doable. You can
treat the array x as a vector just like lower level R does and access the
contents using the formula it uses.
-Original Message-
From: R-devel On Behalf Of Sokol Serguei
Sent: Friday, February 12, 2021 5:50 PM
To: r-devel@r-project.org
Subject: Re: [Rd] Unexpected behavior of
Le 12/02/2021 à 23:49, Sokol Serguei a écrit :
Le 12/02/2021 à 22:23, Rui Barradas a écrit :
Hello,
Yes, although there is an accepted solution, I believe you should
post this solution there. It's a base R solution, what the question
asks for.
And thanks, I would have never reminded myself
Le 12/02/2021 à 22:23, Rui Barradas a écrit :
Hello,
Yes, although there is an accepted solution, I believe you should post
this solution there. It's a base R solution, what the question asks for.
And thanks, I would have never reminded myself of slice.index.
There is another approach -- pr
Hello,
Yes, although there is an accepted solution, I believe you should post
this solution there. It's a base R solution, what the question asks for.
And thanks, I would have never reminded myself of slice.index.
Rui Barradas
Às 20:45 de 12/02/21, robin hankin escreveu:
Rui
> x <- array(
Rui
> x <- array(runif(60), dim = c(10, 2, 3))
> array(x[slice.index(x,1) %in% 1:5],c(5,dim(x)[-1]))
(I don't see this on stackoverflow; should I post this there too?) Most of
the magic package is devoted to handling arrays of arbitrary dimensions and
this functionality might be good to include
Hello,
This came up in this StackOverflow post [1].
If x is an array with n dimensions, how to subset by just one dimension?
If n is known, it's simple, add the required number of commas in their
proper places.
But what if the user doesn't know the value of n?
The example below has n = 3, and
