On Saturday 24 March 2007 12:12 pm, Gabor Grothendieck wrote:
> It matches in the sense of grep or regexpr
>
> grep("a", "ab") > 0
> regexpr("a", "ab") > 0
>
> Try this:
>
> x <- c("2006-01-01error", "2006-01-01")
> as.Date(x, "%Y-%m-%d") + ifelse(regexpr("^-..-..$", x) > 0, 0, NA)
>
Well, sti
It matches in the sense of grep or regexpr
grep("a", "ab") > 0
regexpr("a", "ab") > 0
Try this:
x <- c("2006-01-01error", "2006-01-01")
as.Date(x, "%Y-%m-%d") + ifelse(regexpr("^-..-..$", x) > 0, 0, NA)
On 3/24/07, Vladimir Dergachev <[EMAIL PROTECTED]> wrote:
> On Saturday 24 March 2007
On Saturday 24 March 2007 6:21 am, Prof Brian Ripley wrote:
> This is how strptime() works: it processes the input to match the format.
Except that the format does not match the string - there are leftover
characters. Even by R's own definition:
> match("a", "ab")
[1] NA
as, of course, is reaso
This is how strptime() works: it processes the input to match the format.
On Fri, 23 Mar 2007, Vladimir Dergachev wrote:
> I have encountered a nuance in as.Date() behaviour that is not altogether
> obvious - not sure whether this is intended or not:
>
>> as.Date("2001-01-01error")
> [1] "2001-0
Hi,
I have encountered a nuance in as.Date() behaviour that is not altogether
obvious - not sure whether this is intended or not:
> as.Date("2001-01-01error")
[1] "2001-01-01"
I.e. it ignores the rest of the characters. This happens both in 2.3.1 and
2.4.1 versions.
This also happens wit
