use a factor as col argument?
Thanks for an answer.
Regards,
Christoph Buser
------
Christoph Buser <[EMAIL PROTECTED]>
Seminar fuer Statistik, LEO C13
ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND
phone:
Dear Prof. Ripley
Thank you for your reply and for changing the function in
R-devel.
I've intended to ask my question in way 2) but I probably have
chosen a ambiguous formulation. :-)
Regards
Christoph Buser
--
Christoph
; target "numeric"
> defined "numeric"
>
## Shows that for the argument "name" printit is used. For the argument
## "printit" name is used
test1(pi)
> .local(object = object, name = printit, printit = name)
Best regards,
Christoph Buser
n
integer. I am happy with this change, but:
Is it desirable to change apply so that it does not return a
character matrix in the example above or include a warning for
such a case?
Thank you very much for an answer.
Regards,
Christoph Buser
----
unlist() or array().
But in the end I am not sure if an integer matrix is better than
a character matrix or a factor matrix. I am not sure what output
is best if one uses as.factor in apply.
Regards,
Christoph
------
Christoph Buser &l