> > > for($m=1;$m<=5;$m++){
> > > $div_idd[$m]=${'row->sub' . $m . 'd'};
> > > }
I'm not sure if it will work, but you might try either using the
mysql_fetch_array($result); function and then refer to them by
$row["src1d"]; or try $div_idd[$m] = $row->$$name; where $name = "sub" . $m
. "d"; I'm
Ok. That makes since.
Thanks
Steve
At 04:20 PM 7/26/2002 -0500, you wrote:
>var names can only be letters, numbers, and underscores.
>
>Jim Grill
>Support
>Web-1 Hosting
>http://www.web-1hosting.net
>- Original Message -
>From: "Steve Buehler" <[EMAIL PROTECTED]>
>To: "PHP" <[EMAIL PROT
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