On Sun, Feb 22, 2009 at 9:02 PM, [email protected]
wrote:
> On Feb 23, 9:25 am, MRAB wrote:
>> [email protected] wrote:
>> > Hello all,
>> >I am writing an application where I need to open a shared
>> > file on a remote machine using python script. I tried using the
>> > f
On Feb 22, 9:02 pm, "[email protected]"
wrote:
> On Feb 23, 9:25 am, MRAB wrote:
>
>
>
> > [email protected] wrote:
> > > Hello all,
> > > I am writing an application where I need to open a shared
> > > file on a remote machine using python script. I tried using the
> > > f
On Feb 23, 9:25 am, MRAB wrote:
> [email protected] wrote:
> > Hello all,
> > I am writing an application where I need to open a shared
> > file on a remote machine using python script. I tried using the
> > following function:
>
> > f = urllib.open("\\remote_machine\\folder1\\fil
[email protected] wrote:
Hello all,
I am writing an application where I need to open a shared
file on a remote machine using python script. I tried using the
following function:
f = urllib.open("\\remote_machine\\folder1\\file1.doc")
I also tried using
class urllib.Fa
On Sun, Feb 22, 2009 at 8:13 PM, [email protected]
wrote:
> Hello all,
> I am writing an application where I need to open a shared
> file on a remote machine using python script. I tried using the
> following function:
>
> f = urllib.open("\\remote_machine\\folder1\\file1.doc")
>
>
Hello all,
I am writing an application where I need to open a shared
file on a remote machine using python script. I tried using the
following function:
f = urllib.open("\\remote_machine\\folder1\\file1.doc")
I also tried using
class urllib.FancyURLopener(...)
but d
