parameter, then the server return correct reply.
para = MyData(0.5,0.01)
server.Fun([para ], [ ] )
From:
dieter
To:
[email protected]
Date:
01/23/2015 03:26 PM
Subject:
Re: python client call Java server by xmlrpc
Sent by:
"Python-list"
[email protected] writes:
>
[email protected] writes:
> I have xmlrpc server written in Java, and it has a method like
>
> Fun( vector, vector), the vector is array of user-defined object, which is
> a class extends HashMap.
>
> And I call it like:
>
> server = xmlrpclib.ServerProxy("http://myserver";)
>
> server.Fun( [
