-Original Message-
> From: r-devel-boun...@r-project.org [mailto:r-devel-boun...@r-project.org] On
> Behalf
> Of Patrick Burns
> Sent: Wednesday, April 24, 2013 2:30 AM
> To: Duncan Murdoch
> Cc: r-devel
> Subject: Re: [Rd] as.name and namespaces
>
> Here is an
On Wed, Apr 24, 2013 at 4:29 AM, Patrick Burns wrote:
> Here is an example problem:
>
>> mycall <- expression(lm(Y ~ x))[[1]]
>> mycall
> lm(Y ~ x)
>> newname <- "stats::lm"
>
>> desiredResult
> stats::lm(Y ~ x)
>
> I've solved the problem in the kludgy way of
> deparsing, fixing the string and th
There's also the brute force option:
> mycall <- expression(lm(Y ~ x))[[1]]
> mycall[[1]] <- quote(stats::lm)
> mycall
stats::lm(Y ~ x)
> eval(mycall, list(Y=rnorm(5),x=1:5))
Call:
stats::lm(formula = Y ~ x)
Coefficients:
(Intercept)x
0.07430 0.02981
On Apr 24, 2013, a
Here is an example problem:
> mycall <- expression(lm(Y ~ x))[[1]]
> mycall
lm(Y ~ x)
> newname <- "stats::lm"
> desiredResult
stats::lm(Y ~ x)
I've solved the problem in the kludgy way of
deparsing, fixing the string and then parsing.
I like Duncan's third method, but it seems like
it assumes
On 13-04-23 3:51 PM, Patrick Burns wrote:
Okay, that's a good reason why it shouldn't.
Why it should is that I want to substitute
the first element of a call to be a function
including the namespace.
Three ways:
1. Assign the function from the namespace locally, then call the local one.
2.
On Apr 23, 2013, at 21:51 , Patrick Burns wrote:
> Okay, that's a good reason why it shouldn't.
>
> Why it should is that I want to substitute
> the first element of a call to be a function
> including the namespace.
Offhand, I'd say that it shouldn't be a problem, but do you have a more
concr
Okay, that's a good reason why it shouldn't.
Why it should is that I want to substitute
the first element of a call to be a function
including the namespace.
Pat
On 23/04/2013 18:32, peter dalgaard wrote:
On Apr 23, 2013, at 19:23 , Patrick Burns wrote:
'as.name' doesn't recognize a name w
On Apr 23, 2013, at 19:23 , Patrick Burns wrote:
> 'as.name' doesn't recognize a name with
> its namespace extension as a name:
>
> > as.name("lm")
> lm
> > as.name("stats::lm")
> `stats::lm`
> > as.name("stats:::lm")
> `stats:::lm`
>
>
> Is there a reason why it shouldn't?
Any reason why it
'as.name' doesn't recognize a name with
its namespace extension as a name:
> as.name("lm")
lm
> as.name("stats::lm")
`stats::lm`
> as.name("stats:::lm")
`stats:::lm`
Is there a reason why it shouldn't?
Pat
--
Patrick Burns
pbu...@pburns.seanet.com
twitter: @burnsstat @portfolioprobe
http://w
