Hi John,
As I mentioned in our private exchange, this is well known in R, i.e.
vectorized versions are not always faster or more efficient than straight
loops. It is a misconception that loops should be avoided at any cost. See
John Fox's illuminating article on Rnews (p. 46) on this subject.
ht
http://rcom.univie.ac.at/
Or just install the RExcelInstaller package and run the installRExcel function.
A book on the interface will be coming out sometime in Winter.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
801.408.8111
> -Origi
lamack lamack wrote:
Dear all, I have a question about RApache. Is it possible install it under
XAMPP server? I would like of some directions. Is it needed install the R
before?
As long as your XAMPP server runs some variant of UNIX, rapache should
install. and Yes, you should install R fi
Hello Christos,
To my surprise, vectorization actually hurt processing speed!
#Example
X <- c("ab", "cd", "ef")
patt <- c("b", "cd", "a")
repl <- c("B", "CD", "A")
sub2 <- function(pattern, replacement, x) {
len <- length(x)
if (length(pattern) == 1)
pattern <- rep(pattern, len
I'm trying to add stacked bars to a third column of a barplot and using
the following code:
year <- c(2004, 2005, 2006, 2007, 2008)
nlic <- c(5,8,6,4,2)
allow <- c(5,8,6,4,2)
shot <- c(1,6,0,1,0)
farm <- c(0,0,0,0,0)
dfs <-matrix(data=c(nlic, allow), nrow=5, ncol=2)
barplot(t(dfs), beside=T, nam
> > I just updated my Redhat EL systems to R-2.7.2, and tried
> to update my
> > packages as well. Lattice is one that failed. What do I
> need to do?
>
> Install the R-devel RPM? (Assuming you installed R from an RPM.)
Yes, I installed R from an RPM. Installing the R-devel RPM worked on
o
Erich Studerus, Psychiatrische Uni-Klinik wrote:
Hi,
I have a set of 30 binary variables measuring side effects after drug
treatment. Since each subject can have multiple side effects, I want to
display these side effects in a multiple choice table. I'm using the
summary and mChoice functions
You can read it in as a data.frame and then use 'aggregate' to get the mean:
> x <- read.table(textConnection(' Seller Art. Unit_Price
+ 1 v1 p1 9.148352
+ 2 v1 p1 2.858073
+ 3 v1 p2 3.775315
+ 4 v1 p2 9.821429
+ 5 v1 p3 3.286827
+
Is this what you want:
> x <- "/pages-cell.net/deepan/sony/"
> z <- gsub("/(.*)/", "\\1", x)
>
> z
[1] "pages-cell.net/deepan/sony"
On Wed, Oct 8, 2008 at 8:20 PM, Waverley <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I want to extract some of the substring via pattern recognition. But
> I don't know
Deepayan,
It is empty.
> subset(dat11, Pri_No %in% c(1,2))
[1] tallyscapenumidbbContag bbED
[6] bbENN_MN bbLPIbbLSIbbPAFRAC bbPD
[11] bbPROX_MNpfor year extent bi_ca
[16] rex_bin PriNopri1234
Frostygoat gmail.com> writes:
>
> Hi I'm getting a weird result when I try to switch from a normal box
> plot to a notched one. The ends of the box fold down toward the
> median giving a horned appearance. Is just the sample itself? It is
> small, but the un-notched plot looks okay. Anyway t
Hi all,
I am newbie in using R software and also doing statistical test. I want to
know if my data in in normal distribution. I have 2 groups of data and I did
calculate Shapiro Wilks using R software. Here is the results:
Group 1: W = 0.9206, p-value = 0.01683
Group 2: W = 0.9626, p-value =
On Wed, Oct 8, 2008 at 1:56 PM, Michael Just <[EMAIL PROTECTED]> wrote:
> Hello, this code below was from a helpful R-help user.
>
> dat <- read.csv("Resid_fix2.csv", sep="," , header=T)
> dat11 <- dat[1:413,]
> # convert ambiguous columns to factors:
> dat11$Pri_No <- factor(dat11$Pri_No)
> dat11
On Wed, Oct 8, 2008 at 12:15 PM, Rolf Turner <[EMAIL PROTECTED]> wrote:
>
> On 8/10/2008, at 5:16 PM, Deepayan Sarkar wrote:
>
>> On 10/7/08, Rolf Turner <[EMAIL PROTECTED]> wrote:
>>>
>>> I am trying to do a histogram lattice plot and I would like the
>>> histogram to be filled with a different
Hi Dan,
Thanks a lot for this! It works but I have some minor issues.
Let's take the working example for instance, which x is of
100 rows and y of 120 rows.
After merge(), z is of 120 rows and is sorted by the ascending order
of "SEARCH_KEY1".
The following is what I got out of the working examp
Dear all, I have a question about RApache. Is it possible install it under
XAMPP server? I would like of some directions. Is it needed install the R
before?
Best regards.
_
Confira vídeos com notícias do NY Times, gols direto
Hi,
I want to extract some of the substring via pattern recognition. But
I don't know how to do it in R.
In perl:
my $url = "/pages-cell.net/deepan/sony/";
if($url =~ m/\/(.*)\//g)
{
my @result = $1;
return @result;
}
How does the same work in R?
Thanks much in advance
--
Waverley @ Palo Al
On Wed, Oct 8, 2008 at 3:41 PM, Alex Karner <[EMAIL PROTECTED]> wrote:
> R friends,
>
> I'm running R 2.7.2 on Windows XP SP2.
>
> I have some data that's amenable to smoothing, and some that's not. I'm
> trying to plot smoothed lines for the former along with just points for the
> latter in a sing
Wade Wall gmail.com> writes:
> What I am wanting to do is learn to build some simple GUIs for a limited
> number of functions. Basically, I am envisioning a screen with check boxes,
> a drop down menu etc. that users could select to run analyses on imported
> data.
The R Gui Generator (http:/
Hi,
I have a set of 30 binary variables measuring side effects after drug
treatment. Since each subject can have multiple side effects, I want to
display these side effects in a multiple choice table. I'm using the summary
and mChoice functions of the Hmisc package, because it produces nicely
R friends,
I'm running R 2.7.2 on Windows XP SP2.
I have some data that's amenable to smoothing, and some that's not. I'm
trying to plot smoothed lines for the former along with just points for the
latter in a single panel. The problem comes when trying to break out the
points by group. My sample
Duncan,
Thank you so much. It is exactly what I was looking for. However, for some
reason, indices() does not work ("Error: could not find function "indices").
I used which(), it worked.
Thanks again for the help,
Julia
Duncan Murdoch-2 wrote:
>
> On 08/10/2008 2:36 PM, liujb wrote:
>> Dear
Good evening.
I have this following table and I would like to turn it into a matrix in
which my rows would be filled with de "Sellers", my columns with my
"Articles" and my data would be the mean unitary price used by each seller
in each produt.
Seller Art. Unit Price
1 v1 p1
Hi,
I'm using the package randomForest to generate a classifier for the exemplary
iris data set:
data(iris)
iris.rf<-randomForest(Species~.,iris)
Is it possible to print all decision trees in the generated forest?
If so, can the trees be also written to disk?
What I actually need is to translat
Hi Allen, look at the following working example:
x=data.frame(rnorm(100),1:100)
names(x)=c("PROBE_ID1","SEARCH_KEY1")
y=data.frame(rnorm(120),1:120)
names(y)=c("PROBE_ID2","SEARCH_KEY2")
z=merge(x,y,by.x="SEARCH_KEY1",by.y="SEARCH_KEY2",all.x=T,all.y=T)
z # check the resulting data frame it sho
Hi Allen, look at the following working example:
x=data.frame(rnorm(100),1:100)
names(x)=c("PROBE_ID1","SEARCH_KEY1")
y=data.frame(rnorm(120),1:120)
names(y)=c("PROBE_ID2","SEARCH_KEY2")
z=merge(x,y,by.x="SEARCH_KEY1",by.y="SEARCH_KEY2",all.x=T,all.y=T)
z # check the resulting data frame it sho
I am trying something I haven't attempted before and the available
documentation doesn't quite answer my questions (at least in a way I can
understand). My usual course of action would be to extract my data from my
DB, do whatever manipulation is necessary, either manually or using a C++
program,
PS - After installing rcom from CRAN as a zipped binary, my home-brew
package runs on R2.8.0 beta as it did on r releases before R2.7.x
Thank you, Professor Ripley.
Charles Annis, P.E.
[EMAIL PROTECTED]
phone: 561-352-9699
eFax: 614-455-3265
http://www.StatisticalEngineering.com
-Origina
Hello,
On 10/8/08, gallon li <[EMAIL PROTECTED]> wrote:
> I want to print the following multiple boxes of output from R.
>
[..]
> Instead of manually typing all these numbers, can I have an easy way to
> output these in the right format from R?
>
It would help to know what commands you issued, a
Professor Ripley:
I'm sorry. I misunderstood.
R version 2.8.0 beta (2008-10-07 r46631)
Copyright (C) 2008 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain conditions.
Type
On Wed, 8 Oct 2008, Waichler, Scott R wrote:
I just updated my Redhat EL systems to R-2.7.2, and tried to update my
packages as well. Lattice is one that failed. What do I need to do?
Install the R-devel RPM? (Assuming you installed R from an RPM.)
R version 2.7.2 (2008-08-25)
install.
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi Chi,
ParallelR is a commercial software to run R in parallel. It is working
very well. We tested it at a small linux cluster.
You also can use R and the parallel packages (snow, Rmpi, nws, ...)
packages. All Open Source and for free. You probably
On Wed, 8 Oct 2008, Charles Annis, P.E. wrote:
Thank you Professor:
Here is an example using R2.8.0 beta. It shows the coding to be "latin1"
But you did not use file.choose or basename here.
I installed my package which requires rcom, RODBC, RColorBrewer, survival I
was unable to find rcom
I just updated my Redhat EL systems to R-2.7.2, and tried to update my
packages as well. Lattice is one that failed. What do I need to do?
R version 2.7.2 (2008-08-25)
> install.packages("lattice", repos = "http://cran.fhcrc.org/";)
Warning in install.packages("lattice", repos = "http://cran.fh
Dear Daniel,
Thank you very much for the help!
I tried the code and got the following:
>
John<-read.table(file="John_probe.txt",header=TRUE,row.names=NULL,fill=TRUE)
>
Susan<-read.table(file="Susan_probe.txt",header=TRUE,row.names=NULL,fill=TRUE)
> dim(John)
[1] 48701 2
> dim(Susan)
[1] 4671
Can this be an answer ?
which(v %in% names(table(v)[table(v)>1]))
[1] 2 5
Nael
On Wed, Oct 8, 2008 at 8:36 PM, liujb <[EMAIL PROTECTED]> wrote:
>
> Dear R users,
>
> I have this vector that consists numeric numbers. Is there a command that
> detects the repeated numbers in a vector and returns
Hello, this code below was from a helpful R-help user.
dat <- read.csv("Resid_fix2.csv", sep="," , header=T)
dat11 <- dat[1:413,]
# convert ambiguous columns to factors:
dat11$Pri_No <- factor(dat11$Pri_No)
dat11$RecovUnit <- factor(dat11$RecovUnit)
# plot:
require(lattice)
bwplot(bbED~ Pri_No |
kathie wrote:
Dear R users,
I'd like to make this data
rem.y = c(-1,0,2,4,5)
from
y = c(-1,-1,0,2,2,2,2,4,4,5,5,5,5,5).
That is, I need to remove repeated values.
Here is my code, but I don't think it is efficient. How could I improve
this?
By using the 'unique' fu
Dear Kathie,
See ?unique.
y = c(-1,-1,0,2,2,2,2,4,4,5,5,5,5,5)
unique(y)
[1] -1 0 2 4 5
HTH,
Jorge
On Wed, Oct 8, 2008 at 3:12 PM, kathie <[EMAIL PROTECTED]> wrote:
>
> Dear R users,
>
> I'd like to make this data
>
>rem.y = c(-1,0,2,4,5)
>
> from
>
>y = c(-1,-1,0,2,2,2,2,
Interactive, Comprehensive and Highly Visual !
R-PLUS 3.3 Rocks :)
At a click, import data from different formats, use Excel-like
spreadsheet for manipulating your data, create publication-quality
reports, generate editable graphics ... and click click to run your
favorite models through dialogs
On 08/10/2008 2:36 PM, liujb wrote:
Dear R users,
I have this vector that consists numeric numbers. Is there a command that
detects the repeated numbers in a vector and returns the index of the
repeated numbers (or the actual numbers)? For example, v <- c(3,4,5,7,4).
The command would return me
Kathryn
?unique
and see also duplicated.
> unique(c(-1,-1,0,2,2,2,2,4,4,5,5,5,5,5))
[1] -1 0 2 4 5
HTH
Peter Alspach
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of kathie
> Sent: Thursday, 9 October 2008 8:12 a.m.
> To: r-help@r-proje
Manuel,
Thanks, this worked well. I was also toying around with other options in
bargraph.CI per your suggestion.
Thanks,
Michael
bargraph.CI(RecovUnit, bbED, group = year, data =scape234,
+ xlab = "Recovery Unit", ylab = "Edge Density", cex.lab = 1.5,
x.leg = 1,
+ density
On Wed, 2008-10-08 at 09:49 -0700, Dylan Beaudette wrote:
> On Wednesday 08 October 2008, Manuel Morales wrote:
> > Another option is bargraph.CI or lineplot.CI from the package sciplot.
> >
> > See http://mutualism.williams.edu/sciplot for examples.
> >
> > On Tue, 2008-10-07 at 23:31 -0500, Micha
On Wed, 2008-10-08 at 12:01 -0500, Michael Just wrote:
> Thank you all for you suggestions. They are all helpful. However, I have
> come to a more fundamental problem. Preparing my data to even make such a
> graph. I thought I was ready. I will obviously need to find the n, mean,
> and confidence
Dear R users,
I have this vector that consists numeric numbers. Is there a command that
detects the repeated numbers in a vector and returns the index of the
repeated numbers (or the actual numbers)? For example, v <- c(3,4,5,7,4).
The command would return me index 2 and 5 (or the repeated number
Dear R users,
I'd like to make this data
rem.y = c(-1,0,2,4,5)
from
y = c(-1,-1,0,2,2,2,2,4,4,5,5,5,5,5).
That is, I need to remove repeated values.
Here is my code, but I don't think it is efficient. How could I improve
this?
#---
I also managed to get the right result but within a for loop ;)
So I really appreciate your solutions!
Thanks a lot!
--
View this message in context:
http://www.nabble.com/Using-grep-tp19881017p19882769.html
Sent from the R help mailing list archive at Nabble.com.
_
Hi I'm getting a weird result when I try to switch from a normal box
plot to a notched one. The ends of the box fold down toward the
median giving a horned appearance. Is just the sample itself? It is
small, but the un-notched plot looks okay. Anyway to fix this?
e7=as.vector(c(234,37,98,116,4
Hi Dieter,
thanks a lot for looking inside my code though it was not executable...(sorry
for that).
Finally, I found a rather stupid mistake. My original code did not use the
variable i for the second boxplot. So the second round actually plotted two
different data at the two calls...
so it h
On Wed, Oct 8, 2008 at 6:17 AM, milton ruser <[EMAIL PROTECTED]> wrote:
[snip]
>
> Finally, in fact GRASP do what I am looking for, and I am starting to
> compare the results of this packages with other very wel- know softwares
> (DescktopGarp, Maxent, OpenModeller). If someone of you have suggesti
On Wednesday 08 October 2008, Manuel Morales wrote:
> On Wed, 2008-10-08 at 09:49 -0700, Dylan Beaudette wrote:
> > On Wednesday 08 October 2008, Manuel Morales wrote:
> > > Another option is bargraph.CI or lineplot.CI from the package sciplot.
> > >
> > > See http://mutualism.williams.edu/sciplot
On Wed, 8 Oct 2008, Giovanni Petris wrote:
I am wondering if there is a function in R that returns quantiles of a
weighted sample, i.e., a set of values, each coming with a different
weight. The function quantile() does that only for the case when the
weights are all equal.
In other words, I am
On 9/10/2008, at 12:34 AM, Julia S. wrote:
Hm.
Bert Gunter wrote:
that even the most technical
aspects of the discipline can be made manifest to anyone with half
a brain
and a stat 101 course under their belt.
I don't think this is something I can use in a rebuttal. The
reviewer may
On 8/10/2008, at 6:48 PM, Erin Hodgess wrote:
Hi R People:
I am looking at the Braun/Murdoch book, " A First Course in
Statistical Programming in R", and I have a question about a function
there. It's on page 52, Example 4.5; the sieve of Erastosthenes.
There is a line:
primes <- c()
Is the
On 8/10/2008, at 5:16 PM, Deepayan Sarkar wrote:
On 10/7/08, Rolf Turner <[EMAIL PROTECTED]> wrote:
I am trying to do a histogram lattice plot and I would like the
histogram to be filled with a different colour in each panel.
Note: I want every bar in each histogram to be the same colour
On 10/8/2008 2:28 PM, Kevin Wright wrote:
An earlier post asked about limiting the z-axis range. I have the
opposite problem. I need to expand the z-axis range in order to
reduce the vertical relief on the surface plot (i.e. make it flatter).
Any suggestions on how to do that?
persp3d suppor
Thank you Professor:
Here is an example using R2.8.0 beta. It shows the coding to be "latin1"
I installed my package which requires rcom, RODBC, RColorBrewer, survival I
was unable to find rcom in the packages drop-down menu. I tried mirrors
USA(PA) and USA(PA2). rcom does appear in the menu
(Ted Harding) wrote:
> On 08-Oct-08 18:00:27, Liviu Andronic wrote:
>
>> Hello everyone,
>>
>> As some may know, today Google unveiled its 2001 search index [1]. I
>> was curious to see how was R like at that time, and was not
>> disappointed. Compared to today's main page [2], seven years ago t
On Wed, 8 Oct 2008, Liviu Andronic wrote:
Hello everyone,
As some may know, today Google unveiled its 2001 search index [1]. I
was curious to see how was R like at that time, and was not
disappointed. Compared to today's main page [2], seven years ago the
page looked [3] a bit rudimentary, espe
On 08-Oct-08 18:00:27, Liviu Andronic wrote:
> Hello everyone,
>
> As some may know, today Google unveiled its 2001 search index [1]. I
> was curious to see how was R like at that time, and was not
> disappointed. Compared to today's main page [2], seven years ago the
> page looked [3] a bit rudim
An earlier post asked about limiting the z-axis range. I have the
opposite problem. I need to expand the z-axis range in order to
reduce the vertical relief on the surface plot (i.e. make it flatter).
Any suggestions on how to do that?
Kevin
__
R-hel
Dear Javier,
> sublists, to be passed to a function, sintaxis like this won't work:
>
>> sublist <- main.lst[[1:4]]
are you looking for:
sublist <- main.lst[1:4]
HTH
Claudia
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-
The package 'eha' fits these distributions (and more) with general
left truncation and right censoring, and also regression models a la
survreg. Look at 'phreg' for parametric proportional hazards models
and 'aftreg' for accelerated failure time models. In your case of no
covariates, the two functi
mentor_ gmx.net> writes:
> with the "space" parameter it is possible to change the gap / distance
> between the bars, but is it also
> possible to change the "space" after each 6th bar?
> So for example you have bars from 1 to 6 then a large gap and then the next
> six bars from 7 to 12
Space c
Hello everyone,
As some may know, today Google unveiled its 2001 search index [1]. I
was curious to see how was R like at that time, and was not
disappointed. Compared to today's main page [2], seven years ago the
page looked [3] a bit rudimentary, especially the graphic. (It is wort
noting that s
I'm running R 2.7.1 with Tinn-R 2.0.0.7 and Windows XP Professional. I
have write privileges to the folders containing my R installation, my
Tinn-R installation, and my Tinn-R initialization settings. I installed R
first, followed by Tinn-R. I have modified my RProfile.site file (in
Tinn-R,
see
http://www.nabble.com/weighted-quantiles-to19864562.html#a19865869
url:www.econ.uiuc.edu/~rogerRoger Koenker
email[EMAIL PROTECTED]Department of Economics
vox: 217-333-4558University of Illinois
fax: 217-244-6678Champ
Hello!
I am wondering if there is a function in R that returns quantiles of a
weighted sample, i.e., a set of values, each coming with a different
weight. The function quantile() does that only for the case when the
weights are all equal.
In other words, I am looking for a quantile function tha
Dea-R community.
I'd like to draw your attention to an issue I have recently
encountered while doing my current data analysis.
I've got an unexpected (to me) result from the command:
> augPred(lmList(my.object)),
'my.object' being a grouped data frame of class:
> class(my.object)
[1] "nfnGroup
On 10/8/2008 12:42 PM, Michael Friendly wrote:
Thanks, John
What you say about mixing rgl.* and *3d calls may be true, but that is
not my problem. After this occurred,
I tried many things, but reduced it to the smallest, most basic example
(in my original post), using only plot3d(), that
worke
Can you please try a 2.8.0 beta build? I have a suspicion as to what
might be going on, and it cannot happen there.
If my guess is correct,
nfile <- paste("diagnostic â vs a ", file.label, ".jpg", sep = "")
savePlot(path.expand(nfile), type="jpg")
may work for you in 2.7.2 (but as I said, I w
Thank you all for you suggestions. They are all helpful. However, I have
come to a more fundamental problem. Preparing my data to even make such a
graph. I thought I was ready. I will obviously need to find the n, mean,
and confidence interval for my data before I can plot them. for some of
these
Jacky -- Duncan has kindly allowed me to maintain SJava. A current
version is not readily available, but I will provide you with some help
off-list (and arrange for more public dissemination soon).
Martin
Jacky Huang wrote:
Dear duncan,
I'm writing to ask you for some help about compiling
Julia S. wrote:
> Hi there,
>
> thanks for your help. I did read Bates statement several times, and I am
> very glad and thankful that many statisticians spend much time on this. The
> problem is, as Dieter pointed it out, that many "end users" often have to
> use statistics without being able to f
On Wednesday 08 October 2008, Manuel Morales wrote:
> Another option is bargraph.CI or lineplot.CI from the package sciplot.
>
> See http://mutualism.williams.edu/sciplot for examples.
>
> On Tue, 2008-10-07 at 23:31 -0500, Michael Just wrote:
> > Hello,
> > I'd appreciate a suggestion on how to co
On 08-Oct-08 15:19:02, mentor_ wrote:
> Hi,
> I have a vector A with (200, 201, 202, 203, 204, ... 210) and
> a vector B with (201, 204, 209).
> Now I would like to get the position in vector A matches with
> the entries in vector B
> So what I want to have is the following result:
> [1] 2 5 10
Fi
Thanks, John
What you say about mixing rgl.* and *3d calls may be true, but that is
not my problem. After this occurred,
I tried many things, but reduced it to the smallest, most basic example
(in my original post), using only plot3d(), that
worked perfectly in both the CRAN and R-Forge version
Hello;
I'll put my real problem through a simple example:
I've got a main list:
> main.lst <- lst()
With a number of sublists:
> for(i in 1:1000){
main.lst[[i]] <- list()
main.lst[[i]]$first <- runif(1,0,1)
main.lst[[i]]$second <- runif(2,3,4)
}
If later on I need to split this list
A <- seq(200,210,1)
B <- c(201,204,209)
which(A %in% B)
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of mentor_
> Sent: Wednesday, October 08, 2008 11:19 AM
> To: r-help@r-project.org
> Subject: [R] Using grep
>
>
> Hi,
>
> I have a vector A wi
Here is a possible solution:
> A
[1] 200 201 202 203 204 205 206 207 208 209 210
> B
[1] 201 204 209
> which(!is.na(match(A,B)))
[1] 2 5 10
>
Hope this helps,
Sincerely,
Erin
On Wed, Oct 8, 2008 at 10:19 AM, mentor_ <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I have a vector A with (200, 201, 202
On Tue, Oct 7, 2008 at 11:31 PM, Michael Just <[EMAIL PROTECTED]> wrote:
> Hello,
> I'd appreciate a suggestion on how to construct plots (barplots?) that use
> means on the Y axis instead of density/count. I'd also like to use groups
> and plot error or confidence interval bars on these graphs. I
which(A %in% B)
-Christos
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of mentor_
> Sent: Wednesday, October 08, 2008 11:19 AM
> To: r-help@r-project.org
> Subject: [R] Using grep
>
>
> Hi,
>
> I have a vector A with (200, 201, 202, 203, 204, .
Dear duncan,
I'm writing to ask you for some help about compiling SJava.
I encounter some errors when I compiled SJava on Window XP:
Building JNI header files...
Extracting the classes from Environment.jar
/jdk1.3/bin/jar: not found
RForeignReference
After executing command "sh ./co
Another option is bargraph.CI or lineplot.CI from the package sciplot.
See http://mutualism.williams.edu/sciplot for examples.
On Tue, 2008-10-07 at 23:31 -0500, Michael Just wrote:
> Hello,
> I'd appreciate a suggestion on how to construct plots (barplots?) that use
> means on the Y axis instead
Hi,
I have a vector A with (200, 201, 202, 203, 204, ... 210) and a vector B
with (201, 204, 209).
Now I would like to get the position in vector A matches with the entries in
vector B
So what I want to have is the following result:
[1] 2 5 10
I tried the following:
grep(B, A)
grep(c(B), A)
A
Hi,
with the "space" parameter it is possible to change the gap / distance
between the bars, but is it also
possible to change the "space" after each 6th bar?
So for example you have bars from 1 to 6 then a large gap and then the next
six bars from 7 to 12
Thanks a lot!
--
View this message in
Hi there,
thanks for your help. I did read Bates statement several times, and I am
very glad and thankful that many statisticians spend much time on this. The
problem is, as Dieter pointed it out, that many "end users" often have to
use statistics without being able to fully understand the math
Dear Michael,
I haven't tried rgl.snapshot() in the development version of rgl, so I can't
comment on that, but I believe that these are two unrelated problems. I
think that the version of rgl on CRAN fails to display text when rgl.* and
*3d function calls are mixed, while this works in the develo
Hm.
Bert Gunter wrote:
>
> that even the most technical
> aspects of the discipline can be made manifest to anyone with half a brain
> and a stat 101 course under their belt.
>
>
I don't think this is something I can use in a rebuttal. The reviewer may be
offended and reviewers are people one
Antje yahoo.de> writes:
> I want to create some boxplots (as png) within an lapply method. To get
> nice gridlines behind the boxplot, I plotted it twice and therefore I
> set par(new=TRUE).
> This works nicely for the first plot but the second does plot on the
> first plot
> too and creates
Hi!
Have you looked at snow, snowfall, Rmpi, or rparallel, please?
Hope this helps,
Sincerely,
Erin
On Wed, Oct 8, 2008 at 10:14 AM, Chi Chan <[EMAIL PROTECTED]> wrote:
> Anyone using or has access to ParallelR? I was looking at the page and
> found nothing really useful!
>
> http://www.revoluti
dataToMerge=data.frame(yourtablename2$PROBE_ID2, yourtablename2$SEARCH_KEY2)
##Puts the two columns of interest in dataset 2 in a separate data frame.
mergedData=merge(yourtablename1,dataToMerge,by.x=SEARCH_KEY1,by.y=SEARCH_KEY
2,all.x=T,all.y=F)
##merges the first table with the data frame just c
Dear list,
I need some clues on this. I have two excel files and I basically want
to map one to the other one. Can you give me some hints how to do
it?
The first excel file, named as "Susan_probe.xls", there are two columns,
"PROBE_ID1" and "SEARCH_KEY1"
PROBE_ID1 SEARCH_KEY1 ILMN_30212 ILMN
Anyone using or has access to ParallelR? I was looking at the page and
found nothing really useful!
http://www.revolution-computing.com/sitegenius/topic.php?id=195
I want to see if I can run R on a cluster of workstation, and use
batch systems like Grid Engine or Xgrid:
http://gridengine.sunsour
Thank you Professor:
After reading in the file this is what I see:
> file.label
[1] "EXAMPLE 1 â vs a.xls"
charToRaw(file.label)
[1] 45 58 41 4d 50 4c 45 20 31 20 c3 a2 20 76 73 20 61 2e 78 6c 73
> Encoding(file.label)
[1] "UTF-8"
> Encoding(paste("diagnostic â vs a ", file.label, ".jpg", sep
*Summary*: The latest Windows binary version of rgl_081.708 from
R-Forge has some problem that
causes rgl.snapshot() to fail, at least on my system.
Thereafter, *all* rgl 3D graphics are rendered without any text labels.
The last problem remains even after (a) removing rgl and re-installing
fro
Hi all,
I am trying to run an autologistic model using the function errorsarlm from
spdep package.
**I built an XY matrix extracting the two colums from matriz**
coords1<-matriz[matriz$casos1==1, c(4,5)]
coords1<-as.matrix(coords1)
**I identify neighbours of region points**
nb20<-dnearneigh(
Hi everybody,
I want to create some boxplots (as png) within an lapply method. To get nice
gridlines behind the boxplot, I plotted it twice and therefore I set par(new=TRUE).
This works nicely for the first plot but the second does plot on the first plot
too and creates a mess...
How can I for
That also works without a hitch on my box, even in vanilla 2.7.2. What
exactly is in file.label as given by
charToRaw(file.label)
Encoding(file.label)
? It should be in UTF-8, and so should
paste("diagnostic â vs a ", file.label, ".jpg", sep = "")
It looks like the latter is not being treat
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