On Aug 12, 12:21 pm, [EMAIL PROTECTED] wrote:
>
> I cannot understand why 'c' constitutes a group here without being
> surrounded by "(" ,")" ?
>
> >>>import re
> >>> m = re.match("([abc])+", "abc")
> >>> m.groups()
>
> ('c',)
>
It sounds from the other replies that this is just the way re's work
In article <[EMAIL PROTECTED]>,
[EMAIL PROTECTED] wrote:
> Fairly new to this regex thing, so this might be very juvenile but
> important.
>
> I cannot understand and why 'c' constitutes a group here without being
> surrounded by "(" ,")" ?
>
> >>>import re
> >>> m = re.match("([abc])+", "abc")
[EMAIL PROTECTED] wrote:
> Fairly new to this regex thing, so this might be very juvenile but
> important.
>
> I cannot understand and why 'c' constitutes a group here without being
> surrounded by "(" ,")" ?
>
import re
m = re.match("([abc])+", "abc")
m.groups()
> ('c',)
>
> Grat
On Aug 12, 1:31 pm, Fabio Z Tessitore <[EMAIL PROTECTED]>
wrote:
> Il Sun, 12 Aug 2007 17:21:02 +, linnewbie ha scritto:
>
> > Fairly new to this regex thing, so this might be very juvenile but
> > important.
>
> > I cannot understand and why 'c' constitutes a group here without being
> > surro
[EMAIL PROTECTED] wrote:
> Fairly new to this regex thing, so this might be very juvenile but
> important.
>
> I cannot understand and why 'c' constitutes a group here without being
> surrounded by "(" ,")" ?
>
import re
m = re.match("([abc])+", "abc")
m.groups()
> ('c',)
>
> Grat
Il Sun, 12 Aug 2007 17:21:02 +, linnewbie ha scritto:
> Fairly new to this regex thing, so this might be very juvenile but
> important.
>
> I cannot understand and why 'c' constitutes a group here without being
> surrounded by "(" ,")" ?
>
import re
m = re.match("([abc])+", "abc")
>
