Hi,
I am attempting to create an advanced form with 9 different search fields.
I am using the WHERE 1 AND sql function to add onto the generated end sql
function so I don't have to created over 300,000 IF statements. The code below
is showing up this error:
[quote]Warning: mysql_fetch_assoc()
[snip] Warning: mysql_fetch_assoc(): supplied argument is not a valid
MySQL result resource in
/var/www/vhosts/numyspace.co.uk/web_users/home/~unn_w11014928/public_html/search.php
on line 261[/snip]
It would appear that your query is not returning a result. Echo out the
query and try running
Jonathan Davies wrote:
> I am attempting to create an advanced form with 9 different search
> fields. I am [concatenating a bunch of bits together] so I don't
> have to [create] over 300,000 IF statements.
> mysql_fetch_assoc(): supplied argument is not a valid MySQL
> result resource on line 261
Hi,
Is there a way to make difference between line breaks and paragraphs, when
I save a text to a database from a user input? The new line characters (\n,
\r) are not too consequent to determine when did the user only one new line
or more new lines. (Some clients make only \n or \r, some others ma
On 2 Nov 2012, at 19:32, Simon Dániel wrote:
> Is there a way to make difference between line breaks and paragraphs, when
> I save a text to a database from a user input? The new line characters (\n,
> \r) are not too consequent to determine when did the user only one new line
> or more new lines
Hello,
i have compile PHP 5.4.8 on my Debian System. I have before Version 5.4.7.
I delete before all old Files from PHP and then run the commands:
./configure --sysconfdir=/usr/local/etc --with-pear --enable-bcmath
--with-bz2=/usr --disable-calendar --enable-ctype --without-curl
--without-cur
I'm sorry. This code just makes me weep.
Let's just take a quick look at this line here:
> $rsSearch = mysql_query($sqlSearch);
You have not supplied a database connection, so mysql_query will fail.
Further, you have not even checked the result to *see* if it failed.
Once you fix those things,
Hi Jonathan,
Haven't used MySql for ages. More used to Oracle and PostgreSql.
Your table nmc_cd contains foreign keys pointing to nmc_category and
nmc_publisher. Create a view containing all the data from those three tables
using implicit joins as the data in table nmc_cd should NOT contain any
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