subsitute(expr), with only one argument, is only useful inside of a
function and then only when the expression, expr, involves an argument
to the function. Then the unevaluated actual arguments to the
function are substituted into the [unevaluated] expression.
E.g.,
f <- function(x, y=stop("y
On Jul 21, 2014, at 10:07 AM, Mick Jordan wrote:
> I came across this code in library.R
>
> package <- as.character(substitute(package))
>
> where package is the first argument to the "library" function.
>
> I've been racking my brains to understand why this is not just an elaborate
> (and i
I came across this code in library.R
package <- as.character(substitute(package))
where package is the first argument to the "library" function.
I've been racking my brains to understand why this is not just an
elaborate (and ineffcient) way to write:
package <- "package"
E.g.
> package <-
