look-ahead look-behind don't consume string so how does it advance through
the string - could someone clearly explain how it works.
re.sub(r'((?<=\A)|(?<=,))(?=,|\Z)', 'NA', ',1,,,two,3,,,')
'NA,1,NA,NA,two,3,NA,NA,NA'
re.sub(r'(?https://mail.python.org/mailman3//lists/python-list.python.org
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On 2026-08-09, Veek M wrote:
> look-ahead look-behind don't consume string so how does it advance through
> the string - could someone clearly explain how it works.
>
> re.sub(r'((?<=\A)|(?<=,))(?=,|\Z)', 'NA', ',1,,,two,3,,,')
> 'NA,1,NA,NA,two,3,NA,NA,NA'
It's matching the empty string. It'll
On Sat, 8 Aug 2026 04:25:43 - (UTC), Veek M wrote:
> On Sat, 8 Aug 2026 04:22:59 - (UTC), Veek M wrote:
>
>> On Sat, 8 Aug 2026 01:19:32 - (UTC), Lawrence D’Oliveiro wrote:
>>
>>> b'\xef\xbf\xbf\n'.decode()
>>
>> Could you explain how it works and what exactly is going on?
>>
>> fh
On Sat, 8 Aug 2026 01:19:32 - (UTC), Lawrence D’Oliveiro wrote:
> b'\xef\xbf\xbf\n'.decode()
Could you explain how it works and what exactly is going on?
fh.readline() returns a unicode string with the funny chars (bytes 0xff
0xff) encoded as \\xef \\xbf \\xbf - why is it \\? why not just u
On Sat, 8 Aug 2026 04:22:59 - (UTC), Veek M wrote:
> On Sat, 8 Aug 2026 01:19:32 - (UTC), Lawrence D’Oliveiro wrote:
>
>> b'\xef\xbf\xbf\n'.decode()
>
> Could you explain how it works and what exactly is going on?
>
> fh.readline() returns a unicode string with the funny chars (bytes 0x
So in kate, i Ctrl-Shift-U and type to enter a unicode codepoint of
0x. Then at the REPL prompt i do
fh = open('/tmp/x', 'rt', -1, 'ascii', 'backslashreplace', None)
and i get
fh.readline()
'\\xef\\xbf\\xbf\n'
Since I wrote two bytes 0xff and 0xff into Kate - why am i getting 0xef
0
