Tim Peters added the comment:
Arguments to `remainder()` are converted to floats, and the returned value is
also a float. These specific arguments convert to the same float:
>>> a = 12345678901234567890
>>> b = 12345678901234567891
>>> float(a) == float(b)
True
And the float they convert _t
Steven D'Aprano added the comment:
math.remainder performs *floating point* remainder. That means it has to
convert the arguments to floats first, and there is no float capable of
representing either of those two numbers exactly:
py> '%f' % float(12345678901234567890)
'12345678901234
New submission from David Hwang :
These two numbers are off by 1, and so should give different answer to
>>> math.remainder(12345678901234567890,3)
1.0
>>> math.remainder(12345678901234567891,3)
1.0
--
components: Library (Lib)
messages: 361211
nosy: David Hwang
priority: normal
severit
