I have previously sent a same email to [EMAIL PROTECTED], however
I am not sure if the mailing address has been changed to this one. If the
duplicated messages are received twice, I am sorry for that and please
delete one of them.
Dear R helper:
When I was trying to install the fCalendar packag
Dear R helper:
When I was trying to install the fCalendar package, R report the
following error and then my installation failed:
* Installing *source* package 'fCalendar' ...
** R
** inst
** preparing package for lazy loading
Loading required package: MASS
Loading required package: fEcofin
Loadin
On Sat, Mar 22, 2008 at 9:58 PM, jim holtman <[EMAIL PROTECTED]> wrote:
> Is this close to what you want?
>
> > spread <- function(x, mindiff=0.5){
> + unique(as.integer(x / mindiff) * mindiff)
> + }
>
> >
> > x <- c(1,2,seq(2.1,2.3,0.1),3,4)
> > x
> [1] 1.0 2.0 2.1 2.2 2.3 3.0 4.0
> > s
Hello,
I'm trying to built a model for a time-series analysis with an periodic
term for seasonality.
I've tried both harmonic (package spatstat) and periodicSpline (package
splines). The former don't allow a periodic constraint (or it does?),
while I've not been able to use the latter within a da
help.search("circle")
should point you to grid.circle in the grid package, at least in my
R version 2.6.1 (grid package version 2.6.1).
On Sun, Mar 23, 2008 at 8:44 AM, Gabor Grothendieck
<[EMAIL PROTECTED]> wrote:
> Look at draw.circle and draw.arc in the plotrix package.
>
> On Sat, Mar 22, 2
Is this close to what you want?
> spread <- function(x, mindiff=0.5){
+ unique(as.integer(x / mindiff) * mindiff)
+ }
>
> x <- c(1,2,seq(2.1,2.3,0.1),3,4)
> x
[1] 1.0 2.0 2.1 2.2 2.3 3.0 4.0
> spread(x)
[1] 1 2 3 4
>
> spread(x,.2)
[1] 1.0 2.0 2.2 3.0 4.0
>
On Sat, Mar 22, 2008 at 8:03 PM, L
There are 7 rows since this is probably a data frame and each column
in a dataframe (or a matrix in this case) all have the same number of
rows. I think what you want is to 'sum' the number of times a
condition is met; this might come closer to what you were expecting:
sum(weekly$a != 0)
On Sat,
I am creating a timeline plot, but running into a problem in positions
where the values to plot are too close together to print the text
without overlap. The simplest way I can think of to solve this
(although there may be other ways?) is to create a new numeric vector
whose values are as close as
Hi
I've used Dotplot from Hmisc to draw a dotplot with error bars, where each row
of the dotplot has two points. Now I'd like for the error bars to have caps on
the end so I can see how much they overlap, but I can't figure out how to
produce them.
This draws the plot I want, but doesn't add ca
Hi all:
Can someone help me count the
number of rows with values in
colum "a" only. assume the name
of my dataframe is "weekly"
I was trying
i<- nrows(weekly$a)
i
but returns 7 when it should
be 4. Thanks
a b c d
27.000
27.000
1.569 0.013
Look at draw.circle and draw.arc in the plotrix package.
On Sat, Mar 22, 2008 at 5:40 PM, ermimi <[EMAIL PROTECTED]> wrote:
>
> Hello!!!
>
> I would want to draw a circle but I don´t want use the function symbol(..).
> Do anybody know other function that allow me draw a circle?
> Thank you very mu
Hello,
For a few large set of points, whenever I use a "CI" constraint in the qss
term, I get the following error message:
Warning message:
In rq.fit.sfnc(x, y, tau = tau, ...) :
tiny diagonals replaced with Inf when calling blkfct
Without any constraint, these sets work well. Does anyone kn
Hello!!!
I would want to draw a circle but I don´t want use the function symbol(..).
Do anybody know other function that allow me draw a circle?
Thank you very much,
Greetings Luismi
--
View this message in context:
http://www.nabble.com/Draw-Circles-tp16227640p16227640.html
Sent from the R he
Thank you, Professor Ripley!
LazyLoad:FALSE in my DESCRIPTION file was the charm!
(It took a bit of looking to determine the correct syntax. A search for
"lazyloading" in "Writing R Extensions" was a red herring, but a search on
CRAN suggesting "lazy loading" - obvious in hindsight, of course
"Sergey Goriatchev" <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> I have the code for the bivariate Gaussian copula. It is written
> with for-loops, it works, but I wonder if there is a way to
> vectorize the function.
> I don't see how outer() can be used in this case, but maybe one can
I don't quite understand what you doing but have you
looked at ?names ?
x1 <- 3
x2 <- 5
y <- -34.5
mylist <- list(x1,x2,y)
mynames <- c("First Trade Position", "Second Trade
Position", "P&L")
names(mylist) <- mynames
mylist
--- Fernando Saldanha <[EMAIL PROTECTED]> wrote:
> I wanted to cr
I wanted to create a list with the names of variables and their
values. So I wrote the following function.
add.to.list.names.vars.1 <- function(lnv, vnv) {
i <- 1
while (i < length(vnv)) {
z <- as.character(eval(substitute(quote(vnv[i+1])))[[2]][[i + 2]])
lnv[[vnv[i]]] <- list(Name = z
shuyan wu wrote:
> Hi,
> After I installed R in my computer, I have loaded package Faraway,
You probably mean package "faraway", but that should not be related to
the following problem.
> but when I want to plot, it will show errors like below:
>
> *> x<-c(1,2)
>> y<-c(3,4)
>> plot(x,y)
>
Hi, Greg:
1. I did the integration in Excel for four reasons: First, it's
easier (even for me) to see what's happening and debug for something
that simple. Second, my audience were people who were probably not R
literate, and they could likely understand and use the Excel file easier
Why do the integration in Excel instead of using the integrate function in R?
The R function will allow integration from -Inf to Inf.
What was the correction to the formula? The last one you showed looked like
the difference between the average min and average max, but did not take into
acc
Hi,
After I installed R in my computer, I have loaded package Faraway, but
when I want to plot, it will show errors like below:
*> x<-c(1,2)
> y<-c(3,4)
> plot(x,y)
Error in windows() : unable to start device devWindows*
I don't know why, please help me.
Shuyan
[[alternative HTML ver
> sweep( rawdata, 2, sens, '/' )
hope this helps,
From: [EMAIL PROTECTED] on behalf of Tribo Laboy
Sent: Sat 3/22/2008 8:21 AM
To: r-help@r-project.org
Subject: [R] More elegant multiplication or division of a data frame with
avector
Hello,
I am importin
Not sure if these are any better but here are a few alternatives:
rawdata / rep(sens, each = nrow(rawdata))
as.data.frame(mapply("/", rawdata, sens))
as.data.frame(as.matrix(rawdata) %*% diag(1/sens))
On Sat, Mar 22, 2008 at 10:21 AM, Tribo Laboy <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I am imp
Eik Vettorazzi wrote:
> But usually weeks start with a Monday. So what should happen when new
> year isn't on a Monday? format(days, "%W") puts the first Monday of the
> year in the first week, which makes sense.
>
>
No it doesn't. Well, it does, but it will only match our planning
calendars
Hi Thomas,
You may want to check out the quantmod package. There is a whole
suite of charting functionality now included.
You will need to change the 'Last' colname to Close, but other than
that your data should work. If you download the most recent build or
svn snapshot from http://r-forge.r-p
Hello,
I am importing some raw voltage multichannel measurements into an R
data frame. I need to scale each column with the respective
sensitivity for that channel. I figured how to do it, but I am curious
if there isn't a more elegant way.
Now I start with something like this:
rawdata <- data.f
Is this what you want?
> DAT
siteobsfrc
1A 1.2745106 -1.6899502
2B 1.4394225 0.4167296
3A -0.1087532 0.7710872
4B -0.6319814 -0.2177236
5A -0.4208416 0.5099765
> (z <- by(DAT, list(DAT$site), function(x) mean(x$obs - x$frc)))
: A
[1] 0.3846007
---
I have the code for the bivariate Gaussian copula. It is written with
for-loops, it works, but I wonder if there is a way to vectorize the
function.
I don't see how outer() can be used in this case, but maybe one can
use mapply() or Vectorize() in some way? Could anyone help me, please?
## Density
Try this:
Lines <- '"Date (GMT)" "Open" "High" "Low" "Last"
17-03-2008 00:00:00 1,5764 1,5766 1,5747 1,5750
17-03-2008 00:05:00 1,5749 1,5750 1,5741 1,5744
17-03-2008 00:10:00 1,5745 1,5762 1,5741 1,5749'
DF <- read.delim2(textConnection(Lines))
library(quantmod)
z <- re
I want to create a open/high/low/last plot of intraday data.
I try to use the function plotOHLC from the tsteries package. I create
my own multiple time series and then try to plot it.
raw Data Format (file eurusd2.csv):
"Date (GMT)""Open" "High" "Low" "Last"
17-03-2008 00:00:00 1,5764
Dear R-Help List,
I'm trying to simulate data from a conditional distribution, and
haven't been able to modify my existing code to do so. I searched
the archives, but didn't find any previous post that matched my
question.
n=1
pop = data.frame(W1 = rbinom(n, 1, .2),
W2 = runif(n, min
Now, I wonder who Duncan meant by
'one person on the list who can diagnose the problem'
?
Hint: small packages are not selected for lazyloading, so do your example
with lazy loading set in the DESCRIPTION file.
If I do that, the example runs in R-devel but not in 2.6.2. It is
a locale is
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