Hi, All:
I had some trouble debugging C source dynamically loaded into R , when I
issued N in gdb(or insight) , the debugger, instead of moving downward step by
step, jumped to strange positions (upward, downward, one step, a few steps
away).
To enter the debugger, I issued gdb(insight
It's working , Thanks a lot !!!
tong
- Original Message -
From: Prof Brian Ripley <[EMAIL PROTECTED]>
Date: Saturday, May 12, 2007 4:27 am
Subject: Re: [Rd] Problem with rnorm ?
To: Tong Wang <[EMAIL PROTECTED]>
Cc: R-devel
> 1) You are linking an executable against -lR. You can't do t
First of all, thanks to everybody for R.
I have written a program in C that requires some basic matrix
operations, namely the following:
- matrix multiplication and addition,
- determinant and transpose,
- inverse of a symmetric matrix.
Since I am a happy R user I thought I could call R from wi
I can't reproduce that with ggplot 0.4-0 as some of the functions you are
using do not appear to be part of ggplot (I suspect you are using a newer
version of ggplot than you have released) but the following illustrates
the difference using "R version 2.5.0 Patched (2007-05-01 r41405)"
and lattice
Hi everyone,
I've run into a bit of strange problem with implicit vs explicit
printing and the call stack. I've included an example at the bottom of
this email. The basic problem is that I have an S3 object with a
print method. When the object is implicitly printed (ie. typed
directly into the c
1) You are linking an executable against -lR. You can't do that as here,
for R is never initialized (and I very much doubt you will be able to
give a reference that recommended you to do that). You need to link
against standalone libRmath, or start up R properly if you really need R.
2) The ar
> #include
> #include
>
> int main(void){
> double x[3];
> for(int i=0;i<3;i++) x[i]=rnorm(0,1);
> printf("%lf,%lf,%lf",x[0],x[1],x[2]);
> return 0;
> }
>
> output : -8.773321,-8.773321,-8.773321
You probably have to call GetRNGstate() before rnorm and PutRNGstate() after.
At least
