Hey all
I want to include a php located on a different server. Is this possible?
If so, what would be the pest way to do it?
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T * FROM employees",$db);
if ($myrow = mysql_fetch_array($result)) {
// display list if there are records to display
do {
printf("%s %s\n", $PHP_SELF,
$myrow["id"], $myrow["first"], $myrow["last"]);
} while ($myrow = mysql_fetch_array(
I am running a red hat 9 linux box with Apache 1.3.27 with PHP 4 what is
the default location for the php.ini file
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Thanks all
It is in the /etc.
thanks
Adam Voigt wrote:
/etc probably, just do a "locate php.ini" on the console.
On Wed, 2003-06-25 at 10:51, Blake Schroeder wrote:
I am running a red hat 9 linux box with Apache 1.3.27 with PHP 4 what is
the default location for the php.ini file
Hey all
I used to include a perl script via Sever Side Include how could I do
this in php?
example:
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Blake Schroeder
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Whats the best way to validate email address (check for white space,
check for .com, .net.edu etc)
-Blake
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AIL PROTECTED]> wrote:
What do you say to someone who says:
"PHP is just a kiddie language"?
(Source: http://www.dhtmlcentral.com/forums/topic.asp?TOPIC_ID=19373)
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basically i just want
to
search a mysql database by someones surname.
cheers!
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Black Mesa Computers/Internet Service
Grants, NM 87020
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Many Thanks in advance.
Regards,
ERWIN
__
Do you Yahoo!?
New Yahoo! Photos - easier uploading and sharing.
http://photos.yahoo.com/
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+--(http
("Impossibile spostare il file, controlla l'esistenza o i permessi
della directory
dove fare l'upload.");
} else {
die("Problemi nell'upload del file " . $_FILES["upfile"]["name"]);
}
echo "L'upload del file " . $_FILES["upfile"]["name"] .
le works. I have tried some experiments with
a $path_to_css variable, but I have not had much success. I think
part of the problem is that I might be stumbling over escaping
everything properly.
Is there a better way to do what I am trying to do?
Thanks,
Danny
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ng php?
I have this
but don't know how to specify how to store the pictures on the server...
thanks!
thanks
Matt
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Matt
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m1->bar1;
$bar2 = $num2->bar2;
echo"Hi\n";
echo"$bar1\n";
echo"$bar2\n";
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Justin
Thank you now I have a working example to go from.
Justin Patrin wrote:
On Wed, 11 Aug 2004 16:35:33 -0500, Blake Schroeder <[EMAIL PROTECTED]> wrote:
I am trying to change some of my functions in to classes and objects. I
have been checking out the php.net and google and sti
'
>
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e too.
Sure unplug your network cable.
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What is wrong with whis syntax:
$array = array("$_POST['input_1']","$_POST['input_2']");
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The form that is being submitted can only be a POST or a GET not both
example:
How can you do both?
-Blake
Maldiv wrote:
Hello,
I have a php update form which use $_POST and $_GET too. I call the update
like this update.php?id=1
And after the user submit the form with new data I use command lik
Put a hidden field in your form named id.
-Blake
Blake Schroeder wrote:
The form that is being submitted can only be a POST or a GET not both
example:
How can you do both?
-Blake
Maldiv wrote:
Hello,
I have a php update form which use $_POST and $_GET too. I call the
update
like this
Hey
I cant figureout the syntax please help
echo "Some text".aFunction()."some more text";
The function is not working.
Thanks
-B
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The following code works:
echo "Some text";
aFunction();
echo "Some more text";
-B
Matt Matijevich wrote:
[snip]
echo "Some text".aFunction()."some more text";
[/snip]
Have you checked to see if aFunction() is returning anything?
.
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Everyone
Thank you for all the great feedback. Since my function doesnt return
data it just echos it to the browser.
When I use this format it does not display correctly
echo "some text" . aFunction() . "some more text";
If I use the orginal code it displays fine.
echo "Some text";
aFunction();
as
experimental... Basicly, this would get currupt?
(wierd-var-test.php)
Or are there some other details I've missed?
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s I've missed?
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