[Rd] is.Date function question

Why is there no is.Date function in R? I am running 2.1.1 does it exist in newer version? If there is a reasoning behind the lack of a is.Date function what is it? Thanks Charles -- Charles Dupont Computer System Analyst School of Medicine Phone: (615) 936-6510 Department of

[Rd] fix for a major format.pval limitation

rmat.pval' a '...' argument that would get passed to all the 'format' function calls in 'format.pval'. I have attached a patch that does this. This patch is against svn r-release-branch and will also apply to r-devel. Charles Dupont -- Charles Dupont Comp

[Rd] Patch for format.pval limitation in format.R

val' a '...' argument that would get passed to all the 'format' function calls in 'format.pval'. I have attached a patch that does this. This patch is against svn r-release-branch, but it also works with r-devel. Charles Dupont -- Charles Dupont Computer Sys

[Rd] wishlist -- Fix for major format.pval limitation (PR#9574)

Full_Name: Charles Dupont Version: 2.4.1 OS: linux 2.6.18 Submission from: (NULL) (160.129.129.136) 'format.pval' has a major limitation in its implementation. For example suppose a person had a vector like 'a' and the error being ±0.001. > a <- c(0.1,

Re: [Rd] wishlist -- Fix for major format.pval limitation (PR#9574)

007 1:40 PM, Gabor Grothendieck wrote: > >> > On 3/20/07, Duncan Murdoch <[EMAIL PROTECTED]> wrote: > >> >> On 3/20/2007 12:44 PM, Gabor Grothendieck wrote: > >> >> > On 3/20/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: >

Re: [Rd] describe function in package Hmisc and function format.dates in chron (PR#13087)

) Warning message: package 'chron' was built under R version 2.7.2 describe(prostate) Error in formatDateTime(dd, atx, !timeUsed) : could not find function "format.dates" __ R-devel@r-project.org mailing

[Rd] possible bug: NULL equality in lists.

27;cat' [1] FALSE FALSE FALSE This is consistent for every example of NULL's in a list that I can think of. Is this a bug or undocumented correct behavior? Here is my version output platform i486-pc-linux-gnu arch i486 os linux-gnu system i486, linux-gnu status major2 mi

Re: [Rd] possible bug: NULL equality in lists.

Uwe Ligges wrote: > Seth Falcon wrote: > > >>Uwe Ligges <[EMAIL PROTECTED]> writes: >> >> >> >>>Charles Dupont wrote: >>> >>> >>> >>>>I was messing around with R and I found an example R behaving oddly: &

Re: [Rd] Expanding partial names

Duncan Murdoch wrote: > I'm writing wrappers for some functions that change some of the default > arguments. I'd rather not list all of the arguments for the low level > functions because there are about a dozen wrapper functions, and about > 20 arguments to lowlevel. Instead I'm trying someth

Re: [Rd] Expanding partial names

Duncan Murdoch wrote: > Okay, here's my effort based on Deepayan's and Charles' ideas. The > newArgs function is not what I'd call transparent, but I like the way > the wrapper looks. > > > newArgs <- function(..., Params) { > + f <- function(...) list(...) > + formals(f) <- c(Params, form

[Rd] strsplit does not return correct value when spliting "" (PR#8777)

Full_Name: Charles Dupont Version: 2.2.0 OS: linux Submission from: (NULL) (160.129.129.136) when strsplit("", " ") returns character(0) where as strsplit("a", " ") returns "a". these return values

Re: [Rd] (PR#8777) strsplit does [not] return correct value when spliting ""

> > What rule are you using, and where did you find it in the R documentation? > > In fact > >> strsplit("", " ") > > [[1]] > character(0) > > which is not as you stated. This is a feature, as it distinct from > >> strsplit(" "

[Rd] Infinite Loop when installing a package from source (PR#9258)

Full_Name: Charles Dupont Version: Version 2.3.1 OS: linux Submission from: (NULL) (160.129.129.136) I think that this is infinite. I let it run for 30 minutes. During which it consumed 98% of my memory (1Gb) and steadily helled 90-99% of CPU. Steps to reproduce problem 1. get a source

[Rd] Why does not the command 'length(a <- 1:5) <- 4' not work?

4 : could not find function "<-<-" I would assume that 'length(a <- 1:5) <- 4' should work because 'length(a <- 1:5)' does work. Thank you for your help. Charles Dupont -- Charles Dupont Computer System Analyst