Re: [Rd] pnorm

2008-02-08 Thread jing hua zhao
Hi, thanks to all for the helpful information. In fact our colleague is indeed keen to check for the difference. More importantly, I was in too much a haste to drop the message as I now recalled we got around in a similar way in Stata and SAS for a more extreme case before. JH > Date: Thu, 7

Re: [Rd] xspline(..., draw=FALSE) fails if there is no open device (PR#10727)

2008-02-08 Thread Peter Dalgaard
[EMAIL PROTECTED] wrote: > Full_Name: Jari Oksanen > Version: 2.6.2 RC (2008-02-07 r44369) > OS: Linux > Submission from: (NULL) (130.231.102.145) > > > Even if function xspline() is called with argument draw=FALSE, it requires a > graphics device (that it won't use since it was draw=FALSE). I run

Re: [Rd] xspline(..., draw=FALSE) fails if there is no open device (PR#10728)

2008-02-08 Thread p . dalgaard
[EMAIL PROTECTED] wrote: > Full_Name: Jari Oksanen > Version: 2.6.2 RC (2008-02-07 r44369) > OS: Linux > Submission from: (NULL) (130.231.102.145) > > > Even if function xspline() is called with argument draw=3DFALSE, it req= uires a > graphics device (that it won't use since it was draw=3DFALSE).

[Rd] xspline(..., draw=FALSE) fails if there is no open device (PR#10727)

2008-02-08 Thread jari . oksanen
Full_Name: Jari Oksanen Version: 2.6.2 RC (2008-02-07 r44369) OS: Linux Submission from: (NULL) (130.231.102.145) Even if function xspline() is called with argument draw=FALSE, it requires a graphics device (that it won't use since it was draw=FALSE). I run into this because I intended to use xs

[Rd] bad variable names when printing a data frame containing a matrix (PR#10730)

2008-02-08 Thread timh
library(glmpath) data(heart.data) # heart.data is a list, $y a vector, $x a matrix data <- data.frame(x=I(heart.data$x), y = heart.data$y) > data[1:2,] x.1 x.2 x.3 x.4 x.5 x.6 x.7 x.8 x.9 y 1 16012 5.73 23.11 149 25.3 97.252 1 2 144 0.01 4.41 28.61 0

[Rd] lm with factors for which only one level occurs

2008-02-08 Thread Gabor Grothendieck
Consider the following: > lm(conc ~ Type, CO2, subset = Plant == "Quebec") Error in `contrasts<-`(`*tmp*`, value = "contr.treatment") : contrasts can be applied only to factors with 2 or more levels Here Type is a factor for which only one level occurs within the "Quebec" subset. This is some