Re: [PHP] php variables in a backtick command

The quotes are only for the shell command which does not use quotes around password. Thanks for the feedback. Jonathan "Sebastian" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > well $user['password'] has no double quotes around it. > > - Original Message - > From: "Jo

Re: [PHP] php variables in a backtick command

Ah, that is a good idea, putting the command in a variable and then executing the variable. I have doen that before but did not think of it now. Too many things going on. Thanks! Jonathan "Rory Browne" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > I'm not sure about variable

Re: [PHP] php variables in a backtick command

I'm not sure about variable expansion with backticks(I don't use backticks, if necessary I use shell_exec() instead). I'm just after installing a fresh SuSE 9.1, and php is giving me a segfault at the minute, with that particular code, but if you were using double quotes you could: $command = "add

Re: [PHP] php variables in a backtick command

well $user['password'] has no double quotes around it. - Original Message - From: "Jonathan Duncan" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Saturday, December 11, 2004 8:09 PM Subject: [PHP] php variables in a backtick command > I am trying to run a shell command with backtick