tif"
[2] "F:/Naval_Live_Oaks/2005/data//CH.tif"
[3] "F:/Naval_Live_Oaks/2005/data//CRR.tif"
[4] "F:/Naval_Live_Oaks/2005/data//HOME.t
Jim wrote:
> Have a look at par(xaxs="i"), which you can pass to the plot function
> as well.
Hi everybody,
Thank you very much for your suggestion, Jim. I did not think of that
graphical parameter "xaxs". It would really be a workaround for my
first example.
Unfortunately, it does not solve the
The following is a plot that used to work (last December, I think with
a patched version of ggplot2 from Hadley), but has stopped working
with recent updates. Other instances of facet_grid work and the data
look normal to me. Since I have no idea what caused the error
message, I'm having
On Mon, 2009-05-25 at 17:36 -0400, Charles Annis, P.E. wrote:
> I'm not sure how not to use chm help, since that's the only way I've ever
> done things.
>
> But why would things work well from a USB Flash Drive and not for a CD when
> the folders are identical? (The CD was burned from the image o
Hi,
i am learning R recently and find it very helpful in time series model.
In ARMA model, given (p,q) it can get the estimation of a[i] and b[j] easily
with arima() function.
X[t] = a[1]X[t-1] + ... + a[p]X[t-p] + e[t] + b[1]e[t-1] + ... + b[q]e[t-q]
but in my recent data model,
Jarle Bjørgeengen wrote:
On May 26, 2009, at 4:37 , Frank E Harrell Jr wrote:
Manuel Morales wrote:
On Mon, 2009-05-25 at 06:22 -0500, Frank E Harrell Jr wrote:
Jarle Bjørgeengen wrote:
On May 24, 2009, at 4:42 , Frank E Harrell Jr wrote:
Jarle Bjørgeengen wrote:
On May 24, 2009, at 3:34
If, as in this example, i is always 1, 2, ... and has an odd length
in each group then:
do.call(rbind, by(DF, DF$id, function(x) x[median(x$i), ]))
On Tue, May 26, 2009 at 8:13 AM, Zeljko Vrba wrote:
> I have a large data-frame with measurements such as:
>
> id i v1 v2 v3
> 1 1 1.1 1.2 1.3
>
I think it is standard practice. If you want R to load a workspace
automatically when R is launched, you can add the command in
.Rprofile. See ?Startup for more on Initialization at Start of an R
Session.
Ronggui
2009/5/26 Luis Ridao Cruz :
> R-help,
>
> I have installed R under Ubuntu and
> I'm
And with ubuntu in combination with the Array.org eeepc repository, the
installation is a piece of cake (if you follow the instructions on the
site).
cheers,
Paul
Jarle Bjørgeengen wrote:
On May 26, 2009, at 1:13 , Jarle Bjørgeengen wrote:
Hi Robert,
I agree with Robert.
You meant you a
I have a large data-frame with measurements such as:
id i v1 v2 v3
1 1 1.1 1.2 1.3
1 2 1.4 1.5 1.6
1 3 1.5 1.7 1.8
2 1 2.1 2.2 2.3
2 2 2.7 2.5 2.6
2 3 2.4 2.8 2.9
For each unique value of 'id' (which in the real data-set is a combination of
three variables) I want to compute the median of
Sebastian Meyer wrote:
Dear R developer,
I am not quite sure, if I should post my concern as a wish to
r-b...@r-project.org. Thus, as recommended, I first send an email to you.
My request is the following: I would appreciate, if it was possible to
obtain a plot of a 'stepfun' with a strict inte
On May 26, 2009, at 1:13 , Jarle Bjørgeengen wrote:
Hi Robert,
I agree with Robert.
You meant you agree with Paul, right ?
> Of course :-)
BR Jarle Bjørgeengen
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PL
Hi Robert,
I agree with Robert.
It seems the cleanest way of getting R on Linux is to use one of the
Linux distros R is packaged for.
It may work otherwise, but there _will_ be more fiddling around
resolving dependencies manually or semi manually.
Best regards.
- Jarle Bjørgeengen
On Ma
On Tue, May 26, 2009 at 11:02:22AM +0100, Robert Kinley wrote:
> I've used R for many years on windows machines, but
> have now acquired an Asus eee 1000 linux machine.
>
> In order to get the best out of the machine, I used the
> 'pimpmyeee.sh' script, to get the full KDE desktop.
>
> The versi
Hi,
perl not found
This says that perl is not installed, you need to install it. In
addition, I am not really sure what "all necessary pacakges" or "your
software" is and what you want to do with R. Please read the posting
guide carefully for requirements for postings to the help list. In
ad
Hi Robert,
I had the exact same problem on my eeepc 900. I replaced the
xandros-like linux in this way:
- Download an Ubuntu iso file (I use 8.04, Kubuntu)
- Put the .iso file on a usb stick (use unetbootin)
- Install the ubuntu version
- Install the eeepc specific stuff from http://array.org/
R-help,
I have installed R under Ubuntu and
I'm very new to a Linux distribution.
To open an empty R session I just type R on the Terminal aplication.
But how can I open a saved workspace?
At present I just start R and then load ("my_workspace") but it must be possible
to do it all at oncer
Dear R developer,
I am not quite sure, if I should post my concern as a wish to
r-b...@r-project.org. Thus, as recommended, I first send an email to you.
My request is the following: I would appreciate, if it was possible to
obtain a plot of a 'stepfun' with a strict interpretation of xlim.
What
To whom it may concern
We are currently trying to utilize your software on windows. We have downloaded
all necessary packages and followed instructions as to how to perform the
model. Thus the installation has worked perfectly, however when trying to run
the program an error message appears "Co
I have a column in which dates and times are specified thus
m/d/ HH:MM:SS
Alas, some entries do not include the time and therefore are only
m/d/
so I used read.csv and specified that the relevant column should be read as
is and it remained as a character variable.
I then split the value on
A simpler solution:
my.string <- c("",
"01001001011011101100",
"1001001011010101",
"1101110100000011",
"000100100101001001011001",
"000101101101101001101001")
my.string <- paste(my.string, collapse="\",\n
Menezes, Ian wrote:
Stefan,
Thanks for the response
I'm using the GUI version of R in Windows. I usually just click the R
icon on my desktop, so Im not sure how I would use the --internet2
option?
You can edit the shortcut (right click and follow the menus), or install
R with that option
hi
I've used R for many years on windows machines, but
have now acquired an Asus eee 1000 linux machine.
In order to get the best out of the machine, I used the
'pimpmyeee.sh' script, to get the full KDE desktop.
The version of Linux is Xandros, which I believe is
a close relative of Debian, bu
peng chen wrote:
Hi, R experts:
I am trying to generate data output in the following format:
rom_array := (
"",
"01001001011011101100",
"1001001011010101",
"1101110100000011",
"000100100101001001011001",
"00
On Tue, 26 May 2009 02:34:55 -0700 (PDT) Tim Clark
wrote:
TC> I would like separate plots for Tony, Mike, and Vicky. What is the
TC> best way to do this?
use the lattice package:
library(lattice)
xyplot(y~x|Name,data=dat)
Mr. Sarkar (the author of the package) has written an excellent book
Dear List,
I would like to create several graphs of similar data. I have x and y values
for several different individuals (in this case fish). I would like to plot
the x and y values for each fish separately. I can do it using a for loop, but
I think I should be using "apply". Please let m
On 5/26/2009 2:53 AM, Karl Knoblick wrote:
> Hallo!
>
> I have done a sample size calculation for proportions with EpiR. The input is:
> treatment group rate p=0.65
> control group rate p=0.50
> significance level 0.95
> power 0.80
> two-sided
> ration group 1 and 2: 1.0
>
> I have done this in t
Many thanks to Jim, Bill, and Carl. Using indexes instead of the for loop gave
me my answer in minutes instead of hours! Thanks for all of your great
suggestions!
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 5/22/09, jim holtman wrote:
> From: jim holtman
Dear R users,
I know cross-validation does not work in rpart with user defined split
functions. As Terry Therneau suggested, one can use the xpred.rpart function
and then summarize the matrix of the predicted values into a single
"goodness" value.
I need only a confirmation: set for example xva
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