> PROTECT(y=x); and
This has no sense as y is just the same pointer as x. By doing this you
did not create any new data, if you modify y, x will be modified. y does
not need protection as x is probably protected.
> PROTECT (y = duplicate(x)); ?
This will allocate new memory for data in x and c
First, thanks to those of you who responded to my previous post about my
code that was taking longer and longer to process. After following your
suggestions, and I now thinking that the problem was some calls to
Rf_duplicate in my C code.
So I'm hoping I could get some clarification on what Rf_du
