Re: [PHP] Re: Eval var from query

2003-07-14 Thread Kevin Stone
- Original Message - From: "Shawn McKenzie" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, July 14, 2003 1:51 PM Subject: Re: [PHP] Re: Eval var from query > Thanks Kevin! That works great. It outputs: hi my name is Shawn > > Now if I want

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Shawn McKenzie
Got it! eval( '$newdata = "'.$data.'";'); Thanks! Shawn "Shawn McKenzie" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Thanks Kevin! That works great. It outputs: hi my name is Shawn > > Now if I want to assign $data to another var, let's say $newdata and have it > eval the $n

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Shawn McKenzie
Thanks Kevin! That works great. It outputs: hi my name is Shawn Now if I want to assign $data to another var, let's say $newdata and have it eval the $name var inside of that. How would that work? Meaning I want to $newdata = hi my name is Shawn Thanks! Shawn "Kevin Stone" <[EMAIL PROTECTED

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Kevin Stone
;";'; $name = 'Shawn'; eval($code); // prints "hi may name is Shawn". Hope that makes it more clear. - Kevin - Original Message - From: "Kevin Stone" <[EMAIL PROTECTED]> To: "PHP-GENERAL" <[EMAIL PROTECTED]> Sent: Monday, J

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Kevin Stone
The string you send to eval() must be valid PHP code. So try this.. eval( 'echo "'.$data.'";'); - Kevin - Original Message - From: "Shawn McKenzie" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, July 14, 2003 1:15 PM Subject: [PHP] Re: Eval var from query > eval($data) > >