I am running chi-square test of goodness of fit, the observation data was
well groupped to observation freq. I assume the data obey the normal
distribution N(μ σ^2), while μ and σ^2 are unknown. So I use their
estimation. Consequently, I calculated out the probabilities and input in
vector p
>x<-c
Hello @r-devel,
From what I read in the following thread:
https://stat.ethz.ch/pipermail/r-package-devel/2023q4/010197.html
The major reason to limit paths lengths in R packages is to help
support MS Windows 260-chars paths lengths limit (pre-W10).
However, the official document
On 9/17/24 12:28, Iago Bonnici via R-devel wrote:
Hello @r-devel,
From what I read in the following thread:
https://stat.ethz.ch/pipermail/r-package-devel/2023q4/010197.html
The major reason to limit paths lengths in R packages is to help
support MS Windows 260-chars paths lengths
> Gabor Grothendieck
> on Mon, 16 Sep 2024 11:21:55 -0400 writes:
> Suppose we have `dat` shown below and we want to find the the `y` value
> corresponding to the last value in `x` equal to the corresponding
component
> of `seek` and we wish to return an output the same l
The other problem in this example is setting NA's.
replace(x, x == 0, NA)
requires two instances of x making it not very pipe friendly. In
dplyr there is na_if
to address that problem and base R might have something that addresses this
so we don't have to define our own zero2na as the base of
