This is slightly more verbose, but perhaps
do.call("seq", as.list(c(extendrange(D_orig, f=0.1), len=100)))
Best,
Ista
On Mon, Feb 3, 2014 at 9:00 AM, Lorenz, David wrote:
> Berry,
> It sounds like you just need a little helper function like this:
>
> ser <- function(x, len=100, f=0.1) {
>
<- c(41, 12, 38, 29, 50, 39, 22)
seqr(range=extendrange(m, f=0.1), len=5)
# Takes min and max of range if thae vector has more than two elements.
seqr(range=m, by=3)
---
From: lor...@usgs.gov
Date: Mon, 3 Feb 2014 08:00:41 -0600
Subject: Re: [Rd] seq range argument
To: berryboessen
Berry,
It sounds like you just need a little helper function like this:
ser <- function(x, len=100, f=0.1) {
dr <- extendrange(x, f=f)
return(seq(dr[1L], dr[2L], length.out=len))
}
I called it ser, short for sequence extended range. Use it thusly:
Ijustneed <- ser(D_orig)
Hope this h
Hello dear developers,
I find myself often having the result of "range" oder "extendrange", which I
want to create a sequence with.
But "seq" needs two seperate arguments "from" and "two".
Could an argument "range" be added?
Otherwise I will have to create an object with the range (may come from
