Please ask the maintainer. The 'udunits' R package seems to require its
libraries in particular places. Note that it is looking for
/usr/lib/libudunits.a, that is a static library in a 32-bit library
directory, whereas you most likely have /usr/lib64/libudunits.so or
/usr/lib64/libudunits.a
Why dont you use the rattle GUI for data selection ?
Regards,
Ajay
On Mon, May 12, 2008 at 6:24 AM, Roslina Zakaria <[EMAIL PROTECTED]> wrote:
> Hi R-expert,
> I try to eliminate 29 Feb but I got an error message below:
> feb_data1 <- Pooraka_data[Pooraka_data$Month=="2",]
> feb_28days <- feb_d
Dear list,
I want to insert a recorde into a SQLite table by dbGetQuery(), but
there is a problem when the value contains quotation mark.
> dd<-data.frame(txt=c("having both ' and \" in character.","OK"))
> library(RSQLite)
Loading required package: DBI
> con<-dbConnect(dbDriver("SQLite"),":memor
Hi Worik:
Is this what you want?
> Names <- letters[1:5];
> Dates<- 1:20;
> d<- data.frame(dates=Dates, a = vector(mode="numeric",
> length=length(Dates)));
> for(i in 2:5){d[,paste(sep="",Names[i])]<-with(d,a)}; d
dates a b c d e
1 1 0 0 0 0 0
2 2 0 0 0 0 0
3 3 0 0 0 0 0
4
Thanks. It is helpful.
Best
On Mon, May 12, 2008 at 4:34 AM, Paul Murrell <[EMAIL PROTECTED]> wrote:
> Hi
>
>
> ronggui wrote:
>> Thanks,Hadley.
>>
>> Another question is how can I know there is a grob path called
>> "xaxis::ticks"? Is there any easy way to figure out?
>
>
> grid.ls() ?
>
> Paul
Hi R Users,
I am new to running R on a Linux platform (I'm used to Windows) - I'm running R
2.7.0 on Ubuntu 7.10 (Gutsy) as sudo (without Emacs). My architecture is
Pentium D (x86_64).
I am having problems successsfully configuring the downloaded package 'udunits'.
When I execute
> install.p
What you are getting back in 'feb_no_29' is a data frame which can not be
used for indexing. Do 'str(feb_no_29)' and see what you set. What you
probably want to do is to use 'which' to find out which rows match the
criteria and then delete them:
feb_29 <- which((Pooraka_data$Month == "2") & (Poo
Hi R-expert,
I try to eliminate 29 Feb but I got an error message below:
feb_data1 <- Pooraka_data[Pooraka_data$Month=="2",]
feb_28days <- feb_data1 [feb_data1$Day=="28",]
feb_29days <- feb_data1 [feb_data1$Day=="29",]
## delete 29 Feb
feb_no_29 <- feb_data1 [-(feb_29days),]
feb_no_29 <- feb_data1
Two very good responses to this question, but I wonder, Is there some
more complete documentation on using this form of model and dataframe
construction? I've been using R for ~5 years now and wasn't aware of it.
Response 1: Insert a matrix as a column of the dataframe using I().
var<-1:1
On Mon, May 12, 2008 at 10:34:40AM +1200, Rolf Turner wrote:
>
> On 12/05/2008, at 9:45 AM, Andrew Robinson wrote:
>
> >On Sun, May 11, 2008 at 07:52:50PM +0100, Federico Calboli wrote:
> >>
> >>The main point of my question is, having a 3 way anova (or ancova, if
> >>you prefer), with *no* nesti
On 12/05/2008, at 11:37 AM, rostam shahname wrote:
mac os X
No, no, no!!! That's what ***you*** type (in R)! :-)
cheers,
Rolf
On Sun, May 11, 2008 at 8:24 PM, Rolf Turner
<[EMAIL PROTECTED]> wrote:
On 12/05/2008, at 11:17 AM, rostam sha
mac os X
On Sun, May 11, 2008 at 8:24 PM, Rolf Turner <[EMAIL PROTECTED]>
wrote:
>
> On 12/05/2008, at 11:17 AM, rostam shahname wrote:
>
> Hi R users,
>> I have a python script.
>> Assume that I would like to run this external python script when executing
>> a
>> R script or command line R.
>>
On 12/05/2008, at 11:17 AM, rostam shahname wrote:
Hi R users,
I have a python script.
Assume that I would like to run this external python script when
executing a
R script or command line R.
I don't know how to this using R code.
I really appreciate if you could help me.
Thanks for your hel
Hi R users,
I have a python script.
Assume that I would like to run this external python script when executing a
R script or command line R.
I don't know how to this using R code.
I really appreciate if you could help me.
Thanks for your help
Rostam
[[alternative HTML version deleted]]
_
Andrew
Have you tried:
dat2[!paste(dat2[,1], dat2[,2])%in%paste(dat1[,1], dat1[,2]),] ?
HTH
Peter Alspach
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Andrew McFadden
> Sent: Monday, 12 May 2008 9:40 a.m.
> To: r-help@r-project.org
>
On 12/05/2008, at 9:45 AM, Andrew Robinson wrote:
On Sun, May 11, 2008 at 07:52:50PM +0100, Federico Calboli wrote:
The main point of my question is, having a 3 way anova (or ancova, if
you prefer), with *no* nesting, 2 fixed effects and 1 random effect,
why is it so boneheaded difficult to s
Hi
ronggui wrote:
> Thanks,Hadley.
>
> Another question is how can I know there is a grob path called
> "xaxis::ticks"? Is there any easy way to figure out?
grid.ls() ?
Paul
> Thanks in advance.
>
> On Wed, May 7, 2008 at 10:06 PM, hadley wickham <[EMAIL PROTECTED]> wrote:
>> On Tue, May
On Sun, May 11, 2008 at 07:52:50PM +0100, Federico Calboli wrote:
>
> The main point of my question is, having a 3 way anova (or ancova, if
> you prefer), with *no* nesting, 2 fixed effects and 1 random effect,
> why is it so boneheaded difficult to specify a bog standard fully
> crossed mod
Hi R users
I am trying to find unmatched data from two dataframes. I would like to
find unmatched data based on several factors. For the following data:
dat1 <- data.frame(x = paste("A", 1:6, sep=""),
y = c("andy","bob","ciaran","dan", "eion",
"fred"
On Fri, May 02, 2008 at 07:35:37AM +0100, Prof Brian Ripley wrote:
> There is a *manual* on R Data Import/Export, not just an FAQ.
>
> This is the first request I have seen for .ods (whatever that is --
The most well-known application that uses this file format is the Calc
(Spreadsheet) part of
On 5/11/08, E C <[EMAIL PROTECTED]> wrote:
> Is there a way of positioning the color key in levelplot when the axes are on
> a categorical (rather than numerical) scale? I've put some sample code below.
> I need to add a secondary y axis to the right side of my plot but then the
> labels interfe
On 11-May-08 18:58:45, Myers, Brent wrote:
> There is a very useful and apparently fundamental feature of R
> (or of the package pls) which I don't understand.
>
> For datasets with many independent (X) variables such as chemometric
> datasets there is a convenient formula and dataframe constructi
Is there a way of positioning the color key in levelplot when the axes are on a
categorical (rather than numerical) scale? I've put some sample code below. I
need to add a secondary y axis to the right side of my plot but then the labels
interfere with the color key (which is currently on the ri
There is a very useful and apparently fundamental feature of R (or of
the package pls) which I don't understand.
For datasets with many independent (X) variables such as chemometric
datasets there is a convenient formula and dataframe construction that
allows one to access the entire X matrix with
On 10 May 2008, at 07:36, Kingsford Jones wrote:
Federico,
I think you'll be more likely to receive the type of response you're
looking for if you formulate your question more clearly. The
inclusion of "commented, minimal, self-contained, reproducible code"
(as is requested at the bottom of eve
Hello, I am interested in performing a stepwise regression using the robust
regression technique to estimate the models at each stage.
At the moment I am using the lm code and the stepAIC code to select the "best"
OLS model. This final model is then re-estimated using the rlm code.
I am hopin
Dear Jim,
The following codes maybe helps.
for (i in 1:length(dat1[,1])) {
for (j in 1:length(dat2[,1])) {
if (dat1[i,1] == dat2[j,1] & dat1[i,2] == dat2[j,2]) print (j)
}
}
time1<- as.Date(c("2006-01-03", "2006-05-03", "2006-05-04",
"2006-05-11", "2006-05-12", "2006-05-16", "2006
On May 11, 4:47 pm, "Douglas Bates" <[EMAIL PROTECTED]> wrote:
> Do you mean that you want to collapse similar rows into a single row
> and perhaps a count of the number of times that this row occurs?
Let me rephrase the problem by providing an example.
Input:
A =
[,1] [,2]
[1,]1
Dear Jim,
Maybe u want this,
> subset(dat2, time1 %in% dat2$v1 & time2 %in% dat2$v1)
v1 v2
2 2006-05-09 7065.0
3 2006-05-04 3622.5
5 2006-07-14 3532.5
7 2006-05-12 6480.0
8 2006-05-17 4612.5
15 2006-07-05 4837.5
16 2006-07-06 3352.5
18 2006-07-24 6772.5
20 2006-07-18 5625.0
Wa
Hello,
I'm having trouble installing rJava on R-2.6.1 / Suse10.3.
What could be wrong?
Regards,
Juan Pablo
This is the output of
> install.packages("rJava", dependencies=T)
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
probando la URL 'h
Gustave Lefou wrote:
Hello,
I still have my problem. I couldn't make Uwe Ligges's example work. I wonder
why :-(
The following doesn't work :
param.list=list(mu1=0,mu2=0,s1=3,s2=2,s3=2,s4=4)
plot(1:8,type="n")
text(8,3,adj=1,labels=substitute("with " * mu ==
bgroup("(",atop(mu1,mu2),")") *
Gustave Lefou wrote:
Thank to both of you.
I found an interesting document by Uwe Ligges in Rnews December 2002 (Vol
2/3)
The following seems encouraging
x=seq(1,180,by=1)
beta=10
eta=5
plot(x,log(x),type="p",xlab="x",ylab="h(x)",main=substitute("Failure rate "
* eta==myeta * "," * beta ,l
Here is one way to compare the entire rows between the data frames:
> x1 <- do.call(paste, dat1)
> x2 <- do.call(paste, dat2)
> dat1[x1 %in% x2,]
[1] v1 v2
<0 rows> (or 0-length row.names)
>
> x1
[1] "2006-01-03 7312.5" "2006-05-03 3352.5" "2006-05-04 4252.5" "2006-05-11
3825"
[5] "2006-05-12 27
It is giving you exactly what you are asking for. You asked first which of
dat1$v1 were in dat2$v; you got a TRUE on the second value (2006-05-03):
> dat1$v1 %in% dat2$v1
[1] FALSE TRUE TRUE FALSE TRUE FALSE TRUE TRUE FALSE FALSE FALSE FALSE
FALSE
You then asked for which of dat1$v2 were in
On Sun, 2008-05-11 at 09:58 -0400, Agus Susanto wrote:
> Is that possible to create superscript text on the graph legend, for example
> to put "cm2" (centimeter square) on the legend. Please show me how to do it.
> Thanks.
Here is one way, showing super and subscripts. The key bit is the
expressio
Hi, I'm hoping to find out whether R, or an R add-on, can generate a
particular type of graph. And, more basically, whether such a type of
graph even makes sense.
I'm looking for something resembling both a column chart and a bar
chart, where the basic visual "unit" is a solid rectangle of col
Not exactly. I need something to subset ONLY rows common to both
dataframes. In the provided example, dat1 and dat2 have no common rows
so I would expect:
[1] v1 v2
<0 rows> (or 0-length row.names)
But I can´t do it...
On Sun, 11 May 2008 10:07:25 -0400, "Zhuanshi He"
<[EMAIL PROTECTED]> said:
Is that possible to create superscript text on the graph legend, for example
to put "cm2" (centimeter square) on the legend. Please show me how to do it.
Thanks.
--
Agus Susanto
[[alternative HTML version deleted]]
__
R-help@r-project.org mail
Dear list:
I can now reproduce with a bit of my real data, the problem I asked for
your help yestarday:
time1<- as.Date(c("2006-01-03", "2006-05-03", "2006-05-04",
"2006-05-11", "2006-05-12", "2006-05-16", "2006-05-19", "2006-05-26",
"2006-09-15", "2006-10-30", "2006-11-08", "2006-11-14", "2006-1
On Sat, May 10, 2008 at 5:27 AM, amarkos <[EMAIL PROTECTED]> wrote:
> An indicator matrix is a binary matrix with orthogonal columns whose
> rows sum to 1. A row of this matrix could be [0 1 0 0]. My problem is
> to group the similar rows (profiles) so that to create a compact form
> of the matrix.
how do i calculate the p-value of trend test
Hello,
I have two data.
x<-c(1, 2, 1, 3, 2)
y<-c(3, 1, 2, 3, 5)
1. How do i create matrix from this two.
what i want is this
x y
1 1 3
2 2 1
3 1 2
4 3 3
5 2 5
2. what is the best way to use chisq.test to get the p.value
t
Here is how you can apply the mat function mentioned by Cassardi,
x<-c(1, 2, 1, 3, 2)
y<-c(3, 1, 2, 3, 5)
mat<-matrix(c(x,y),5,2) ##the first parameter gives the data vector
wich is filled columnwise in the matrix, then comes the row and column
dimensions)
colnames(mat)<-c("x","y")
yo
Hello there,
Prof Brian Ripley wrote:
On Sun, 11 May 2008, Esmail Bonakdarian wrote:
Stephan Kolassa wrote:
Have you tried successively removing/commenting parts of the script
before the sample() command until the problem goes away? That way you
should be able to pinpoint the offending scr
Hello,
I still have my problem. I couldn't make Uwe Ligges's example work. I wonder
why :-(
The following doesn't work :
param.list=list(mu1=0,mu2=0,s1=3,s2=2,s3=2,s4=4)
plot(1:8,type="n")
text(8,3,adj=1,labels=substitute("with " * mu ==
bgroup("(",atop(mu1,mu2),")") * "," * Sigma[x] ==
bgroup(
On Sun, 11 May 2008, Esmail Bonakdarian wrote:
Stephan Kolassa wrote:
Have you tried successively removing/commenting parts of the script before
the sample() command until the problem goes away? That way you should be
able to pinpoint the offending script command.
Hi,
This brings up a que
Stephan Kolassa wrote:
Have you tried successively removing/commenting parts of the script
before the sample() command until the problem goes away? That way you
should be able to pinpoint the offending script command.
Hi,
This brings up a question I have .. is there a way to do *block* comm
hoogeebear wrote:
Hi,
I created some bar charts. My first one is concerned with males, and my
second concerned with females.
Is there a way I can put the charts into one chart? There is 2 different
columns in each file. Here is my new file containing males and females:
gender,familar
Female,Yes
Dear R developers,
I'm trying to load files by means of Rserve. If the files have blanks in it
names or
german umlauts the loading failes(for example when using the rgdal lib with
readGDAL() ). In the R application without Rserve this works.
Is there a general encoding recipe or switch that this
Hello Luca.
Dr. Ottorino-Luca Pantani wrote:
>
> ...
>
> c(1803.02, 193.51, 3.47)
>
> Each solution is to be taken with 3 different pipettes (5000, 250 and 10
> µL Volume max) and each of those delivers volumes in steps of 50 µL, 5
> µL or 1µL, respectively
> Since the above values would
Dear list,
I've got a question concerning difference between loess and locpoly. I have to
use a plug-in method to chose a bandwith so I take locpoly method to fit a
curve.
My problem is:I know how to get predicted values in loess:
m=loess(y~x)
y_fitted=predict(m).
But how to get the sam
cirrus74 <[EMAIL PROTECTED]> [Sun, May 11, 2008 at 03:44:46AM CEST]:
>
> Is it possible to simulate the Monty Hall problem using R? If so, could
> someone please show me how? Thanks for any help rendered.
The kind of simulation, as any thinking about this seeingly paradoxical
situation, depends o
Dennis,
I assume that there is a set.seed() somewhere in your script, possibly
in something you source()d (hopefully not in anything library()d).
Have you tried successively removing/commenting parts of the script
before the sample() command until the problem goes away? That way you
should b
See ?cbind and ?matrix.
Gabor
On Sat, May 10, 2008 at 03:21:26PM -0700, Claire_6700 wrote:
>
> Hello,
>
> I have two data.
>
> x<-c(1, 2, 1, 3, 2)
> y<-c(3, 1, 2, 3, 5)
>
> How do i create matrix from this two.
>
> what i want is this
>
> x y
> 1 1 3
> 2 2 1
> 3 1 2
> 4 3
Hello,
I have two data.
x<-c(1, 2, 1, 3, 2)
y<-c(3, 1, 2, 3, 5)
How do i create matrix from this two.
what i want is this
x y
1 1 3
2 2 1
3 1 2
4 3 3
5 2 5
thanks
Claire
--
View this message in context:
http://www.nabble.com/Creating-Matrix-tp17168173p17168173.html
Sen
Is it possible to simulate the Monty Hall problem using R? If so, could
someone please show me how? Thanks for any help rendered.
--
View this message in context:
http://www.nabble.com/Monty-Hall-simulation-tp17169235p17169235.html
Sent from the R help mailing list archive at Nabble.com.
__
Hello,
I wanted to know which are the commands to perform a
Dunn test, and how must the data be entered.
Thanks,
Nicolás
Tarjeta de crédito Yahoo! de Banco Supervielle.
Solicitá tu nueva Tarjeta de crédito. De tu PC directo a tu casa.
www.tuprimeratarjeta.com.ar
Martin, Kate, Fernando, et al.
Be careful bootstrapping robust estimators. The trouble is that when resampling
is done with replacement, the outliers can be selected too many times which
would ruin the standard error estimates. Martin is right that bootstrapping
would be fine if there are not t
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