Actually I can afford for it. Think that Think
Jorge Ivan Velez wrote:
>
> Anything else?
>
>
> Jorge
>
>
> On Sun, Jun 1, 2008 at 5:30 PM, ensark <[EMAIL PROTECTED]> wrote:
>
>>
>> hý, I am preparing undergraduate thesis If you help me this would make
>> me
>> feel good.
>> First I nee
[EMAIL PROTECTED]:
> p0<- c(f=0.87, b=0.1, c=150)
> f<-p[1]; b<-p[2]; c<-p[3]
Do *not* redefine the meaning of the function c() to 150, or to p[3].
If you do, very few things in R will continue to work properly!
--
Karl Ove Hufthammer
__
R-help@r-pro
Hi,
I am drawing several plots and want to have italics in a main title;
this is easy with expression(). However, I want also to add a value to
it, say n_i, that depends on an ith plot. For this I am using paste().
An example: n_i = 10, 20, 30; I want to draw a plot for each i with
the title: "Rel
Hello everyone. I have an interest in fitting jump diffusion AR(p)
processes (which will likely form part of a Garch model). Does anyone
know of some R code that will allow this please, hopefully using max
likelihood (or similar) methods?
I'm currently using WinBUGS and RWinBUGS to utilise a B
Hello R help
I have been trying to use Rob Hyndman's monotonically increasing spline
function. But like another user or two seem have a problem with a
missing DLL (namely "spline_coef"). None of the previous help postings
seemed to have any solutions to this problem. As per a Ripley
suggestion
Anything else?
Jorge
On Sun, Jun 1, 2008 at 5:30 PM, ensark <[EMAIL PROTECTED]> wrote:
>
> hý, I am preparing undergraduate thesis If you help me this would make me
> feel good.
> First I need to analyze effect of Dow Jones Industrial average(DJIA)'s
> return on Istanbul Stock Exchange(ISE
would you like coffee with that?
From: [EMAIL PROTECTED] [EMAIL PROTECTED] On Behalf Of ensark [EMAIL PROTECTED]
Sent: Sunday, June 01, 2008 5:30 PM
To: r-help@r-project.org
Subject: [R] how to analyze time series structures?
hı, I am preparing undergrad
hı, I am preparing undergraduate thesis If you help me this would make me
feel good.
First I need to analyze effect of Dow Jones Industrial average(DJIA)'s
return on Istanbul Stock Exchange(ISE). I want to use Markov-Switching
Bayesian Vector Autoregression Models (MSBVAR) that is used to ex
try:
vol <- rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3)
time <- rep(c(2,4,8),each=7)
p.mated <- c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, NA, 0.68, 0.62, 0.64,
0.58, 0.53, 0.47, 0.24, 0.8, 0.79, 0.71, 0.56, 0.74, 0.8, 0.47)
eury <- data.frame(vol=vol, time=time, p.mated=p.mated)
eury <- na.omit(eury)
p0 <-
Here is a clean version. I did this with nls and it works (see below), but
I need to do it with optim. Keun-Hyung
# optim
vol<-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3)
time<-rep(c(2,4,8),each=7)
p.mated<-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, NA, 0.68, 0.62, 0.64, 0.58,
0.53, 0.47,
0.24, 0.8, 0.79,
On Sat, 31-May-2008 at 06:07PM -0400, Carl Witthoft wrote:
> Anyone know what's up w/ tolstoi.newcast.edu.au (home of the
> threaded R-help archives)? I've got a "can't connect" for several
> days now.
No luck here either, even with the correct spelling.
$ ping tolstoy.newcastle.edu.au
PING to
Hadley, In my application the leaf viewports will not overlap, but I guess that
would not necessarily be the case for all applications. In any event, do you
happen to know how to transform coordinates in the top-level viewport to
coordinates in another viewport in the tree? Thanks. -Ben
__
On 31.05.2008, at 00:11, Prof Brian Ripley wrote:
On Fri, 30 May 2008, Duncan Murdoch wrote:
But I think with Brian Ripley's work over the last while, R for
Windows actually handles utf-8 pretty well. (It might not guess
at that encoding, but if you tell it that's what you're using...)
Ye
ss <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> Hi list,
>
> If I have a matrix,
>
>> a<-read.table("a.txt",header=TRUE,row.names=1)
>> dim(a)
> [1] 4 3
>> a
>x y z
> a1 1 6 3
> a2 2 6 3
> a3 2 3 8
> a4 5 3 4
>>
>
> Can you suggest how to produce a plot like the one attached here
Ben,
What if the click occurs over multiple viewports?
Hadley
On Mon, Jun 2, 2008 at 6:50 AM, Wittner, Ben, Ph.D.
<[EMAIL PROTECTED]> wrote:
> Short form:
>
>How do I transform the output of grid.locator() (or
> grid.locator(unit='npc')) to the native (or npc) coordinates of a vi
Short form:
How do I transform the output of grid.locator() (or
grid.locator(unit='npc')) to the native (or npc) coordinates of a viewport other
than the top-level viewport?
Thanks in advance. -Ben
Long form:
I would like the user to be able to cl
Many thanks, Matthias! cat() did the job, exactly as wanted.
message() won't do, since sink() eother captures output
(type="output", the default) or captures messages
(type="message"), in which case it won't capture the ouput!
In any case, even if it captured both, I wouldn't want to
sin() all the
Dear Ted,
what about
cat("\n")
or
message("")
Best,
Matthias
(Ted Harding) wrote:
Hi Folks,
This must be easy but I've not managed to locate the solution!
Basically: I'm using sink() to save successively obtained
results, e.g. I construct a set of reg
Hi Folks,
This must be easy but I've not managed to locate the solution!
Basically: I'm using sink() to save successively obtained
results, e.g. I construct a set of regression coefficients
etc. with names rows and columne (I want to see the names
in the output) as an object (say "Object"), and th
Hi list,
If I have a matrix,
> a<-read.table("a.txt",header=TRUE,row.names=1)
> dim(a)
[1] 4 3
> a
x y z
a1 1 6 3
a2 2 6 3
a3 2 3 8
a4 5 3 4
>
Can you suggest how to produce a plot like the one attached here? Basically,
I want to plot each sample (each column) using the dots one by one and al
Thanks Gabor, I have updated that and it is now working fine
Gabor Grothendieck <[EMAIL PROTECTED]> wrote: Please upgrade to the latest
version of zoo. as.yearmon.factor
was only added to zoo in recent versions and its likely your date
column is a factor.
If that is not the problem then please
[EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
> Dear All, I suspect I'm becoming a bit anoying but... following the
> "question" about the low r2 vs signific regression (thru ANCOVA),
> the reviewer suggested (and I quote here):
>
> 'If you used RNA/DNA ratios as the dependent variable,
Please upgrade to the latest version of zoo. as.yearmon.factor
was only added to zoo in recent versions and its likely your date
column is a factor.
If that is not the problem then please provide the dput output as
requested.
On Sun, Jun 1, 2008 at 9:59 AM, Megh Dal <[EMAIL PROTECTED]> wrote:
>>
[EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]
uk:
>> I'm attempting to plot a cubic relationship between two variables
>> controlling for the effects of a third variable. In this short
>> example, I'm trying to use AGE to predict CORTEX while controlling
>> for the effects of TIV (total int
> packageDescription("zoo")$Version
[1] "1.1-1"
Gabor Grothendieck <[EMAIL PROTECTED]> wrote: You need to unambiguously specify
what your data
looks like. Please provide the dput output as previously
requested. Also what version of zoo are you using?
packageDescription("zoo")$Version
On Sun
Also here is an example showing it works with the assumed
format and zoo version:
> data1 <- structure(list(V1 = structure(c(6L, 2L, 4L, 3L, 5L, 1L), .Label =
> c("Apr-81",
+ "Dec-80", "Feb-81", "Jan-81", "Mar-81", "Nov-80"), class = "factor"),
+ V2 = c(NA, NA, NA, NA, NA, NA), V3 = c(1007.44
You need to unambiguously specify what your data
looks like. Please provide the dput output as previously
requested. Also what version of zoo are you using?
packageDescription("zoo")$Version
On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal <[EMAIL PROTECTED]> wrote:
> I got following:
>
>> z <- zoo(da
I got following:
> z <- zoo(data1[,3], as.yearmon(data1[,1], "%b-%y"))
> head(z)
Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006
1206.68 782.45 1187.00 1398.77 1883.23 1431.80
> z <- zoo(data1[,3], as.Date(as.yearmon(data1[,1], "%b-%y")))
> head(z)
0001-01-01 0002-01-01 0003-01-01
On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck
<[EMAIL PROTECTED]> wrote:
> On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal <[EMAIL PROTECTED]> wrote:
>> Hi all,
>>
>> I have following monthly time series :
>>
>>> head(data1)
>> V1 V2 V3
>> 1 Nov-80 NA 1007.44
>> 2 Dec-80 NA 982.05
>> 3 Jan
On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I have following monthly time series :
>
>> head(data1)
> V1 V2 V3
> 1 Nov-80 NA 1007.44
> 2 Dec-80 NA 982.05
> 3 Jan-81 NA 994.25
> 4 Feb-81 NA 996.31
> 5 Mar-81 NA 939.91
> 6 Apr-81 NA 923.32
If the
He creado un perfil en Facebook donde puedo publicar mis imágenes, vÃdeos y
eventos, y quiero agregarte como amigo/a para que puedas verlo. Primero,
necesitas registrarte en Facebook. Una vez registrado/a, puedes también crear
tu propio perfil.
Gracias,
Pau
Esta es la dirección:
http://ww
Hi all,
I have following monthly time series :
> head(data1)
V1 V2 V3
1 Nov-80 NA 1007.44
2 Dec-80 NA 982.05
3 Jan-81 NA 994.25
4 Feb-81 NA 996.31
5 Mar-81 NA 939.91
6 Apr-81 NA 923.32
Now I want to convert it to a 'zoo' object. I wrote following syntax :
ss = zoo(data1[,3], as.
gmail.com> writes:
>
> I saw a similar question but I still don't fully understand how to implement
> optim.
>
> > vol<-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3)
> > time<-rep(c(2,4,8),each=7)
> > p.mated<-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, "null", 0.68, 0.62, 0.64,
> 0.58, 0.53, 0.47,
> + 0.24
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