You may refer to the last example in ?layout
Regards,
Yihui
--
Yihui Xie
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Homepage: http://www.yihui.name
School of Statistics, Room 1037, Mingde Main Building,
Renmin University of China, Beijing, 100872, China
On Wed, M
Hii,
Can anybody help me, I don't know how to print the "median". Below is my
code snipplet...
x
<-read.table(file="D:/Uni/Diplom/Diplom/Grafiken/R/BATMAN/Kabel/Batman1hop/Standardabweichung__output_30_1_Kabel(30m)_b.txt")
png(filename = "D:/Grafiken/R/Standardabweichung/Kopie.png", width =
There is some considerable confusion in both the question and the reply.
rv is **not** a random variable. It is an (iid) sample from (i.e. a
"realization" of) a random variable. It has *no* "density function" and the
density() function is simply a procedure to **estimate** the density of the
unde
I think most people find it odd at first if they have always used "=" but
quickly you get use to it and nothing could be more clear. It is explicit.
It is active and provides a direction, a value goes into an object. The
equal sign for assignment is ambiguous.
As an example
x = 3
we only kn
Dear Jens and Wacek:
I appreciate your answers very much.
I came up an example based on your comments.
I feel the example helped me to understand...(I could be missing your points
though :( )
If so, please let me know.
Simon pointed out the following link:
http://www.stat.auckland.ac.nz/mail/arch
ok,
i think i have to be more precise of what we are doing.
first thing: this code is not from me, and Im new to R (and never touched
anything like this)
Im just the lucky guy who has to maintain this crap :)
this call to the lm function is part of a code wich is used to predict the
marketvalue
rv <- rbinom(1,1,0.1) + rnorm(1)
d.rv = density(rv)
d.x = d.rv$x
d.y = d.rv$y
d.rv.max = d.rv$x[which.max(d.rv$y)]
plot(d.rv)
abline(v=d.rv.max)
#that what you want?
On Thu, Mar 12, 2009 at 6:28 PM, wrote:
> I would like to find the maximum values on the density function of a
> rando
I think Venables' and Ripley's convention makes good sense:
http://www.stat.auckland.ac.nz/mail/archive/r-downunder/2008-October/000300.html
So we not only are explicit about what we are assigning, but where we
are assigning it.
Cheers,
Simon.
On Thu, 2009-03-12 at 17:10 -0700, David M Smith w
No, MANOVA is for Multivariate analysis of variance which is used if there
are multiple responses as well as variables but you just have one response
which is blood pressure. You should just have
model <- lm(BP ~Weight+Height)
anova(model)
If Weight is related to Height only one should be signific
Hello,
When I run my .r script using source (myfilename) from console the plots appear.
However, when I execute the same file via terminal command line using R CMD
BATCH myfilename, the plots do not appear.
I am working with Mac.
Am I doing something wrong?
Thanks,
Atul
_
On Thu, Mar 12, 2009 at 8:29 AM, "Jens Oehlschlägel" wrote:
> Thus there is dangerous advice in the referenced blog which reads:
> "
> f(x <- 3)
> which means "assign 3 to x, and call f with the first argument set to the
> value 3
> "
The thrust of the blog post was the stylistic question of whe
Dear Jason,
On Thu, Mar 12, 2009 at 6:11 PM, Gabor Grothendieck
wrote:
> Try this:
>
> library(sqldf)
> BODsub <- BOD[1:3,]
> sqldf("select * from BOD except select * from BODsub")
>
> For more see: http://sqldf.googlecode.com
>
Also, please see
http://finzi.psych.upenn.edu/R/R-devel/archive/26
Dear R users,
Thanks in advance.
I am Deb, Statistician at NSW Department of Commerce, Sydney.
I am using R 2.8.1 on Windows XP.
This has reference to the package âDPpackageâ. The binary version is
available on Mac OS, but I am using Windows XP.
May I request you to assist me in the
Hi list,
I have a real problem with plotting US state map. When I try to plot the
northern state, there will be some blank space in the top of graph (see case
1 example), and when I plot southern states, there will be a blank space in
the bottom of plot (see case 2). I spent almost 2 days to figure
Thanks Thomas.
Assuming I want to change the "k" factor (used in AIC type procedures), is
there a way to do that ?
Also - is there a way to force the model to make only one "step" in the
creation of the model ?
(My aim is to be able to create an adaptive procedure, and I am looking for
a way of doi
Hello All,
Does anyone know of a package that performs constraint-based clusters?
Ideally the package could perform "Time-Ordered Clustering", a technique
applied in a recent journal article by Runger, Nelson, Harnish (using MS
Excel). Quote, "in our specific implementation of constrained
clusteri
I get the following error when I run qplot()
qplot(grade, read,data = hhm.long.m, geom = c("point", "smooth"))
Error in smooth.construct.cr.smooth.spec(object, data, knots) :
x has insufficient unique values to support 10 knots: reduce k.
I am not sure how to tackle this problem. When I take a
That was to read worksheet names but its true that the same packages
rcom and rdcom can control Excel and therefore write spreadsheets.
On Thu, Mar 12, 2009 at 5:52 PM, wrote:
> I think that Gabor sent something earlier today ( or atleast something
> related ) so check the archives for his solu
Try this:
library(sqldf)
BODsub <- BOD[1:3,]
sqldf("select * from BOD except select * from BODsub")
For more see: http://sqldf.googlecode.com
On Thu, Mar 12, 2009 at 5:58 PM, Jason Rupert wrote:
>
> I have two data.frames.
>
> One is the subset of the other. I need to determine what rows were
Jorge was kind enough to point out that I made a mistake in referencing
gabor's solution.
See below. Thanks Jorge.
Begin forwarded message
Subject: Re: [R] Writing xls - multiple sheets
Date: 3/12/2009 6:03:13 PM
From: Jorge Ivan Velez
To: markle...@verizon.net
Hi Mark,
I have two data.frames.
One is the subset of the other. I need to determine what rows were removed
from the superset data.frame to form the subset data.frame.
I was hoping to turn up functionality similar to setdiff for data.frames, but
did not have any luck. It seems I need to find a func
Sueli Rodrigues wrote:
Hi,
I'm studying the Michael J. Crawley book (Statistics An Introduction using
R)and I'm trying to reproduce one example (page 168) for plot a barplot
with error bars, but when I put the function I receive the following
message. Please, could someone told me what's wrong?
I think that Gabor sent something earlier today ( or atleast something
related ) so check the archives for his solution.
On Thu, Mar 12, 2009 at 4:29 PM, Ferry wrote:
Hi,
Is there a package I can use to write to multiple sheets on xls file,
other than using the paid version of xlsReadWri
I would like to find the maximum values on the density function of a
random variable. For example, I have a random variable
rv <- rbinom(1,1,0.1) + rnorm(1)
Its density function is given by density(rv) and can be displayed by
plot(density(rv)). How to calculate its maximum values?
A densi
Jens Oehlschlägel wrote:
> Sean,
>
>
>> would like to receive expert opinion to avoid potential trouble
>>
> [..]
>
>> i think the following is the most secure way if one really
>> really has to do assignment in a function call
>>f({a=3})
>> and if one keeps this convention, <- can b
Unfortunately, the suggested way with JauntePE does not work completely.
Maybe I have found a better alternative now:
There is a little free application by Sysinternals (now owned by MS) which
can create junction points, i.e. a system link to a directory under Windows.
It is available here:
http:
Hi,
Is there a package I can use to write to multiple sheets on xls file,
other than using the paid version of xlsReadWrite package
(xlsReadWritePro)?
Thank you,
Ferry
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
P
On Thu, 12 Mar 2009, Duncan Murdoch wrote:
Jason Rupert wrote:
I would like to use grep and gsub to manipulate a vector to make the names
used consistent, i.e. reduce a level or two.
This is dangerous: grep and gsub use regular expressions, so a lot of
characters (see ?regexp for the list)
I think you will find that many readers of this list would rather try
to dissuade you from this misguided strategy. You are unlikely to get
to a sensible solution in using step-down procedures with this sort of
situation (large number of predictors with modest size of data).
--
David Winsem
On Mar 12, 2009, at 3:02 PM, David Winsemius wrote:
True, I suppose. The specification from Ma could have been more
explicit. Should she want to only have duplicates in sequence, then
perhaps the use of construction within the rle function would be
useful.
act2[ act2$Rep[-1] != act2$Rep[
Look at:
?update
For example:
lm.obj <- lm (y ~ x1 + ... + x300)
lm.obj1 <- update(lm.obj, . ~ . - x1)
lm.obj2 <- update(lm.obj1, . ~ . - x2)
Ravi.
Ravi Varadhan, Ph.D.
Assistant Professor,
Division of Geriatric Medicin
yes, indeed, you can certainly speed things up, by just changing the
design matrix X and feeding it back to lm.fit().
In addition, if you just need the least squares estimates, then you gain
a bit more by using constructs of the form:
XtX <- crossprod(X)
Xty <- crossprod(X, y)
betas <- solve(
You should try installing fGarch package. Then you can simulate various garch
models using garchsim command. Hope it help.
jurica
SUMANTA BASAK-4 wrote:
>
> Hi All,
>
> I,m trying to do a GARCH simulation in R 2.3.0 release
> in Windows XP. I've seen garchsim function but that is
> for garch
Jason Rupert wrote:
I would like to use grep and gsub to manipulate a vector to make the names used consistent, i.e. reduce a level or two.
This is dangerous: grep and gsub use regular expressions, so a lot of
characters (see ?regexp for the list) have special meanings.
For the kind of
Hi,
Im using the lm() function where the formula is quite big (300 arguments)
and the data is a frame of 3000 values.
This is running in a loop where in each step the formula is reduced by one
argument, and the lm command is called again (to check which arguments are
useful) .
This takes 1-2 mi
Hi,
Im using the lm() function where the formula is quite big (300 arguments) and
the data is a frame of 3000 values.
This is running in a loop where in each step the formula is reduced by one
argument, and the lm command is called again (to check which arguments are
useful) .
This takes 1
Hi,
After hearing good things about the R community over on the west coast, I
have started a New York based R meetup group. We intend to have our first
get together on Thursday April 2nd, at 7pm. For more details pop on over to
http://meetup.com/nyhackr
Regards,
Josh
--
Joshua Reich
646 256 47
True, I suppose. The specification from Ma could have been more
explicit. Should she want to only have duplicates in sequence, then
perhaps the use of construction within the rle function would be useful.
act2[ act2$Rep[-1] != act2$Rep[-length(act2$Rep)], ]
DateDtime Hour Min Se
I would like to use grep and gsub to manipulate a vector to make the names used
consistent, i.e. reduce a level or two.
However, here is what I found when I attempted to use grep and gsub:
> tmp_test<-c("House 1 Plot Plus +100","House 2 Plot Plus +100","House 3 Plot
> Plus -100","House 4
Thank you for you help Dr. Winsemius.
The problem seems to stem from the fact that I have used the incorrect name in
the prediction dataframe.
The following code seems to work correctly.
Thank you again,
Michael
wt.data <- data.frame(code = factor(LETTERS[1:24]),
area =
c(60865,480,65
Simpler, but maybe wrong. Not duplicated
was my first response as well, but then I began
wondering if the question implied globally
duplicated or duplicated within subgroups.
Patrick Burns
patr...@burns-stat.com
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of "The R Inferno" and "A Guide
I think I answered a very similar question from you yesterday
but perhaps the mail went astray. The subject line is not
informative.
It may make it easier to think about if you use a function like
isFirstInRun <- function(x) c(TRUE, x[-1]!=x[-length(x)]
Given a vector x (without NA's in it) it
Hi all,
I'd like to do cross-validation on lm and get the resulting lift curve/table
(or, alternatively, the estimates on 100% of my data with which I can get
lift).
If such a thing doesn't exist, could it be derived using cv.lm, or would we
need to start from scratch?
Thanks!
--
Eric Siegel,
?try
For example,
for (i in 1:n) {
try (fit <- nls(...), silent=TRUE)
if (class(fit) != "try-error") dowhateverthatneedstobedonewiththeresults
else fit <- NA
}
Ravi.
---
Ravi Varadhan, Ph.D.
Assistant P
If the goal here is to repeatedly run a particular model from
different starting values
then the nls2 package will do that for you.
On Thu, Mar 12, 2009 at 2:13 PM, Bill Shipley
wrote:
> Hello. I have a script in which I repeatedly fit a nonlinear regression to
> a series of data sets using nls
Hi Bill,
You should have a look at the try() function that lets you enclose an
expression and handle failure in a way that prevents the entire execution
from halting.
Josh
On Thu, Mar 12, 2009 at 1:13 PM, Bill Shipley
wrote:
> Hello. I have a script in which I repeatedly fit a nonlinear regres
Hello. I have a script in which I repeatedly fit a nonlinear regression to
a series of data sets using nls and the port algorithm from within a loop.
The general structure of the loop is:
for(i in 1:n){
extract relevant vectors of dependent and independent variables
estimate starting val
Dear all,
Is there a function to fit nested logit available somewhere ?
Sincerly
Justin BEM
BP 1917 Yaoundé
Tél (237) 99597295
(237) 22040246
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz
Tammy Ma wrote:
Hi, All
I have so many files in my directory. I got the following error. At this time,
I couldn't use debug() to check error one by one because so many files getting
invloved. How can I get some idea about my error??
The usual advice: simplify the problem until it's obvio
Thank you all for the suggestions and answers.
Oliver
On Mar 12, 6:51 am, Duncan Murdoch wrote:
> On 11/03/2009 11:35 PM, Oliver wrote:
>
> > hi, all
>
> > I am looking at R package RGL to draw a colored mesh/surface plot like
> > this one (from matlab).
> >http://www.mathworks.com/access/helpde
Hi, All
I have so many files in my directory. I got the following error. At this time,
I couldn't use debug() to check error one by one because so many files getting
invloved. How can I get some idea about my error??
.
Skipping book_log-20060222T143612.txt
Skipping book_log-20060222T162
Dear all,
I did this replacement below and its work for the first case but not in the
second case! Please tell me what's wrong with the second case.
Case 1:
> m
[,1] [,2]
[1,]14
[2,]25
[3,]36
> l
[,1] [,2]
[1,]9 10
> matric1<-replace(m,m[3,],l)
> ma
If these are the only files in the directory, then you might try...
(File paths will need to change if the folder "200209" isn't in the
working directory)
fpath <- "./200209"
a <- list.files(fpath)
for(i in 1:length(a)){
assign(paste("y",i,sep=""),read.table(paste(fpath,a[i],sep="/")))
}
Ano
Hello everyone,
Do we have package in R which will estimates the parameter in
Seemingly Unrelated Spatial Regression Model? Any help would be appreciated.
Thanks
Arun
--
View this message in context:
http://www.nabble.com/Seemingly-unrelated-model-with-spatial-processes-tp22478913p22
On Mar 12, 2009, at 11:45 AM, David Winsemius wrote:
On Mar 12, 2009, at 11:14 AM, Michael Denslow wrote:
# I am not sure how to get the lines to draw correctly here
matlines(pred.frame$a,pp, lty=c(1,2,2),col="black")
The x values are your sequence whereas the y values are in the
sequen
Hi everyone,
I have data from an experiment in which human participants were
instructed to generate a random sequence of yes/no answers under 4
different conditions. I want to test how successful they were in doing
this. More specifically, I want to test the null hypothesis that the 4
conditions co
On Thu, Mar 12, 2009 at 03:06:30PM +, Mohan Singh wrote:
> I am trying to print graphs as pdf's or eps in a for loop, but I can't seem
> to get it right
>
>
>
> Either it prints only a single eps graph (overwrites) or when I use
> #pdf(paste(i,".pdf", sep="")) .. it prints all pdf's but the
On Mar 12, 2009, at 11:14 AM, Michael Denslow wrote:
Dear R help,
This seems to be a commonly asked question and I am able to run
examples that have been proposed, but I can't seems to get this to
work with my own data. Reproducible code is below. Thank you in
advance for any help you c
Sean,
> would like to receive expert opinion to avoid potential trouble
[..]
> i think the following is the most secure way if one really
> really has to do assignment in a function call
>f({a=3})
> and if one keeps this convention, <- can be dropped altogether.
secure is relative, since due
Hi,
your example is quite messy (neither reproducible or minimal). I think
you could try the following,
mdf <- data.frame(1:3)
names(mdf) <- "147"
i <- 147
mdf[ as.character(i) ]
Hope this helps,
baptiste
On 11 Mar 2009, at 22:34, Mohan Singh wrote:
Hi everyone
I am trying to
On Wed, 11 Mar 2009, Camarda, Carlo Giovanni wrote:
Dear R-users,
I am searching to the "best" way to compute a series of n matrix
multiplications between each matrix (mXm) in an array (mXmXn), and each
column of a matrix (mXn).
Please find below an example with four possible solutions.
The fi
Dear R help,
This seems to be a commonly asked question and I am able to run examples that
have been proposed, but I can't seems to get this to work with my own data.
Reproducible code is below. Thank you in advance for any help you can provide.
The main problem is that I can not get the confi
-Original Message-
From: Rolf Turner [mailto:r.tur...@auckland.ac.nz]
Sent: Wednesday, 11 March, 2009 5:09 PM
To: Szumiloski, John
Cc: r-help@r-project.org
Subject: Re: [R] Easy "Recall" to get ls(..., all.names=TRUE)?
On 12/03/2009, at 3:16 AM, Szumiloski, John wrote:
> Dear useRs,
I am trying to print graphs as pdf's or eps in a for loop, but I can't seem
to get it right
Either it prints only a single eps graph (overwrites) or when I use
#pdf(paste(i,".pdf", sep="")) .. it prints all pdf's but they are empty
Can someone suggest which method shud I use for such.
T
If I understand your question and if I understood Dr Harrell's
description of the Hmisc/Design packages capabilities, this should all
be available. I have been blessed with a dataset so large and with so
relatively few missing values that I have not yet needed to put his
methods into practi
Here is a program that will get a list of the sheet names and then
read in the indicated name. Modify to suit.
library(rcom)
xls <- "C:\\test.xls"
oxl <- comCreateObject('Excel.Application')
comSetProperty(oxl, "Visible", TRUE)
owb <- comGetProperty(oxl, "Workbooks")
ob <- comInvoke(owb, "Open",
Hi,
I would like to some excel files with some worksheets. I tried this with
the following R script:
library(gdata)
i<-1
rc<-0
while(rc != "try-error") {
wksh<-try(read.xls("cluster-microarray-FW.xls",sheet=i,verbose=TRUE,perl="perl"))
rc<-class(wksh)
print(sprintf("--- i=%2d rc=%s -
Model simplification in lme
Pinheiro and Bates suggest that model simplification of fixed effects in lme
with anova (model,model2)
is anticonservative. What is the best way to simplify a model in lme?
Testing the p value for each fixed
factor with anova (model, type="marginal") and removing it if i
Hi,
see
?dev.off
but I think (guessing you use a windows system), you would be better of
in using win.metafile() instead of x11() in initiating the graph, see
?win.metafile
There is no need to show all 100+ graphs on your display if you actually
want them in files.
hth.
BaKaLeGuM schrieb:
Hi
See ?pdf and its width and height arguments.
Also if you want to have the graph centered on a standard page, there are
additional arguments to help you achieve that effect:
> pdf("test.pdf", height=5, width=5, paper="letter", pagecentre=TRUE)
> hist(rcauchy(100))
> dev.off()
-Christos
> -Or
Much simpler would be:
act2[!duplicated(act2$Rep),] #use the negation of the duplicated
function on $Rep and indexing
DateDtime Hour Min Second Rep
51 2006-02-22 14:52:18 14 52 18 useractivity_act
52 2006-02-22 14:52:18 14 52 18 4
58
Another method would be to use a summary that incorporates both as a
measure of obesity, In medical investigations it is common to use the
BMI which is the ratio of (weight in Kg) to (height in meters squared).
Yet a third method would be to investigate for nonlinearity on the
response func
Set which size? Of the page? - then you need to specify in pdf().
Of the plot margins? - then par$mai
Of something else? Then you need to be more specific about your
intention.
Sarah
On Thu, Mar 12, 2009 at 10:05 AM, Maxl18 wrote:
>
> Hi,
> I have the following R-code:
>
> pdf(file="test.pdf")
>
If you run the example from ?biglm
data(trees)
ff<-log(Volume)~log(Girth)+log(Height)
chunk1<-trees[1:10,]
chunk2<-trees[11:20,]
chunk3<-trees[21:31,]
a <- biglm(ff,chunk1)
a <- update(a,chunk2)
a <- update(a,chunk3)
summary(a)
you can then do
b <-regsubsets(a, method="forward")
summary(b)
to
?pdf reads: width, height the width and height of the graphics region in
inches. The default values are 7.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel bio
This is a consequence of changes made to support multiple imputation, where
extracting the standard errors was needed. I will try to fix it. A work-around
is to use lapply() and subset()
lapply(c("E","M","H"), function(s) svyquantile(~api99,subset(dclus1, stype==s),
ci=TRUE,quantiles=0.5))
I am estimating daily electricity prices using GARCH (1,1). What I would like
to see is whether there is some kind of daily or seasonal effect in variance of
the price series. For instance, variance of electricity prices might be
different (higher) during weekdays as opposed to during weekend. T
Hi,
I have the following R-code:
pdf(file="test.pdf")
hist(rcauchy(100))
dev.off()
How can I set the size of the histogram in my pdf?
I tried to do with par(...) but I didn't find the right parameter yet.
Thanks, Max
--
View this message in context:
http://www.nabble.com/set-size-of-a-plot-tp
One can't assume an arbitrary function necessarily works with zoo
objects although many do; however, for functions that are sufficiently
similar to lm, like lmrob, dyn in the dyn package can transform it to
work with zoo (as well as with ts and a number of other time series
classes). Just preface l
Dear Ted,
Try this:
# Working directory -- files are located here
setwd("C:\\200209")
# Names of the files
Files<-c(
paste("BA02090",c(2:6,9),".txt",sep=""),
paste("BA0209",c(10:13,16:20,23:27,30),".txt",sep=""),
"GMAS0209.txt","MAST0209.txt"
)
Files
# Reading the files into R
Re
tedzzx wrote:
Dear R experts,
I have a folder names "200209" and in this folder there are many data files,
such as:
"BA020902.txt","BA020903.txt","BA020904.txt",
"BA020905.txt","BA020906.txt","BA020909.txt",
"BA020910.txt","BA020911.txt","BA020912.txt",
"BA020913.txt","BA020916.txt","BA020917.
Wacek Kusnierczyk wrote:
> is your data a data frame or a matrix? do you want to compute the
> differences columnwise, i.e., for each column independently? consider
> this example:
>
> # generate and display dummy data
> (d = as.data.frame(replicate(3, sample(5
>
> # compute succe
Thank you guys, it's a lot simpler than I thought.
Regards,
Rafael.
Veja quais são os assuntos do momento no Yahoo! +Buscados
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinf
On Wed, 11 Mar 2009 06:57:02 -0400
Duncan Murdoch wrote:
> g...@ucalgary.ca wrote:
> > Please forget the last email I sent with the same subject.
> > =
> > I would like to generate pseudo-random numbers between two numbers
> > using R, up to a given distribution,
> > for instance,
Does anyone knows about the possibility to use Microsoft .net runtime (or mono)
from R (like RJava for Java)?
Thanks in advance
Daniele
ORS Srl
Via Agostino Morando 1/3 12060 Roddi (Cn) - Italy
Tel. +39 0173 620211
Fax. +39 0173 620299 / +39 0173 433111
Web Site
The issue with the sample size is that there are so many measurements in
comparison to number of meats.
Aside from that, you should check out the rpart package. Its commands
are similar to the tree package, but there are more options for the
plots. I don't know immediately how to display mis
Dear List,
I have just started to familiarize with artificial neural networks and I find
two names of packages by chance using R search. But unfortunately I can not
find these packages on the CRAN. Is it possible that they were renamed? The
names of the packages in question are:
netalg
netla
I need a package that can compute missing values of n-dimensional vectors for n
> 2. This is a kind of interpolation, complicated in dimensions higher than 2.
The idea is that I have a set of fully specified vectors (i.e., with no missing
values) and I get a new vector that has one or more missi
Sorry for not answering long. After working a lot with new version of "bind"
function I find it actually really useful. Just to avoid any possible
hard-to-debug errors I try to stick to some good practices, like always
specifying default values for formal parameters and calling "bind" with
named a
Hi all and thanks for your time in advance,
I can't figure out why summary.lmrob complains when lmrob is used on a
zooreg object. If the zooreg object is converted to vector before
calling lmrob, no problems appear.
Let me clarify this with an example:
>library(robustbase)
>library(zoo)
>dad<-c(
Hi:
I can't install the R-2.8.1 on the machine IBM AIX according the
instruction configuratioin(OBJECT_MODE=64). I can successfully
./configure ***, and get a Makefile. But during compiling the source code,
there is some problem I can't fix it. Please tell me some tips about "how to
inst
Hi all,
I would like to know how to create n equidistant random points along a
multisegment line/object of class psp and to retrieve the coordinates of
those generated random points.
thanks
P.L.
--
View this message in context:
http://www.nabble.com/Randomization%2C-line-and-spatial-coordina
Dear R experts,
I have a folder names "200209" and in this folder there are many data files,
such as:
"BA020902.txt","BA020903.txt","BA020904.txt",
"BA020905.txt","BA020906.txt","BA020909.txt",
"BA020910.txt","BA020911.txt","BA020912.txt",
"BA020913.txt","BA020916.txt","BA020917.txt",
"BA020918.
On 12 Mar 2009, at 13:22, richard.cot...@hsl.gov.uk wrote:
I'm trying to write a loop to sum my data in the following way:
(the second - the first) + (the third - the second) + (the fourth -
the third) + ...
for each column.
This is just sum(diff(x)), or even x[length(x)] - x[1].
I think r
Dear Rafael,
Perhaps:
sum(diff(x))
where x is your vector. To apply above to your data set (by rows), you could
use
apply(mydata,1,function(x) sum(diff(x)))
See ?diff, ?sum and ?apply for more information.
HTH,
Jorge
On Thu, Mar 12, 2009 at 9:04 AM, Rafael Moral
wrote:
> Dear useRs,
> I'm
This is a telescoping sum that can be calculated analytically as:
(a[2] - a[1]) + ... + (a[n] - a[n-1]) = a[n] - a[1]
On Thu, Mar 12, 2009 at 9:04 AM, Rafael Moral
wrote:
> Dear useRs,
> I'm trying to write a loop to sum my data in the following way:
> (the second - the first) + (the third - t
Well actually, what about that (Assuming mydata is a data frame)
tail( mydata, 1 ) - head( mydata, 1)
since:
(the second - the first) + (the third - the second) + (the fourth - the third)
= the last - the first
Romain
Rafael Moral wrote:
Dear useRs,
I'm trying to write a loop to sum my data
> I'm trying to write a loop to sum my data in the following way:
> (the second - the first) + (the third - the second) + (the fourth -
> the third) + ...
> for each column.
This is just sum(diff(x)), or even x[length(x)] - x[1].
Regards,
Richie.
Mathematical Sciences Unit
HSL
---
Hi,
Try this;
lapply( mydata, function(x){
sum( diff( x ) )
} )
Romain
Rafael Moral wrote:
Dear useRs,
I'm trying to write a loop to sum my data in the following way:
(the second - the first) + (the third - the second) + (the fourth - the third)
+ ...
for each column.
So, I wrote someth
is your data a data frame or a matrix? do you want to compute the
differences columnwise, i.e., for each column independently? consider
this example:
# generate and display dummy data
(d = as.data.frame(replicate(3, sample(5
# compute successive differences columnwise
as.dat
1 - 100 of 121 matches
Mail list logo