Hi List,
I trying an example from pumps{rbugs} with .Renviron in $HOME adjusted
for my box:
WINE="/usr/bin/wine",
BUGS="/usr/local/bin/WinBugs14/winbugs.exe"
data(pumps)
pumps.data <- list(t = pumps$t, x = pumps$x, N = nrow(pumps))
pumps.model <- file.path(.path.package("rbugs"), "bugs/model",
David,
tkanks für your comment, the code and the link.
You are right: "arbitrary" is a better word than "exact" pair matching.
I took the term "one-to-one exact matching" from the paper "MatchIt:
Nonparametric Preprocessing for Parametric Causal Inference" (p. 6):
http://gking.harvard.edu/matchit
kedar nadkarni gmail.com> writes:
> I have been trying to obtain confidence intervals for the fit after having
> used lmer by using intervals(), but this does not work. intervals() is
> associated with lme but not with lmer(). What is the equivalent for
> intervals() in lmer()?
ci in Gregory
Alex Reynolds u.washington.edu> writes:
> Is there a way to modify the choice of notch size [1] in R's boxplot
> routine from outlining a 5% significance region, to say 1% or lower?
Not directly from boxplot, because it is hardwired to indirectly call fivenum,
not quantile.
Check bxp instea
Alex Reynolds wrote:
> Is there a way to modify the choice of notch size [1] in R's boxplot
> routine from outlining a 5% significance region, to say 1% or lower?
>
Not easily. If you look inside boxplots.stats you'll find the hardcoded
constant 1.58, and the documentation has the following t
On Sun, 20 Apr 2008, Marko Milicic wrote:
> Dear R helpers,
>
> I'm trying to build logistic regression model large dataset 360 factors and
> 850 observations. All 360 factors are known to be good predictors of outcome
> variable but I have to find best model with maximum 10 factors. I tried to
>
Thank´s a lot, Patrick!
That´s what I was looking for...
Zitat von Patrick Connolly <[EMAIL PROTECTED]>:
> On Wed, 16-Apr-2008 at 11:58AM +0200, Udo wrote:
>
>
> |> I only "need" line 1, 6 and 9. To show this,
> |> I added "needed" by hand.
> |>
> |>age school out1 out2 needed
> |> 1
Hi
there is also a direct copy option
In Excel select a portion of data you want to copy, preferably with header
and press Ctrl-C
Open R
issue
read.delim("clipboard")
For inverse transfer see
?write
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 20.04.2008 17:51:26:
>
> Than
Hello!
> Dear Esmail,
>
> you really have to have a look at some introduction to R (e.g.
> http://cran.r-project.org/doc/manuals/R-intro.pdf), but see the "Manual"
> section in R website (http://www.r-project.org/). That would answer many
> of your questions.
point well taken, I am a bit
Hello folks,
I am wondering how to do survival analysis with time-related IVs in R. For
example,
> > If we have time-related variables, such as the Overall Condition of
1990, 1991 etc., how can we include these variables in coxph model?
> >
> > If we can not use coxph model, do we need
Prof Brian Ripley wrote:
> On Sun, 20 Apr 2008, Gad Abraham wrote:
>
>> Hi,
>>
>> Say x.train is a matrix of covariates that I want to do PCA on, so I can
>> do regression on its principal components, and x.test is a test set of
>> the same covariates on which I want to evaluate the regression fit
Is there a way to modify the choice of notch size [1] in R's boxplot
routine from outlining a 5% significance region, to say 1% or lower?
Thanks,
Alex
[1] McGill, Tukey, and Larsen. "Variations of Box Plots", The American
Statistician, Vol. 32, No. 1, 12-16.
_
Dear All,
I have a list of models(1000) which have variable scores from 20 different
method. I would like to rank models using consensus approach based on high
scores from different methods.Is there any function available in R for this
purpose? I will appreciate any pointers in this regard.
jinjin wrote:
>
> I am trying to solve the integration equation, for different values of K
> from 4 to 25, the integration is with respect to u,
> Here is the equation:gamma(k/2) / ( sqrt(k-1)*gamma((k-1)/2) ) *
> integrate(f= (1+u^2/k-1)^(-k/2), lower=0, upper= sqrt(a^2*k/(k+1-a^2)) ) =
>
Dear R helpers,
I'm trying to build logistic regression model large dataset 360 factors and
850 observations. All 360 factors are known to be good predictors of outcome
variable but I have to find best model with maximum 10 factors. I tried to
fit full model and use stepAIC function to get best mo
Prof Brian Ripley writes:
> I realize I didn't give a solution:
>
> scan(con, "", sep="\n")
>
Thanks for this (and for correcting the help page); this works. I
also found a workaround using read.table which also allows gzfile
connections with an incomplete last line.
Stephen
_
I have created a lattice bwplot that suffers from axis label
overplotting. The box plot contains grid lines, and I thought that
only plotting the labels for corresponding vertical grid lines would
not only cure the overplotting but also be more aesthetically
pleasing. Unfortunately hours of porin
Gabor Csardi <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> Hmm, my understanding is different,
>
> m <- matrix(sample(10*10), ncol=10)
> m2 <- rbind( m[1:5,], 1:10, m[6:10,] )
> m3 <- cbind( m[,1:8], 1:10, m[,9:10] )
I read the question the same way and, in response to the part of the
On 20/04/2008 3:04 PM, Ronaldo Reis Junior wrote:
> Em Dom 20 Abr 2008, Duncan Murdoch escreveu:
>> On 20/04/2008 12:32 PM, Ronaldo Reis Junior wrote:
>>> Em Dom 20 Abr 2008, Duncan Murdoch escreveu:
On 20/04/2008 9:40 AM, Ronaldo Reis Junior wrote:
> Hi all,
>
> I have a problem w
I realize I didn't give a solution:
scan(con, "", sep="\n")
should do it.
On Sun, 20 Apr 2008, Prof Brian Ripley wrote:
> On Sun, 20 Apr 2008, Stephen Eglen wrote:
>
>> Hi,
>>
>> I have some text files that do not have trailing \n on the last
>> (incomplete) line; how do I read in the last lin
Hi all,
I have been trying to obtain confidence intervals for the fit after having
used lmer by using intervals(), but this does not work. intervals() is
associated with lme but not with lmer(). What is the equivalent for
intervals() in lmer()? I could not get this information from the
documentat
On Sun, 20 Apr 2008, Stephen Eglen wrote:
> Hi,
>
> I have some text files that do not have trailing \n on the last
> (incomplete) line; how do I read in the last line?
>
> e.g. here is a test case: [linux + R version 2.6.1 (2007-11-26) ]
>
>
> z <- gzfile("short.gz", open="w")
> cat("7\n5\n3", fi
Hi,
I have some text files that do not have trailing \n on the last
(incomplete) line; how do I read in the last line?
e.g. here is a test case: [linux + R version 2.6.1 (2007-11-26) ]
z <- gzfile("short.gz", open="w")
cat("7\n5\n3", file=z)
close(z)
z <- gzfile('short.gz')
readLines(z)
[1] "
On 20/04/2008 12:32 PM, Ronaldo Reis Junior wrote:
> Em Dom 20 Abr 2008, Duncan Murdoch escreveu:
>> On 20/04/2008 9:40 AM, Ronaldo Reis Junior wrote:
>>> Hi all,
>>>
>>> I have a problem with an object inside a formula in a function that I
>>> make.
>>>
>>> I create an object named qvartemp. This
Em Dom 20 Abr 2008, Duncan Murdoch escreveu:
> On 20/04/2008 9:40 AM, Ronaldo Reis Junior wrote:
> > Hi all,
> >
> > I have a problem with an object inside a formula in a function that I
> > make.
> >
> > I create an object named qvartemp. This object is OK, look the levels:
> >> print(levels(qvart
Dear Esmail,
you really have to have a look at some introduction to R (e.g.
http://cran.r-project.org/doc/manuals/R-intro.pdf), but see the "Manual"
section in R website (http://www.r-project.org/). That would answer many
of your questions.
>Hello all,
>
>I am trying to implement a simple Gene
On Sun, 20 Apr 2008, Gad Abraham wrote:
> Hi,
>
> Say x.train is a matrix of covariates that I want to do PCA on, so I can
> do regression on its principal components, and x.test is a test set of
> the same covariates on which I want to evaluate the regression fit. I
> would like the covariates to
Thank you Erich for you information, I will continue investigating about as
read data from excel.
Erich Neuwirth wrote:
>
> To transfer data from Excel to R you have a least 3 options.
> RODBC is platform-independent. You can use it to read Excel files
> on any platform where you have an ODBC dr
On 20/04/2008 9:40 AM, Ronaldo Reis Junior wrote:
> Hi all,
>
> I have a problem with an object inside a formula in a function that I make.
>
> I create an object named qvartemp. This object is OK, look the levels:
>
>> print(levels(qvartemp))
> [1] "baixomedio" "alto"
>
> Now I create a new ob
Jim, Thanks for the tip, this did the trick. I knew it would be simple,
too much documentation, too little time!
-Original Message-
From: Jim Lemon [mailto:[EMAIL PROTECTED]
Sent: Sunday, April 20, 2008 5:20 AM
To: Beck, Kenneth (STP)
Cc: r-help@r-project.org
Subject: Re: [R] Legend Clip
Em Dom 20 Abr 2008, Ronaldo Reis Junior escreveu:
> Hi all,
>
> I have a problem with an object inside a formula in a function that I make.
>
> I create an object named qvartemp. This object is OK, look the levels:
> > print(levels(qvartemp))
>
> [1] "baixomedio" "alto"
>
> Now I create a new objec
Hello all,
I am trying to implement a simple Genetic Algorithm. I am doing this
in R since I want access to the statistical functions (eg lm) it
provides.
I'm not new to programming, or GAs, but I am totally new to R (the
package and the language), and I am hoping someone could help with
these qu
Hmm, my understanding is different,
m <- matrix(sample(10*10), ncol=10)
m2 <- rbind( m[1:5,], 1:10, m[6:10,] )
m3 <- cbind( m[,1:8], 1:10, m[,9:10] )
G.
On Sun, Apr 20, 2008 at 10:21:47AM -0300, Henrique Dallazuanna wrote:
> If I understand:
>
> m <- matrix(sample(10*10), ncol=10)
> m[5:6, 8:9]
Hi all,
I have a problem with an object inside a formula in a function that I make.
I create an object named qvartemp. This object is OK, look the levels:
> print(levels(qvartemp))
[1] "baixomedio" "alto"
Now I create a new object with a new formula:
> new.form <- as.formula(gsub(qvar,"qvarte
If I understand:
m <- matrix(sample(10*10), ncol=10)
m[5:6, 8:9] <- 1:4
On 4/18/08, Ng Stanley <[EMAIL PROTECTED]> wrote:
> Hi,
>
> Is there any functions to insert a vector or matrix into an existing matrix
> say between row 5 and 6 or column 8 and 9, without creating a temporary
> matrix ?
>
Joe Trubisz wrote:
> Hi...
>
> In Stata, there is the ability to display scatter plots with data
> points at the same (x,y)
> location, using the 'jitter' command of the twoway scatter stata
> command.
>
> Anyone know of a way that I can do the equivalent thing in R?
>
> For non-Stata reader
Beck, Kenneth (STP) wrote:
> ...
> legend(0.5,0.5, legend = c("CPX","Home"), bty="n",
> fill=c("blue","red"),lwd=1, cex=1, xjust=0.5, yjust=0.4);
>
Hi Kenneth,
Try this:
par(xpd=TRUE)
legend(0.5,0.5, legend = c("CPX","Home"), bty="n",
fill=c("blue","red"),lwd=1, cex=1, xjust=0.5, yjust=0.4);
par
On 20/04/2008 12:33 AM, Mike Ryckman wrote:
> Hello everyone,
>
> I know I can save a snapshot an rgl device, but currently it only appears to
> do png format. Is there some way of exporting a high-quality picture more
> fit for publication?
There's also rgl.postscript. It uses the gl2ps libra
Dear list members;
Does anyone know if there is an R package that can perform PCA or PLS
regression accounting for serial correlation (of the samples)?
Thanks for any hint
Steve
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r
To transfer data from Excel to R you have a least 3 options.
RODBC is platform-independent. You can use it to read Excel files
on any platform where you have an ODBC driver for Excel installed.
xlsReadWrite is available only on Windows. It has a function read.xls
which reads data from Excel worksh
leaps or regsubsets in the leaps package does subset regression which
seems to be what you're looking for.
hth, Ingmar
On Apr 19, 2008, at 11:51 PM, Computer- programmer wrote:
>
> Dear R helpers,
>I'm trying to fit a model for prediction, but I have 18
> variables to choose from. So, my
41 matches
Mail list logo
