Hi Tim,
Oups, sorry. I only just realized my mistake and the meaning of your
message.
On Thu, Mar 30, 2006 at 09:27:02AM +0200, Armin Rigo wrote:
> >>> t = (1,2,3)
> >>> t += [4,5,6]
> TypeError: can only concatenate tuple (not "list") to tuple
>
> >>> t += array([4,5,6])
>
Hi Tim,
On Wed, Mar 29, 2006 at 08:45:10AM -0700, Tim Hochberg wrote:
> Ouch. Assuming the same path is followed with tuples, I think that this
> means the following behaviour will continue:
>
> >>> t = (1,2,3)
> >>> a = array([4,5,6])
> >>> t += a
> >>> t
> array([5, 7, 9])
I fell into the
On 3/29/06, Greg Ewing <[EMAIL PROTECTED]> wrote:
> Tim Hochberg wrote:
>
> > Still, perhaps for Py3K it's worth considering
> > if PyNumber_InplaceAdd should only call __iadd__ and __add__, not
> > __radd__. Thus giving the target object complete control during inplace
> > adds.
>
> That's probabl
Tim Hochberg wrote:
> Still, perhaps for Py3K it's worth considering
> if PyNumber_InplaceAdd should only call __iadd__ and __add__, not
> __radd__. Thus giving the target object complete control during inplace
> adds.
That's probably reasonable, although it would break
the conceptual notion t
Armin Rigo wrote:
> So if we provide a complete fix, [].__add__(x) will be modified to
> return NotImplemented instead of raising TypeError if x is not a list,
> and then [1,2,3]+array([4,5,6]) will fall back to array.__radd__() as
> before.
Ah, okay. That seems like it would work.
--
Greg
_
On 3/29/06, Tim Hochberg <[EMAIL PROTECTED]> wrote:
> Ouch. Assuming the same path is followed with tuples, I think that this
> means the following behaviour will continue:
>
> >>> t = (1,2,3)
> >>> a = array([4,5,6])
> >>> t += a
> >>> t
> array([5, 7, 9])
>
> That's not particularly desirable
On 3/29/06, Armin Rigo <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> On Tue, Mar 28, 2006 at 09:50:49AM -0800, Guido van Rossum wrote:
> > C extensions are my main worry -- OTOH if += for a list can already
> > passes arbitrary types as the argument, then any extension types
> > should be ready to expec
Armin Rigo wrote:
> Hi Greg,
>
> On Wed, Mar 29, 2006 at 12:38:55PM +1200, Greg Ewing wrote:
>
>>I'm really thinking more about the non-inplace operators.
>>If nb_add and sq_concat are collapsed into a single slot,
>>it seems to me that if you do
>>
>> a = [1, 2, 3]
>> b = array([4, 5, 6])
>>
Hi all,
On Tue, Mar 28, 2006 at 09:50:49AM -0800, Guido van Rossum wrote:
> C extensions are my main worry -- OTOH if += for a list can already
> passes arbitrary types as the argument, then any extension types
> should be ready to expect this, right?
Yes, I don't think C extensions are going to
Hi Greg,
On Wed, Mar 29, 2006 at 12:38:55PM +1200, Greg Ewing wrote:
> I'm really thinking more about the non-inplace operators.
> If nb_add and sq_concat are collapsed into a single slot,
> it seems to me that if you do
>
>a = [1, 2, 3]
>b = array([4, 5, 6])
>c = a + b
>
> then a wi
Armin Rigo wrote:
>>>> [].__add__(5)
>TypeError: can only concatenate list (not "int") to list
Would that be much of a loss? It doesn't really
give you much more information than something like
Unsupported operand types for '+': list, int
and what it does give is based on the assumpt
Travis E. Oliphant wrote:
> I can't imaging anybody relying on an in-place operations to return a
> "different" object, but we could make the change and run all the
> NumPy/SciPy tests to see what happens.
I'm really thinking more about the non-inplace operators.
If nb_add and sq_concat are col
On 3/28/06, Armin Rigo <[EMAIL PROTECTED]> wrote:
> Hi,
>
> On Mon, Mar 27, 2006 at 08:00:09PM -0800, Guido van Rossum wrote:
> > So for consistency we want a += b to also execute a.__iadd__. The
> > opcode calls PyNumber_InplaceAdd; I think that PyNumber_InplaceAdd
> > (and PySequence_InplaceConca
Hi,
On Mon, Mar 27, 2006 at 08:00:09PM -0800, Guido van Rossum wrote:
> So for consistency we want a += b to also execute a.__iadd__. The
> opcode calls PyNumber_InplaceAdd; I think that PyNumber_InplaceAdd
> (and PySequence_InplaceConcat, if it exists) should test for both the
> numeric and the s
Greg Ewing wrote:
> Travis E. Oliphant wrote:
>
>> I think this can be fixed easily by first checking the sequence slot for
>> a sq_concat function before calling PyNumber_InPlaceAdd.
>
> However, if this *is* fixed, it looks like it's going to
> break NumPy, in the sense that it will no longer
Travis E. Oliphant wrote:
> I think this can be fixed easily by first checking the sequence slot for
> a sq_concat function before calling PyNumber_InPlaceAdd.
However, if this *is* fixed, it looks like it's going to
break NumPy, in the sense that it will no longer be able
to force an arithmetic
On 3/27/06, Travis E. Oliphant <[EMAIL PROTECTED]> wrote:
> Guido van Rossum wrote:
> > On 3/27/06, Travis Oliphant <[EMAIL PROTECTED]> wrote:
> >> If you have Numeric or numpy installed try this:
> >>
> >> #import Numeric as N
> >> import numpy as N
> >>
> >> a = range(10)
> >> b = N.arange(10)
>
Guido van Rossum wrote:
> On 3/27/06, Travis Oliphant <[EMAIL PROTECTED]> wrote:
>> If you have Numeric or numpy installed try this:
>>
>> #import Numeric as N
>> import numpy as N
>>
>> a = range(10)
>> b = N.arange(10)
>>
>> a.__iadd__(b)
>>
>> print a
>>
>> Result:
>>
>> [0, 1, 2, 3, 4, 5, 6, 7,
Guido van Rossum wrote:
> On 3/27/06, Travis Oliphant <[EMAIL PROTECTED]> wrote:
>
>>If you have Numeric or numpy installed try this:
>>
>>#import Numeric as N
>>import numpy as N
>>
>>a = range(10)
>>b = N.arange(10)
>>
>>a.__iadd__(b)
>>
>>print a
>>
>>Result:
>>
>>[0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
On 3/27/06, Travis Oliphant <[EMAIL PROTECTED]> wrote:
>
> If you have Numeric or numpy installed try this:
>
> #import Numeric as N
> import numpy as N
>
> a = range(10)
> b = N.arange(10)
>
> a.__iadd__(b)
>
> print a
>
> Result:
>
> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>
If you have Numeric or numpy installed try this:
#import Numeric as N
import numpy as N
a = range(10)
b = N.arange(10)
a.__iadd__(b)
print a
Result:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Contrast the returned output with
import numpy as N
a = range(10)
b = N.arange
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