Hi All,
I am from the packaging team in RBS.
We use R DCOMServer Manager 2.0, this application uses RGUI 2.3.0 as one of its
components.
We are planning to upgrade to the latest version of RGUI 2.8.0 but found that R
DCOMServer manager is not compatible with the latest version.
Can you direct me
I have some data (REE plots - geochemistry) where I have values 1:14 for the
x axis, but have no data for some x values. Here for example, let's say
that I don't have data for x=2,5,8.
So
x<-1:14
y<-c(4, NA, 5, 9, NA, 3.4, 8, NA, 19, 22, 12, 14, 15.3, 15)
if I plot the data
plot(x,y)
and then
Hi:
I am coding some interactive interface using an xyplot from lattice.
When a user clicks on a panel of the xyplot, a simulation is executed and
the resulting data is plotted on the corresponding panel.
The problem is that I start with an empty data frame and only fill it as the
user request dat
Michael Olschimke wrote:
Could you please share a link to the NY Times article?
http://www.nytimes.com/2009/01/07/technology/business-computing/07program.html
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R-help@r-project.org mailing list
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PLEASE do
Erik Iverson wrote:
First, you should try to figure out why they would
not want you to run R, so you can address those reasons specifically.
Reasons imply reasoning. It's usually the case that decisions like this
are made on an emotional basis, not a rational one.
"All of my bus
Could you please share a link to the NY Times article? Is it about OSS
in general or specific to R?
Thanks
Michael
Michael Bibo wrote:
> Daniel Viar gmail.com> writes:
>
>
>> I currently use R at work "under the radar", but there's a chance I
>> could loose that access. I'd like to get our
Thanks a lot for that John - really helpful. I generated some random numbers
and seem to be able to get it to work, so that's great.
One thing - it's come up with a 'Type III' test and given me a few warnings.
What's the difference between Type II and Type III tests (if there's some
basic guide y
Daniel Viar gmail.com> writes:
>
> I currently use R at work "under the radar", but there's a chance I
> could loose that access. I'd like to get our company to feel
> comfortable with open source and R in particular. Does anyone have
> any experience with their company's IT department and man
G'day all,
On Thu, 29 Jan 2009 19:24:40 -0700
Kingsford Jones wrote:
> I suppose the solution is unstable because x is ill-conditioned:
While, as you show, x is ill-conditioned, I do not believe that this is
serious enough to explain the differences that Pat sees between MATLAB
and R.
In fac
On Thu, Jan 29, 2009 at 2:29 PM, Daniel Viar wrote:
> I currently use R at work "under the radar", but there's a chance I
> could loose that access. I'd like to get our company to feel
> comfortable with open source and R in particular. Does anyone have
> any experience with their company's IT d
Daniel Viar wrote:
I'd like to get our company to feel
comfortable with open source
Anyone still denying, here in 2009, that open source offers serious
business value is a dinosaur, doomed to extinction. Their cerebella
have calcified. The balance tipped a decade ago.
Just like the real d
Dear Paul,
I noticed a typo in my response and some poor formatting in the email
message; please see below:
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
> Behalf Of John Fox
> Sent: January-29-09 9:23 PM
> To: 'pgseye'
> Cc: r-help@r-p
I suppose the solution is unstable because x is ill-conditioned:
> x
[,1] [,2] [,3] [,4]
[1,] 0.133 0.254 -0.214 0.116
[2,] 0.254 0.623 -0.674 0.139
[3,] -0.214 -0.674 0.910 0.011
[4,] 0.116 0.139 0.011 0.180
> cor(x)
[,1] [,2] [,3] [,4]
[1,] 1.000
Dear Paul,
First, to fit a multivariate linear model to your data, you'll have to
rearrange the data from "long" format (with one observation per replicate)
to "wide" format (with one observation per subject). If your data are in the
data frame Data, then you'd do something like:
Wide <- reshape(
It depends on what you mean? If you would like a goodness of fit of
your ordination to your distance matrix then this is doable and I
would suggest that you look at the labdsv tutorial -
http://ecology.msu.montana.edu/labdsv/R/
On Thu, Jan 29, 2009 at 6:50 PM, Tomek Wlodarski
wrote:
> Dear R d
Yes, Erik, there are all MS shops around! Ours happens to be one.
However, I have absolutely no push back from IT on my use of R to do
marketing analytics. The trick, Dan, is to deliver relevant and
actionable results to the business. Your champions will stick up for
you when, and if, you get any
Provide reproducible code. And you will get an answer, probably.
On Thu, Jan 29, 2009 at 8:29 PM, Edwin Wibisono wrote:
> Hello, I have problem
> I have a, and b in regression
> then I can't plot x,y with (and) a, b lines
>
> can you help me ?
>
> thx
>
>[[alternative HTML version delete
I submit the following matrix to both MATLAB and R
x= 0.133 0.254 -0.214 0.116
0.254 0.623 -0.674 0.139
-0.214 -0.674 0.910 0.011
0.116 0.139 0.011 0.180
MATLAB's inv(x) provides the following
137.21 -50.68 -4.70 -46.42
-120.71 27.28 -8.94 62.19
-58.15 6.93 -7.89 36.94
8.35
Hello, I have problem
I have a, and b in regression
then I can't plot x,y with (and) a, b lines
can you help me ?
thx
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Hi,
Am newish to stats and R, so I certainly appreciate any help. Basically I
have 50 inidividuals whom I have 6 photos each of their optic nerve head. I
want to check that the orientation of the nerve head is consistent, ie the 6
replicates show minimal or preferably no rotation differences. I'l
On Wed, Jan 28, 2009 at 9:51 AM, Dr Carbon wrote:
> How does one coerce predict.gls to incorporate the fitted correlation
> structure from the gls object into predictions? In the example below
> the AR(1) process with phi=0.545 is not used with predict.gls. Is
> there another function that does th
This is a very broad question, and the answer is going to depend on your
particular situation, which we are not privy to.
I'll say two things. First, you should try to figure out why they would not
want you to run R, so you can address those reasons specifically. Second, you
might take a par
Dear R developers and users!
I have calculated metric MDS by cmdscale from matrix of distances
(dissimilarities).
I would like to ask you how can I estimate how well this new mapping
represents characteristic features of my data set?
Thank you for any suggestions.
Best,
tomek
___
On Thu, Jan 29, 2009 at 12:05 PM, Henrik Bengtsson
wrote:
> PS. About the double-letter index (e.g. ii vs. i); A few years ago
> someone suggested me to use this, because it is much easier to search
> for 'ii' in an editor compared with a single-letter 'i'. So true. I
> made the move immediatel
Greg Snow wrote:
What you are describing is actually a permutation test rather than a bootstrap
(related concepts but with a subtle but important difference).
The way to do a permutation test with multiple x's is to fit the reduced model
(use all x's other than x1 if you want to test x1) on th
I currently use R at work "under the radar", but there's a chance I
could loose that access. I'd like to get our company to feel
comfortable with open source and R in particular. Does anyone have
any experience with their company's IT department and management that
they would be willing to share?
problem solved:
As is probably mostly the case, a convergence problem lies in the specification
of the model or the data itself.
Some information: I was trying to model the spatial distribution of fish of a
particular age. The raw observations consisted of the number of individuals of
a part
SnowManPaddington gmail.com> writes:
>
>
> Error in optim(method = "BFGS", c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, :
> initial value in 'vmmin' is not finite
>
> I am running a logit model with latent class segments. I successfully got
> estimates for 2 segments. However when I tried to incr
Thanks for the response, Stephan.
Really, I am trying to say, "My result is insignificant, my effect sizes are
tiny, you may want to consider the possibility that there really are no
meaningful differences." Computing post-hoc power makes a bit stronger of a
claim in this setting.
My real goal i
What you are describing is actually a permutation test rather than a bootstrap
(related concepts but with a subtle but important difference).
The way to do a permutation test with multiple x's is to fit the reduced model
(use all x's other than x1 if you want to test x1) on the original data and
it is easy to make a qqplot for the gamma; suppose that the sample parameters
are 1.101 and 2.49, the data in x:
plot(qgamma(ppoints(x),1.101,2.49),sort(x))
see also lattice:qqmath
albyn
Quoting Dan31415 :
Ah yes, that does produce a nice plot. Can i just ask what exactly it is
sho
On Thu, 29 Jan 2009, Christian Anderson wrote:
Hello R-Help,
I noticed that there is a thread about importing data from the clipboard
that is very poorly answered in the forum. One user suggests giving up, the
other gives a solution that echoes the clipboard, but that's exactly the
same as just
Error in optim(method = "BFGS", c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, :
initial value in 'vmmin' is not finite
I am running a logit model with latent class segments. I successfully got
estimates for 2 segments. However when I tried to increase the no. of
segments, I got this error message at
Tom Backer Johnsen wrote:
Thomas Mang wrote:
Hi,
Please apologize if my questions sounds somewhat 'stupid' to the
trained and experienced statisticians of you. Also I am not sure if I
used all terms correctly, if not then corrections are welcome.
I have asked myself the following question r
Hi ya, thanks a lot everyone!! I changed rr:ii-1 to rr:(ii-1) and the code
works!!! I finally get some estimates from the optimization function (i am
doing a logit model with 2 segments). Thanks thanks!!!
I didn't realize rr:(ii-1) and rr:ii-1 would make such a big difference,
especially because t
Sigbert,
The plot2script function in the TeachingDemos package does essentially what
Duncan talks about for you. Create your plot then run the function giving it a
filename to save the info into (or run without arguments and then past into a
script window or text editor (only tested on windows
?cat
> x <- '\t'
> print(x)
[1] "\t"
> cat(x)
>
On Thu, Jan 29, 2009 at 3:13 PM, Nick Matzke wrote:
> Hi all,
>
> Working at the R command line, how do I get strings to display e.g. tab or
> newline characters as they should be displayed, rather than as e.g. \n or
> \t?
>
> e.g.:
>> x="
Bishwa S Koirala [Thu, Jan 29, 2009 at 08:56:17PM CET]:
>> You must know your password to change your options (including changing
>> the password, itself) or to unsubscribe. It is:
>>
It is definitely a good idea to change your password ASAP.
--
Johannes Hüsing There is somethin
In the code to follow, I'm trying to label points with their corresponding
values but have been unsuccessful after many variations to the following
code. The code below creates the plot I want, I simply cannot get the black
points ("+") to display the actual value. I'm guessing the problem is
so
I got hold of the 0.0.7 RDieHarder binary package as zip for Windows from
CRANextras but don't know how to invoke its main method dieharder() in R with
"file_input" as RNG argument - how to specify path to that input file ?
the 0.0.7 as opposed to 0.1.0 doesn't seem to have ''inputfile'' arg fo
            27193   30949    V2
>
> But i have 41 columns (age column + 40 individuals)
> I have the following script but an error is thrown up
> can anyone help, where am i going wrong
>
> zz <- read.csv("Filename.csv",strip.white = TRUE)
Try this:
install.packages("r
Hi all,
Working at the R command line, how do I get strings to display e.g. tab
or newline characters as they should be displayed, rather than as e.g.
\n or \t?
e.g.:
> x="\t"
> x="\t"
> x
[1] "\t"
> print(x)
[1] "\t"
--
Nicholas J. Matzke
On Thu, 29 Jan 2009 20:55:19 +0100
r-help-requ...@r-project.org wrote:
Welcome to the R-help@r-project.org mailing list!
To post to this list, send your email to:
r-help@r-project.org
General information about the mailing list is at:
https://stat.ethz.ch/mailman/listinfo/r-help
If you eve
Hello R-Help,
I noticed that there is a thread about importing data from the clipboard
that is very poorly answered in the forum. One user suggests giving up, the
other gives a solution that echoes the clipboard, but that's exactly the
same as just ctrl-p. As I am asked this question at least once
Many thanks Hadley,
The solution you gave works well moving label locations within the area
of the axis but does not quite provide what I was after. Apologies for
the confusion - I've only been using ggplot2 it for a day.
Compare the bar chart (from previous example):
awind<-doh + geom_bar
On 1/29/2009 2:03 PM, Jason Rupert wrote:
R-users it appears I am leaning on your knowledge once again. Is there any way to add a
vertical line to a histogram and qplot "stacked" plot? Here is my current
attempt:
"qplot" approach attempt:
qplot(Run, data = data_dataframe, breaks = breaks, f
On 1/29/2009 1:57 PM, R Heberto Ghezzo, Dr wrote:
Hello, can somebody explain me why the following program does not work?
It works for me, though \u2A8A and \u222C display as boxes, something
like the way they do in Firefox if I look at this page:
http://unicode.coeurlumiere.com/?n=8192
(bu
Jason:
Check Hadley's page, there's a few examples there. Good luck
http://had.co.nz/ggplot2/geom_vline.html
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US Fish & Wildlife Service
California, USA
--- On Thu, 1/29/09, Jason Rupert wrote:
> From: Jason Ru
R-users it appears I am leaning on your knowledge once again. Is there any way
to add a vertical line to a histogram and qplot "stacked" plot? Here is my
current attempt:
"qplot" approach attempt:
qplot(Run, data = data_dataframe, breaks = breaks, fill = Temperature, main =
short_title) + sc
Hello, can somebody explain me why the following program does not work?
Which pages of Unicode are implemented?
the u22xx and 2Axx are math symbols and extensions
Thanks
Heberto Ghezzo
Montreal
plot(1)
text(1.0,1.2,"a \u2A8A b \u222C c \u5222 d", cex=2)
text(1.0,1.1," \u222C ", cex=2)
text(1.0
The lines below made me understand clearly. Maybe they are already in
some documentation,
but if not, it might help others to avoid my misunderstanding.
Thanks to all for the clarifications.
-- David
-Original Message-
From: Duncan Murdoch [mailto:murd...@stats.uwo.ca]
Sent: Thursday, Ja
Hello,
since I installed the package VGAM I have problems useing the predict for
othere methods.
for example I have a model from glm and polr the command predict(model) I get
the error: unable to find an inherited method for function "predict", for
signature "polr".
Has perhaps anybody a solut
Classification: UNCLASSIFIED
Caveats: NONE
I am new to R and somewhat to Web server programming.
I am a Java programmer, however, and have done quite a bit with X3D
(extensible 3D) computer graphics.
A statistician that I work with is doing multidimensional scaling (MDS) and
provides some x,
What does str(zz) tell you?
--
David Winsemius
On Jan 29, 2009, at 10:31 AM, Amit Patel wrote:
Hi
I have data in the format below
AgeV1 V2 V3 V4
23646 45190 50333 55166 56271
26174 35535 38227 37911 41184
27723 25691 25712 26
Hi everybody!
I´m with a problem that probably is easy for you but I really don´t know how
to solve.
On the following script:
for(j in 1:length(limiares))
{
excessos<-limiares[j]-estacao[estacao__
R-help@r-project.org mailing list
https://stat.ethz.c
?apply
e.g. for the 'min'
apply(yourMatrix, 1, min, na.rm=TRUE)
On Thu, Jan 29, 2009 at 11:58 AM, Will Glass-Husain
wrote:
> Hi,
>
> I'm a new user. I've been reading through the manual and looking at
> various examples but am still trying to make sense of the most
> efficient ways to handle ma
On 1/29/2009 11:43 AM, Thomas Mang wrote:
> Hi,
>
> Please apologize if my questions sounds somewhat 'stupid' to the trained
> and experienced statisticians of you. Also I am not sure if I used all
> terms correctly, if not then corrections are welcome.
>
> I have asked myself the following quest
Hello Will,
z=matrix(c(1,2,3,4,5,6), 2,byrow=T)
min=apply(z,1,min)
what do you need isapply
?apply and its family are very helpful.
apply( matrix, columns, function)
apply( matrix, rows, function)
Check ?apply
Cheers
Anna
Anna Freni Sterrantino
Ph.D Student
Department of Statistics
U
I am forwarding back to the R list in hopes of getting you a better
answer from someone else. This sounds like it might be logistic
autoregression?
RSiteSearch("logistic autoregress*") came up with
http://finzi.psych.upenn.edu/R/library/repeated/html/gar.html
Ben Bolker
Joseph Magagnoli w
Duncan Murdoch wrote:
> On 1/29/2009 10:39 AM, dav...@rhotrading.com wrote:
>
>> And if the loop variable does not exist before the 'for', why is it
>> created in the parent(?) environment at all?
>
> It's created in the current evaluation frame, because that's where
> everything gets created un
I am trying to estimate a model of third party intervention into civil war.
The data is panel data structure. The unit of analysis
is civil war year. For each civil war year my dependent variable is coded
0=no intervention and 1=intervention. I want to use a
lagged dependent variable as an indep
Thanks for straighten this out. Sorry for my misleading suggestion
that "special" scoping rules comes into play; it is just about
reassignments at the beginning of each loop. Here is a slightly
better illustration:
ii <- "start";
cat("ii:",ii,"\n");
for (ii in 1:2) {
cat("Outer ii:",ii,"\n");
You could look into ' try' and set it up to catch errors and do the appropriate
thing in your error handler. I don't have the exact syntax at hand right now
but looking at ?try or ?tryCatch I think will do what you want.
Kevin
Alexandra Almeida wrote:
> Hi everybody!
>
> I´m with a prob
Hi,
I'm a new user. I've been reading through the manual and looking at
various examples but am still trying to make sense of the most
efficient ways to handle matrices of data.
If I have a 2D matrix of data, how do I get the mean, min, max value
of each row? I see the "mean" function on a matri
Hi,
Please apologize if my questions sounds somewhat 'stupid' to the trained
and experienced statisticians of you. Also I am not sure if I used all
terms correctly, if not then corrections are welcome.
I have asked myself the following question regarding bootstrapping in
regression:
Say for
Hello.
I estimated a VAR(1) TSmodel (var_1) with estMaxLik from the dse1 package given
a TSdata object (mydata).
est.model <- estMaxLik(var_1,mydata)
How can I obtain the standard errors for the four coefficients of the estimated
model to check for significance? - Is it yet calculated and I ca
On 1/29/2009 11:06 AM, Patrick Burns wrote:
Certainly not a complete description, but
'The R Inferno' talks about this on page 62.
Hmmm, I don't think I agree with that description. There's only one
object named i in that example (which was
for (i in 1:6) {
cat('\n i is', i, '\n\n')
for
Hi,
Test <- function(x, y, paired) {
res <- try( ks.test(...), TRUE )
if( inherits( res, "try-error" ) )
res <- NA
res
}
Regards
patricia
> Date: Thu, 29 Jan 2009 13:22:11 -0300
> From: alexandra...@gmail.com
> To: r-help@r-project.org
> Subject: [R] He
Hi everybody!
I´m with a problem that probably is easy for you, but I really don´t know
how to solve.
On the following script:
for(j in 1:length(limiares))
{
excessos<-limiares[j]-estacao[estacao__
R-help@r-project.org mailing list
https://stat.ethz.
Certainly not a complete description, but
'The R Inferno' talks about this on page 62.
Patrick Burns
patr...@burns-stat.com
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of "The R Inferno" and "A Guide for the Unwilling S User")
dav...@rhotrading.com wrote:
I apologize for posting a wron
On 1/29/2009 10:39 AM, dav...@rhotrading.com wrote:
I apologize for posting a wrong opinion; I should of course have checked
before posting.
Henrik's examples illustrate something I had never realized before, and
it really surprised me!
Where can I read the technical details of this scoping aspe
Perhaps if you followed the posting guide and did not send HTML mail
your tables would be readable. But your anova call seems wrong, as
you have the models in decreasing not increasing order.
The correct result is (computing F test by hand)
23.1814/93
[1] 0.2492624
1.5475/3
[1] 0.5158333
I apologize for posting a wrong opinion; I should of course have checked
before posting.
Henrik's examples illustrate something I had never realized before, and
it really surprised me!
Where can I read the technical details of this scoping aspect of 'for'
as it still presents
some subtle puzzles f
Geert,
Sorry for slow reply... I don't see any obvious problems with what you've
done, so I guess it's the usual problem that PQL just doesn't *have* to
converge, and the bit of extra flexibility of using a smooth is too much for
it in this case. If you send me the data offline I can dig a litt
Hi Darren,
Sorry for taking so long to get back to you - my hard drive died and
it's taking me a while to get up and running again of backups etc.
One solution to your problem is to draw the axis labels yourself:
labels <- data.frame(rrating = 1:10, count = 19000)
awind +
opts(axis.text.x =
Hi
I have data in the format below
    Age       V1      V2    V3      V4
  23646        45190 50333 55166 56271
  26174        35535 38227 37911 41184
  27723         25691 25712 26144 26398
and would like to sort it as fo
Diederik,
The `gamm' call looks fine provided `park' is nested in `count'. You are
basically adding a random effect for each survey, and a random effect for
each `park' within survey to the the smooth effects.
best,
Simon
ps. I assume there are more than 18 observations in the full dataset --
Hi,
Â
I am trying to use the lmer function from the lme4 package in R 2.8.0. to fit a
generalized mixed-effects model for a dependent variable with a binomial
distribution (for more info on my experiment, look below). However, I encounter
a major problem: How is it possible to find the general
on 01/29/2009 08:01 AM eugen pircalabelu wrote:
> Hi R-users,
> I have the following problem with CrossTable function within “gmodels”
> package: the output of the function (format “spss” and asresid=T) can not be
> stored within another object.
> For example:
>
>> library(gmodels)
>> data(infer
Hi,
If you mean if the t.test is done as if the samples where paired, the answer is
yes if you write argument paired = TRUE; and the pairs are done in order, that
is 1º with 1º, 2º with 2º, etc.
As you wrote, (paired = FALSE) the t.test is unpaired, and the order of
elements in the vectors a
Hi R-users,
I have the following problem with CrossTable function within “gmodels” package:
the output of the function (format “spss” and asresid=T) can not be stored
within another object.
For example:
>library(gmodels)
>data(infert, package = "datasets")
> CrossTable(infert$education, infert$i
On 1/29/2009 8:56 AM, Rau, Roland wrote:
Dear all,
thank you very much.
Yes, indeed, I should have included the sessionInfo().
Both examples (unicode and standard encoding) work fine; however, I
prefer the suggestion by Prof. Ripley since it allows me to do things
like:
plot(1, main=expression(
Joseph Magagnoli gmail.com> writes:
>
> All R experts,
> How do I fit a dynamic Random effects model with a binary dependent variable
> in R
> Thanks
> JCM
>
You haven't given us nearly enough information to go on.
If you're talking about something like a state-space model with
a binary resp
Hi,
I'm working on fitting a glm model to my data using Gamma error structure
and reciprocal link. I've been using dropterm (MASS) in the model
simplification process, but the F values from analysis of deviance tables
reported by dropterm and anova functions are different - sometimes
significant
Ah yes, that does produce a nice plot. Can i just ask what exactly it is
showing. It seems to me to be a sort of Q-Q plot but with a different set of
axes. Is this correct, if so do the same interpretation rules apply for this
plot, i.e. departures from either end of the curve show poor fitting of
When doing the t-test in the below manner will r compare each element of the
array with the relevant one. I.e. if i was comparing x and y would (1 and 0)
and (1 and 9) be treated as separate variables. Or does it just assume one
variable.
# test data
x <- c(1,1.1,1.15,1.2,1.21,1.23)
y <- c(
Dear all,
thank you very much.
Yes, indeed, I should have included the sessionInfo().
Both examples (unicode and standard encoding) work fine; however, I
prefer the suggestion by Prof. Ripley since it allows me to do things
like:
plot(1, main=expression(e^"\206"))
This fails, however, with:
plo
you can use combn to create the combinations and the following will
create a list of all the results:
x1 <- x2 <- x3 <- x4 <- 1:10
comb <- combn(c('x1','x2', 'x3', 'x4'), 2)
myTab <- lapply(seq(ncol(comb)), function(x){
table(get(comb[1, x]), get(comb[2, x]))
})
# put names of the combinations
Hi
I Have a very large dataset that I would like to conduct ANOVA tests on. Im not
a very strong programmer so any help would be appreciated.
the format is
Identifier            A1      A2       B1    Â
B2Â Â Â Â Â Â C1Â Â C2Â Â Â Â Â Norm1Â Â Â Â Â Â Â Â N
On Thu, 29 Jan 2009, Mark Difford wrote:
Hi Roland,
But this is obviously not a dagger and it seems the Adobe Symbol font
does not have a dagger.
True, but ... Yoda was here.
plot(0:1,0:1, type="n")
text(x=0.5, y=0.5, labels=expression("\u2020"))
text(x=0.4, y=0.6, labels=expression("\u202
Hi,
If all else fails, you could consider using LaTeX itself with psfrag,
or perhaps a similar idea involving eps2pgf.
http://biostat.mc.vanderbilt.edu/twiki/bin/view/Main/PsFrag
Hope this helps,
baptiste
On 29 Jan 2009, at 11:24, Rau, Roland wrote:
Dear all,
I would like to plot the da
Hi Roland,
>> But this is obviously not a dagger and it seems the Adobe Symbol font
>> does not have a dagger.
True, but ... Yoda was here.
plot(0:1,0:1, type="n")
text(x=0.5, y=0.5, labels=expression("\u2020"))
text(x=0.4, y=0.6, labels=expression("\u2021"))
?plotmath, sub "Other symbols" ...
Rau, Roland wrote:
Dear all,
I would like to plot the dagger symbol in R (like LaTeX's \dagger).
However, I was unable to do so.
First, I thought maybe dagger actually exists just like the degree
symbol:
plot(0:1,0:1, type="n")
text(x=0.5, y=0.5, labels=expression(degree))
plot(0:1,0:1, type=
Hi,
Is there anyway to set up R so that it uses a SOCKS proxy in Linux? I am
getting some strange issues with the Institute's new web filtering
system and want to be able to test whether a problem I have with the
biomaRt package is caused by it.
Many thanks
Dan
--
*
Sigbert Klinke wrote:
Hi,
I know that some graphics devices in R store graphics primitives such
that a redraw is possible (e.g. when resizing the window). Is it
possible to get the current number of stored graphic primitives?
Thanks in advance
Sigbert Klinke
___
Dear all,
I would like to plot the dagger symbol in R (like LaTeX's \dagger).
However, I was unable to do so.
First, I thought maybe dagger actually exists just like the degree
symbol:
plot(0:1,0:1, type="n")
text(x=0.5, y=0.5, labels=expression(degree))
plot(0:1,0:1, type="n")
text(x=0.5, y=0.
On Thu, 29 Jan 2009, Sigbert Klinke wrote:
Hi,
I know that some graphics devices in R store graphics primitives such that a
redraw is possible (e.g. when resizing the window). Is it possible to get the
current number of stored graphic primitives?
That's not what happens: the graphics engine
Hi,
I know that some graphics devices in R store graphics primitives such
that a redraw is possible (e.g. when resizing the window). Is it
possible to get the current number of stored graphic primitives?
Thanks in advance
Sigbert Klinke
__
R-help@
Hi
r-help-boun...@r-project.org napsal dne 29.01.2009 10:25:13:
>
> Hello
>
> I have a data set that looks like this;
>
> > b2
> dato chr status PRRSvac
> PRRSsanVac PRRSsanDk PRRSdk
> 33 2007-12-03 090432Rød SPF
> 34 200
Simon, thanks for your reply and your suggestions.
I fitted the following glmm's
gamm3<-try(glmmPQL(count~offset(offsetter)+poly(lon,3)*poly(lat,3),random=list(code_tripnr=~1),family="poisson"))
Which worked OK (see summary below)
I also fitted a model using quasipoisson, but that didn't
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