I does help! Thank you for clarifications!
Sent from my iPhone
> On Feb 4, 2020, at 9:36 AM, Rui Barradas wrote:
>
> Hello,
>
> Don't worry, we've seen worst questions :).
> Inline.
>
> Às 13:20 de 04/02/20, ismael ismael escreveu:
>> I am now aware that I should not post this type of quest
Hello,
Don't worry, we've seen worst questions :).
Inline.
Às 13:20 de 04/02/20, ismael ismael escreveu:
I am now aware that I should not post this type of questions on this
group. However, I would like to have some clarifications related to the
response you've already provided. The code you p
I am nowaware that I should not post this type of questions on this group.
However, Iwould like to have some clarifications related to the response you've
alreadyprovided. The code you provided yields accurate results, however I still
haveissues grasping the loop process in case 1 & 2.
In ca
Hello,
Inline.
Às 11:04 de 03/02/20, Martin Maechler escreveu:
ismael ismael via R-devel
on Mon, 3 Feb 2020 04:09:24 -0600 writes:
> It works!!!
> Thank you so much for your help!
and it was an "R help" question which Rui so generously answered.
But this is the R-devel mail
> ismael ismael via R-devel
> on Mon, 3 Feb 2020 04:09:24 -0600 writes:
> It works!!!
> Thank you so much for your help!
and it was an "R help" question which Rui so generously answered.
But this is the R-devel mailing list.
Please do *NOT* misuse it for R-help questions
It works!!!
Thank you so much for your help!
Sent from my iPhone
> On Feb 3, 2020, at 3:47 AM, Rui Barradas wrote:
>
> Hello,
>
> You can solve the problem in two different ways.
>
> 1. Redefine storage1 as a matrix and extract the aic *in* the loop.
>
> storage1 <- matrix(0, 4, 4)
> for(p
Hello,
You can solve the problem in two different ways.
1. Redefine storage1 as a matrix and extract the aic *in* the loop.
storage1 <- matrix(0, 4, 4)
for(p in 0:3){
for(q in 0:3){
storage1[p + 1, q + 1] <- arima(etc)$aic
}
}
2. define storage1 as a list.
storage1 <- vector("list",
Hello
I am trying to extract AICs from an ARIMA estimation with different
combinations of p & q ( p =0,1,2,3
and q=0,1.2,3). I have tried using the following code unsucessfully. Can
anyone help?
code:
storage1 <- numeric(16)
for (p in 0:3){
for (q in 0:3){
storage1[p] <- arima(x,order=
