Re: [PHP] Is there no one who can help me out there.

2001-09-18 Thread Mark
On Tue, 18 Sep 2001 16:29:21 -0700 (PDT), John Holcomb wrote: >I have a text input field in my form. I need the user >to be able to enter something like: Hello, I need # >help. After which they click on a submit button. The >succeeding page then takes this text and tries to >display it and tri

Re: [PHP] Is there no one who can help me out there.

2001-09-18 Thread David Robley
On Wed, 19 Sep 2001 08:59, John Holcomb wrote: > I have a text input field in my form. I need the user > to be able to enter something like: Hello, I need # > help. After which they click on a submit button. The > succeeding page then takes this text and tries to > display it and tries to stor

Re: [PHP] Is there no one who can help me out there.

2001-09-18 Thread Rebecca Donley
in ASP you could just use a "replace" function. Rebecca >From: John Holcomb <[EMAIL PROTECTED]> >To: Rebecca Donley <[EMAIL PROTECTED]> >Subject: Re: [PHP] Is there no one who can help me out there. >Date: Tue, 18 Sep 2001 16:48:29 -0700 (PDT) > >Thank you.

Re: [PHP] Is there no one who can help me out there.

2001-09-18 Thread John Holcomb
Thank you. This has been the biggest help so far. But, if it's a user entered string is their anyway to do this without having to parse the string and looking for the # sign and then reconstructing the string. That would be very difficult to do. I would appreciate any comments you might have.

Re: [PHP] Is there no one who can help me out there.

2001-09-18 Thread Rebecca Donley
John, I had a similar problem when passing # from one page to another as an html anchor. What worked for me was separating the # in quotes as follows: echo "?id=" . $row[0] . "#" . strtolower($row[1]) . '">'; When I did this I had no problem passing the entire string without the end being i

Re: [PHP] Is there no one who can help me out there.

2001-09-18 Thread Jason Bell
John, someone did reply to you alread. here let me snip from that email oOoOoOoOoOoO Gerard Samuel Said: oOoOoOoOoOoO check to see if the field where the info is going into is long enough. ie varchar(50). anything more than 50 get cut off. > being diplayed on the succeeding web pag