To avoid the Word 2004 issue, copy the plot window then in preview select new
from cliboard. Copy and paste into Word 2004.
--
View this message in context:
http://www.nabble.com/ON-MAC%2C-how-to-copy-a-plot-on-to-Word-document--tp19354558p22217935.html
Sent from the R help mailing list archive
Hi Jorge, this does not seem to return the same thing as
p <- array(c(1:5, rep(NA, times = 3)), dim = c(5, 5, 3))
sd_fun <- function(i){
if(sum(!is.na(i))==0){
temp.sd <- NA
}else{
temp.sd <- sd(i, na.rm = TRUE)
}
return(temp.sd)
}
apply(p, 1:2, sd_fun)
Am I missing something basic here?
On We
Independent Variables: 5 different levels of exposure to information:
no information, appearance
information, educational information, contact information, and
personal information. The types Unranked Categorical Variable
Dependent Variables: 2 and are numerical
The dependent variable will be (2
Hi,
Is there any set of rules for deciding exactly how to vary slopes and
intercepts in a HLM? I have NOMINATE scores from the senate over three
years. So I have multiple observations of senators, nested in states, nested
in years. Covariates include level-1 (senator in a specific year) variables
I would like to run a t-test within a "by" group function. My
dataset, "error", is organized as the following (I have 133 Sites):
Site week Dataset Region lat_map long_map mean_tsim diff20 diff40
diff80
ALFI 15 USACE UC 48.15625 -117.0938 8.87 1.34 1.90
2.98
ALFI 16
Hello,
I d like to run a survival analysis with "left truncated data". Could you
recommend me a package to do this please ?
Thanks
Philippe Guardiola
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat
I think what in my experience is the most common causen for R code
being confined to one platform has not yet been mentioned: it needs a
package that is only available on one platform: of CRAN/BioC packages
that is only a small proprtion, but out of 2000 a small proportion is
still tens.
On T
On Thu, 26 Feb 2009 phguard...@aol.com wrote:
Hello,
I d like to run a survival analysis with "left truncated data". Could
you recommend me a package to do this please ?
The 'survival' package.
-thomas
Thomas Lumley Assoc. Professor, Biostatistics
tlum...@u.washingto
oops, then i guess i should not have sent the recode suggestion.
choonhong: I only
sent it as an example of how to recode your factor. I didn't mean to
imply ( nor
did i even give it much thought ) that what you're doing is
statistically/philosophically
correct.
I'm a friend but I think what D
Hi: John Fox's recode function in his car package provides a convenient
way for doing what
you need. I don't know what your factor is specifically but below is
mostly taken out
of the help for "recode" and shows how to take a factor and recode it to
make it a new
factor. you can apply that for
Hello,
I d like to run a survival analysis with "left truncated data". Could
you recommend me a package to do this please ?
Thanks
Philippe Guardiola
Reçevez AOL Mail sur votre téléphone. Vos e-mails accessibles à tout
m
X11() on my Vista machine running 2.8.1 seems to work the same as
windows(). From the help page, the only difference I see is that
'X11' (and 'x11') have only width, height and pointsize arguments
('windows' has another 13).
Kingsford
On Wed, Feb 25, 2009 at 8:58 PM, Ted Harding
wrote:
> There
hi ted-
thanks for your insight. i appreciate it.
sherri
(Ted Harding) wrote:
There is one MAJOR issue you will have to watch out for, far more
likely to turn up than calls like system().
This is that, if you want to have two or more plotting windows
in use at the same time, while the first o
On Wed, Feb 25, 2009 at 10:58 PM, Ted Harding
wrote:
>
> if(length(grep("linux",R.Version()$os))){
> windows <- function( ... ) X11( ... )
> }
>
Try
if (.Platform$OS.type == "windows") ... else ...
__
R-help@r-project.org mailing list
https://stat.e
You don't.
And even if you do get someone to tell you how, you may still not
legitimately lower your degrees of freedom. Friends don't let friends
use stepwise approaches to regression analysis.
--
David Winsemius
On Feb 25, 2009, at 10:33 PM, choonhong ang wrote:
The district a is the b
Try:
reshape(x, dir = "long", idvar = 1, times = cn[-1], varying =
list(cn[-1]), v.names = "X", timevar = "Name")
On Wed, Feb 25, 2009 at 11:01 PM, Juliet Hannah wrote:
> Out of curiosity, what would be a good way to do this without using
> the reshape package? Thanks!
>
> On Wed, Feb 25, 2009
Aslo note there are a number of packages with functions producing
Burnham and Anderson style AIC tables: pgirmess, bbmle,
dRedging(off-CRAN), PKtools, ...
On Wed, Feb 25, 2009 at 4:58 PM, Mark Drever wrote:
> hi folks,
>
> I'm trying to build a table that contains information about a series of
>
Without a reproducible example, i.e. the input file, one can't say
much but in general you could read it in using read.table, remove
the NAs and then convert it to zoo.
On Wed, Feb 25, 2009 at 11:29 PM, Rob Denniker
wrote:
> Dear list,
>
> I have an irregular time series saved and exported as a z
Dear list,
I have an irregular time series saved and exported as a zoo object. What is the
trick to force zoo to ignore the missing dates when reading it back in? Thanks.
> str(g)
‘zoo’ series from 1948-11-02 to 2012-11-06
Data: num [1:14881, 1:8] 1 0 0 0 0 0 0 0 0 0 ...
- attr(*, "dimnames")
On Wed, Feb 25, 2009 at 10:01 PM, Juliet Hannah wrote:
> Out of curiosity, what would be a good way to do this without using
> the reshape package? Thanks!
Well the core of the melt code is this:
ids <- data[, var$id, drop = FALSE]
df <- do.call("rbind", lapply(var$measure, function(x) {
Out of curiosity, what would be a good way to do this without using
the reshape package? Thanks!
On Wed, Feb 25, 2009 at 8:04 PM, jim holtman wrote:
> You can use the 'reshape' package:
>
>> x <- read.table(textConnection(" Grp X0 X3 X6
>> X12 X25
There is one MAJOR issue you will have to watch out for, far more
likely to turn up than calls like system().
This is that, if you want to have two or more plotting windows
in use at the same time, while the first one is autoatically
opened by the plot() command, you will have to open additional
o
On 26/02/2009, at 4:15 PM, David Winsemius wrote:
dat <- c(1,2,3)
names(dat) <- c(-2329, -1399, -669.4)
dat
-2329 -1399 -669.4
1 2 3
--
David Winsemius
On Feb 25, 2009, at 9:55 PM, Gundala Viswanath wrote:
Hi,
I have the following data that looks like this:
na
Thanks for that... the error message threw me off.
r
-
Remko Duursma
Post-Doctoral Fellow
Centre for Plant and Food Science
University of Western Sydney
Hawkesbury Campus
Richmond NSW 2753
Dept of Biological Science
Macquarie University
North Ryd
The district a is the baseline and we observe the difference between
District a & b is not significant, we can choose to combine these 2 values.
How to write code to combine these 2 value ?
> m1=glm(Claims~District+Group+Age+log(Holders),fami ly=poisson,data=mydata)
> summary(m1)
Call:
glm(formul
> dat <- c(1,2,3)
> names(dat) <- c(-2329, -1399, -669.4)
> dat
-2329 -1399 -669.4
1 2 3
--
David Winsemius
On Feb 25, 2009, at 9:55 PM, Gundala Viswanath wrote:
Hi,
I have the following data that looks like this:
names(dat)
[1] "(-2329,-2319]" "(-1399,-1389]"
Hello, I have two matrices as shown below:
Matrix 1
IDAB1BC1CD1...
name1 1,1 2,1 0,2 ...
name2 2,0 1,2 1,2 ...
name3 0,2 1,1 2,0 ...
name4 2,0 0,2 0,2
It certainly appears that you just _did_ use it as such. You got a
spline. The only error thrown was from predict() and I think that was
because you needed to use a bit of extra coercion.
> predict(sp, x=as.numeric(as.POSIXct("2008-08-02")))
$x
[1] 1217649600
$y
[1] -0.4748701
attr(,"class"
Hi,
I have the following data that looks like this:
> names(dat)
[1] "(-2329,-2319]" "(-1399,-1389]" "(-669.4,-659.4]"
How can I modify those names into just this?
[1] -2329 -1399 -669.4
- Gundala Viswanath
Jakarta - Indonesia
Dear R-helpers,
can I use a POSIXct date as the x variable in interpSpline? The help
page says x and y need to be numeric... is there a workaround?
example:
library(splines)
testdfr <-
data.frame(Date=seq(as.POSIXct("2008-08-01"),as.POSIXct("2008-09-01"),
length=10))
testdfr$yvar <- rnorm(10)
s
Hi, there
Below is my code to one Homework question. I couldn't come up with the
reasonable answer.
could you please help me to figure out what is the problem with my code?
thank you
Question is Coding P{X=j} =(1/2)^(j+1) + (1/2) *2^(j-1)/3^j
my code is
sim <-
Hi all,
I want to represent two categories with one color and have other categories
a different color on a bar plot.
I can do this using for one category/number using the ifelse call in col but
how to extend to two categories/numbers?
barplot(dataframe$vector_o_numbers, col=ifelse(dataframe$vect
I'm deeply disappointed! I keep checking the mail list to see if you guys
are posting answers to questions I haven't asked yet. It would save me a lot
of time!
Best,
Murray
- Original Message -
From: "Rolf Turner"
To: "Sherri Heck"
Cc:
Sent: Wednesday, February 25, 2009 8:16 PM
S
On 25/02/2009 8:19 PM, jdeisenberg wrote:
Sherri Heck wrote:
I have been given some Rcode that was written using a Linux OS, but I
use Windows-based R. The person that is giving it to me said that it
needs to run on a Linux system. Does anyone have any insight and/or can
verify this. I ha
hahaha! okay. at least your responses are positive! thx!
David Winsemius wrote:
Definitely "maybe". Possibly "yes". Usually.
Pick one of the above.
-- David Winsemius
On Feb 25, 2009, at 8:25 PM, Sherri Heck wrote:
i am asking if, in general, r code can be written on a linux-based
system
Sherri Heck wrote:
>
> i am asking if, in general, r code can be written on a linux-based
> system and then run on a windows-based system.
>
Yes, if you avoid system-dependent calls like, um, system , there
should be no problem. For example, normal stuff like t test, correlation,
plot, hist,
Definitely "maybe". Possibly "yes". Usually.
Pick one of the above.
--
David Winsemius
On Feb 25, 2009, at 8:25 PM, Sherri Heck wrote:
i am asking if, in general, r code can be written on a linux-based
system and then run on a windows-based system.
Rolf Turner wrote:
On 26/02/2009, at
i am asking if, in general, r code can be written on a linux-based
system and then run on a windows-based system.
Rolf Turner wrote:
On 26/02/2009, at 2:08 PM, Sherri Heck wrote:
Dear All-
I have been given some Rcode that was written using a Linux OS, but I
use Windows-based R. The perso
Sherri Heck wrote:
>
> I have been given some Rcode that was written using a Linux OS, but I
> use Windows-based R. The person that is giving it to me said that it
> needs to run on a Linux system. Does anyone have any insight and/or can
> verify this. I haven't yet obtained the code, so
On 26/02/2009, at 2:08 PM, Sherri Heck wrote:
Dear All-
I have been given some Rcode that was written using a Linux OS, but I
use Windows-based R. The person that is giving it to me said that it
needs to run on a Linux system. Does anyone have any insight and/
or can
verify this. I haven't
Dear All-
I have been given some Rcode that was written using a Linux OS, but I
use Windows-based R. The person that is giving it to me said that it
needs to run on a Linux system. Does anyone have any insight and/or can
verify this. I haven't yet obtained the code, so I haven't been able t
On Feb 25, 2009, at 7:36 PM, ekwaters wrote:
I am getting a repeated error when I try to run a logistic
regression in R
2.8.1
(glm(prop1~x1,data=glm1,family=binomial("logit"),weights=nt1))
Error in model.frame.default(formula = prop1 ~ x1, data = glm1,
weights =
nt1, :
invalid type (
You can use the 'reshape' package:
> x <- read.table(textConnection(" GrpX0X3 X6
> X12 X25 X50
+1C 0.5326517 0.6930942 0.9403883 1.157571 2.483117 2.809012
+ 2C 0.4715917 0.8613200 2.0706117 2.937632 7.530960 7.120678
+ 3
Dear Mark,
Try this:
models<-paste("model",1:3,sep="")
t(sapply(models,function(x){
m<-get(x)
c(aic=AIC(m),LL=logLik(m))
}
)
)
See ?get, ?AIC, ?logLik and ?sapply for more information.
HTH,
Jorge
On Wed, Feb 25, 2009 at 6:58 PM, Mark Drever wrote
I am getting a repeated error when I try to run a logistic regression in R
2.8.1
>(glm(prop1~x1,data=glm1,family=binomial("logit"),weights=nt1))
Error in model.frame.default(formula = prop1 ~ x1, data = glm1, weights =
nt1, :
invalid type (list) for variable 'x1'
x1 is multistate categorical
I think part of your problem with your chosen method of attack arises
from your misspelling of the logLik function. The other part arises
because you have not yet digested FAQ 7.20:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f
I haven't have much
hi folks,
I'm trying to build a table that contains information about a series of
General Linear Models in order to calculate Akaike weights and other
measures to compare all models in the series.
i have an issue with indexing models and extracting the information
(loglikehood, AIC's, etc.)
I conducted a frequency averaging procedure which left me with the data frame
below (Bin is an artifact of a cut() procedure and can be either
as.character or as.factor):
Bin Freq
1 (-180,-160] 7.904032
2 (-160,-140] 5.547901
3 (-140,-120] 4.522542
4 (-120,-100] 4.784184
5 (-
Hi all,
I am using savePlot in a loop for saving several graph but I get some
graph in 553x552, some other in 1920x1119. How comes ?
My data are almost all the same (same label, same xlim / ylim, almost
same data. Only the color changes). I save them in bmp.
Thanks for your help.
Christophe
Not to draw this off-topic thread out too long, but perhaps there are
enough interested to make it worthwhile:
> And, since my son asked me and I am basketball ignorant: Why are
> basketball scores mostly much too close to equality? The arguments
> (loose power when leading)
The relevant rul
I want to generate or simulate random numbers from a distribution within a
uniform metric of standard normal distribution. For example, how to simulate a
distribution called A which satisfies that the largest absolute difference is
equal to 0.1 between CDFof A and CDF of standard normal distribu
You didn't really provide enough detail on how you wanted the data
reshaped, but I'll take a guess:
> reshape(dat.1, direction='long',
varying=paste('X',c(0,3,6,12,25,50),sep=''), sep='')
Grp time X id
1.0 C0 0.5326517 1
2.0 C0 0.4715917 2
3.0 C0 0.5021
Jim - example is perfect - many thanks!!!
Philipp - many thanks for your example also.
jholtman wrote:
>
> This might do what you want:
>
>> x <- read.table(textConnection("ID x1
>>
>> x2 x3
> + a1 0.0123334
The plot of the tree uses base graphics (works with layout). The histogram
function is a lattice/trellis graph that uses grid graphics (at least the
histogram function that I am aware of).
Unfortunately base and grid graphics do not play nicely together without some
additional steps. Some opt
Hi,I would like to reshape the following "wide" data set to "long" form. I
would appreciate help with the correct code for "reshape". I tried a few
unsuccessfully.
Thanks.
Chetty
__
dat.1
GrpX0X3 X6 X12
Hi,
I want to have histograms behind the regression tree figure.
Since 7 leafs resulted from the tree model (rpart), it would be nice to
have correspondent histograms below the tree figure. After a little
study, I could generate the correspondent histogram for each leaf, but
can't figure out how
This might do what you want:
> x <- read.table(textConnection("ID x1
>x2 x3
+ a1 0.0123334 0.2
12.8
+ b3 0.477896366 0.2 9.6
+
On Wed, Feb 25, 2009 at 01:19:36PM -0800, Pele wrote:
>
> Hi R users,
>
> I have a data frame that contains 10K obs and 200 variables
> where I am trying to format the numeric columns to look
> like the output table below (format to 2 decimal places) but I am
> having no luck.. Can someone tell
Does anyone understand the protocol set forth in Sauerbrei's and Royston's
Multivariable Modeling book on fitting interactions in fractional polynomials?
The first step on p. 156 says to apply the FP algorithm to the predictors.
Clear enough but in what cases does one include the continuous c
Hi R users,
I have a data frame that contains 10K obs and 200 variables
where I am trying to format the numeric columns to look
like the output table below (format to 2 decimal places) but I am
having no luck.. Can someone tell me the best way to
accomplist this?
Thanks in advance for any he
Dear Matt,
You're absolutely right. The reason why my code gives different results is
because it calculates the standard deviation for each row/column in all the
arrays rather than for every cell. My bad.
You can easily get the results you posted running
>apply(p,1:2,sd,na.rm=TRUE)
Here is anoth
Dear R,
I have find a website where they report problem with ARIMA models in R. I
run the examples there and they give result as shown on the website. Does
this mean that nothing has corrected in R? Maybe you not have seen the
page, but the author said he contacted you.
Here is the URL: http:/
Hi Dar.
could you please specify what type of variables the dependent and
independent variables are ? (numeric/ordered/categorical , what is their
range)
could you please specify how many dependent and independent variables you
have ? (numeric/ordered/categorical , what is their range)
In either
see the fmingr function in src/main/optim.c
(https://svn.r-project.org/R/trunk/src/main/optim.c)
On Wed, 25 Feb 2009 rkevinbur...@charter.net wrote:
> I have read that when the gradient function is not supplied (is null)
> then first order differencing is used to find the differential. I was
> tr
Hi all,This is really a stats question as much as an R question. I'm
trying to do a joint scaling test (JST - see below) on some very
oddly-distributed data and was wondering if anyone can suggest a good way of
dealing with model violations and/or using R to evaluate how sensitive the
model is
R 2.5.1 compiled, passed the make check and has been successfully running
for a couple years on a Sun Fire V490 running Solaris 9. I need a newer
version of R, but can't get a newer version of R to pass the make check.
I've tried 2.8.1, 2.7.2, 2.6.2 and 2.6.0. (2.5.1 still passes on this
server) At
Try this:
Lines <-
'"Jahr";"Tag";"Jan";"Febr";"März";"April";"Mai";"Juni";"Juli";"Aug";"Sept";"Okt";"Nov";"Dez"
1978;1;"NA";"NA";"NA";0.0;5.5;0.0;11.8;0.0;2.4;6.4;0.0;0.0
1978;2;"NA";"NA";"NA";0.0;0.5;0.0;2.0;2.0;0.0;9.0;0.0;0.0
1978;3;"NA";"NA";"NA";0.3;0.0;3.0;3.2;0.4;0.0;24.7;0.0;0.0
1978;4;"N
Based on your description so far and on my making a reasonable set of
assumptions that would still need to be checked, your analysis would
appear to be a multivariate (connectedness, learning) analysis of
covariance of a 5 (information exposure) by 3 (previous experience)
design with 2 covari
have you thought about extracting the data and using this in ggplot?
On Wed, Feb 25, 2009 at 3:52 AM, Axel Strauß wrote:
> Prof Brian Ripley schrieb:
>>
>> On Tue, 24 Feb 2009, Axel Strauß wrote:
>>
>>> OK, the one thing I figured out:
>>> Is should be like:
>>> biplot(test.pca, cex=c(2,1), col=c
Perhaps this may help you.
Regards
data(iris3)
ir <- rbind(iris3[ , , 1], iris3[ , , 2], iris3[ , , 3])
ir.pca <- princomp(ir)
biplot(ir.pca)
# Rehacer Biplot
# Calcular Factor para re-escalar scores y eigenvectores
lambda <- ir.pca$sdev[1:2] * sqrt(ir.pca$n.obs)
scores <- t( t(ir.
poLCA is designed to work this way. There's a complete user's guide and
manual on the project website at
http://userwww.service.emory.edu/~dlinzer/poLCA/
http://userwww.service.emory.edu/~dlinzer/poLCA/
Thanks,
Drew
==
Drew Linzer
Assistant Professor
Department of Political Science
Emory Uni
I have read that when the gradient function is not supplied (is null) then
first order differencing is used to find the differential. I was trying to
track down this for my own information but I run into .Internal(optim.). I
was not sure where to look next to see the function that is automat
R 2.5.1 compiled, passed the make check and has been successfully
running for a couple years on a Sun Fire V490 running Solaris 9. I
need a newer version of R, but can't get a newer version of R to pass
the make check. I've tried 2.8.1, 2.7.2, 2.6.2 and 2.6.0. (2.5.1 still
passes on this se
I’m just setting up the experiment and need help explaining what the
data analysis would be. Let me know of any questions….. what would be
compared and how it would be measured. Is it a multi-way or 1-way
anova?
Thanks!
A 5 X 1 between-subject design will be used for the experiment. Four
tool gr
R User R User wrote:
Hi guys,
I'm evaluating R for basic data exploration. I produce a bar plot of the
data, with the x axis labels aligned vertically. However, the start of
labels longer than about 10 characters are cut off by the bottom of the
graphics window.
I'd appreciate your help in pro
Hi,
Does anyone know how to fit a GAM where one or more smooth terms are
constrained to be monotonic, in the presence of "by" variables or
other terms? I looked at the example in ?pcls but so far have not been
able to adapt it to the case where there is more than one predictor.
For example,
requi
Following Dr Ripley's advice I looked at the text.rpart documentation
a bit more thoroughly and after seeing "The edges connecting the nodes
are labeled by left and right splits." I find that the fancy=TRUE
invocation does cause a labeling of what you appear to be calling
"branches".
See
> rcorr.cens is not meant for that.
Thank you for the clarification. On a second thought, I think (hope) a
time-dependent AUC index should be more appropriate in this case, such
as survivalROC.
Many many thanks for all your help!
Eleni Rapsomaniki
Research Associate
Tel: +44 (0) 1223 7402
Well add1 (and others) does fit the regressions you asked about if you give it
the base model only including the intercept and the scope including the x
variables of interest. Unfortunately it only returns certain statistics on
those models, not the whole object, but if you were interested in t
How do you want the labels to appear? Each branch will be the logical
conjunction of the criteria for *all* of the upstream splits. Perhaps
you can get direction by looking at the code of text.rpart:
getAnywhere(text.rpart)
Any split would need to add an "& Split-N yes" or an "& Split-N No"
Eleni Rapsomaniki wrote:
Dear R-users,
One can use the rcorr.cens function in Design to compute the C index when only the stop time is indicated (I think implicitely start=0 in that case). When the start and stop times are used in a Surv object, e.g.
library(Design)
S=with(heart, Surv(start,s
Hi guys,
I'm evaluating R for basic data exploration. I produce a bar plot of the
data, with the x axis labels aligned vertically. However, the start of
labels longer than about 10 characters are cut off by the bottom of the
graphics window.
I'd appreciate your help in properly spacing the space a
Hi Mark,
There is a typo in the first way. My apologies. It should be:
# First
res<-apply(p,3,function(X)
c(scols=apply(X,2,sd,na.rm=TRUE),srows=apply(X,1,sd,na.rm=TRUE))
)
res
HTH,
Jorge
On Wed, Feb 25, 2009 at 11:42 AM, Jorge Ivan Velez wrote:
>
> Dear Matt,
>
> Here are two w
Sorry - I didn't express myself very clearly. Yes, we're looking for
common factors of A and B. One way to get there is by my initial
approach: find the prime factors of each, select those that are in
common, and then take pairwise products. My initial question was about
the last step only. But
gregexpr("\\at|\\og", text)
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Corey Sparks
> Sent: Wednesday, February 25, 2009 11:50 AM
> To: R Help
> Subject: [R] Using gregexpr with multiple search elements
>
> Dear list,
>
I am confused when trying the function survfit.
my question is: what does the survival curve given by plot.survfit mean?
is it the survival curve with different covariates at different points?
or just the baseline survival curve?
for example, I run the following code and get the survival curve
Dear list,
I am trying to use gregexpr to see if entries in a dataframe have
either of two possible values for a string.
here's an example
text<-c("fat", "rat", "cat", "dog", "log", "fish")
If I just wanted to find if any one of the elements in text match the
pattern "at" I would do
gregexp
Dear Matt,
Here are two ways:
# Data
p <- array(c(1:5, rep(NA, times = 3)), dim = c(5, 5, 3))
# First
res<-apply(p,3,function(X)
c(scols=apply(X,2,sd,na.rm=TRUE),srows=apply(X,2,sd,na.rm=TRUE))
)
res
# Second
res2<-apply(p,3,function(X)
list(scols=apply(X,2,sd,na.rm=TRUE),s
hey Laura,
I hope this help
f1 = c("a","b","c")
f2 = c("b","a","c","d")
match(f2,f1)
f3 = match(f2,f1,0)
?match
cbind(f2,f3)
cbind(f2,f3>0)
f4 = ifelse(f3>0,"yes","no")
cbind(f2,f4)
data.frame(f2,f4)
Patrizio
2009/2/25 Laura Rodriguez Murillo :
> Hi dear list,
>
> If anybody could help me, it wo
Hi Dar.
I am not sure I got your question -
Are you asking what analysis to perform ?
Or how to perform it ?
Could you please give more details ?
On Wed, Feb 25, 2009 at 5:52 PM, Dar wrote:
> I am conducting an experiment where students are put into 5 total
> groups (one is the control grou
I am conducting an experiment where students are put into 5 total
groups (one is the control group). They are given a task and then I'm
measuring if there are differences (A 5 X 1 between-subject design
will be used for the experiment). I'm a little confused on the data
explanation (or should I s
Dear help, suppose I have this array and want to compute sd aross rows and
columns.
p <- array(c(1:5, rep(NA, times = 3)), dim = c(5, 5, 3))
apply(p, 1:2, sd) fails because sd requires at least 2 numbers to compute sd
apply(p, 1:2, sd, na.rm = TRUE) fails for the same reason
I crafted my own fu
Hi Laura.
Let's assume file 1 and 2 are vectors loaded in R named: vec1 and vec2,
here is a short code (with dummy numbers) for a solution:
vec1 <- c(1,2,34,4,3,6,76)
vec2 <- c(1,2,34,76,24,62,1,4234,435,4333,4422,304,776)
which.vec2.where.in.vec1 <- vec2 %in% vec1
which.vec2.where.in.vec1.t
Hi dear list,
If anybody could help me, it would be great!
I have two files:
File 1 is a list (one column and around 10 rows)
File 2 is a list with all the names from file one and a few more (one
column and more than 10 rows)
What I want is to add a column in file 2 that says which name
On Wed, Feb 25, 2009 at 4:43 PM, Charles C. Berry wrote:
> On Wed, 25 Feb 2009, Gustaf Rydevik wrote:
>
>> On Wed, Feb 25, 2009 at 3:30 PM, hadley wickham
>> wrote:
>>>
>>> And for completeness here's a function that returns the next integer
>>> on each call.
>>>
>>> n <- (function(){
>>> i <- 0
Did you set a system property for java.libary.path that points to the
native library as the error message instructs?
I'm not familiar with NetBeans, but in Eclipse you can set the JVM
properties in a dialog. Otherwise you can always pass it in via the
command line: -Djava.library.path=
HTH,
Brian
on 02/25/2009 07:52 AM Frank E Harrell Jr wrote:
> Dieter Menne wrote:
>> Frank E Harrell Jr vanderbilt.edu> writes:
>>
>> ... Word and pdf
>>
>>> It depends on how you copy. By all means use Insert ... Picture ...
>>> from file and directly insert pdf.
>>
>> Please, tell me how you got this to
hadley wickham wrote:
> On Wed, Feb 25, 2009 at 8:41 AM, Wacek Kusnierczyk
> wrote:
>
>> hadley wickham wrote:
>>
>>> And for completeness here's a function that returns the next integer
>>> on each call.
>>>
>>> n <- (function(){
>>> i <- 0
>>> function() {
>>> i <<- i + 1
>>>
Maybe as a starter
RSiteSearch("linear discriminant analysis")
R has tools to help you help yourself with this types of questions.
-Christos
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Arup
> Sent: Wednesday, February
Dear friends
I have clustered some objects using the hclust algorithm, with method ward. I
then cutree with 48 classes.
distPredTurn<-as.dist(resultMatrix)
hctr<-hclust(distPredTurn,"ward")
cutree(hctr,k=NC)
I would like to estimate the similarity between each pair of the 48 clusters,
for exa
1 - 100 of 180 matches
Mail list logo
