Re: [Rd] lm() gives different results to lm.ridge() and SPSS

2017-05-05 Thread Nick Brown
variable that corresponds to the interaction term. Am I missing something? Is there a way to perform the regression with the interaction in SPSS without computing the interaction as a separate variable? Best, Nick - Original Message - From: "John Fox" To: "Nick

Re: [Rd] lm() gives different results to lm.ridge() and SPSS

2017-05-05 Thread Nick Brown
m: "peter dalgaard" To: "Viechtbauer Wolfgang (SP)" , "Nick Brown" Cc: r-devel@r-project.org Sent: Friday, 5 May, 2017 3:33:29 PM Subject: Re: [Rd] lm() gives different results to lm.ridge() and SPSS Thanks, I was getting to try this, but got side tracked by ac

Re: [Rd] lm() gives different results to lm.ridge() and SPSS

2017-05-05 Thread Nick Brown
ha ha ha). Nick - Original Message - From: "peter dalgaard" To: "Nick Brown" Cc: "Simon Bonner" , r-devel@r-project.org Sent: Friday, 5 May, 2017 10:02:10 AM Subject: Re: [Rd] lm() gives different results to lm.ridge() and SPSS I asked you before

Re: [Rd] lm() gives different results to lm.ridge() and SPSS

2017-05-04 Thread Nick Brown
umbers have no particular external meaning in lm.ridge(). Kind regards, Nick - Original Message - From: "Simon Bonner" To: "Nick Brown" , r-devel@r-project.org Sent: Thursday, 4 May, 2017 7:07:33 PM Subject: RE: [Rd] lm() gives different results to lm.ridge() and SPSS

[Rd] lm() gives different results to lm.ridge() and SPSS

2017-05-04 Thread Nick Brown
Hallo, I hope I am posting to the right place. I was advised to try this list by Ben Bolker (https://twitter.com/bolkerb/status/859909918446497795). I also posted this question to StackOverflow (http://stackoverflow.com/questions/43771269/lm-gives-different-results-from-lm-ridgelambda-0). I a