RE: [PHP] Easy HTML PHP question

2001-03-29 Thread Paulson, Joseph V. \"Jay\"
; Tim Ward; 'Fabian Raygosa'; [EMAIL PROTECTED] Subject: RE: [PHP] Easy HTML PHP question function ImgClick(imgName) { ThisImage = document.all[imgName]; document.form1.fred.value = ThisImage.value; } I'm pretty sure the event will f

RE: [PHP] Easy HTML PHP question

2001-03-29 Thread Tim Ward
ch 2001 16:17 > To: 'Tim Ward'; 'Fabian Raygosa'; [EMAIL PROTECTED] > Subject: RE: [PHP] Easy HTML PHP question > > > Yeah that would work if I knew how to do that? Any > suggestions on how to go > about doing that? > > Thanks, > Jay >

RE: [PHP] Easy HTML PHP question

2001-03-29 Thread Paulson, Joseph V. \"Jay\"
r to the following disclaimer in respect of this message: http://www.stivesdirect.com/e-mail-disclaimer.html > -Original Message- > From: Fabian Raygosa [mailto:[EMAIL PROTECTED]] > Sent: 29 March 2001 01:11 > To: Paulson, Joseph V. "Jay"; [EMAIL PROTECTED] > Sub

RE: [PHP] Easy HTML PHP question

2001-03-28 Thread Tim Ward
f this message: http://www.stivesdirect.com/e-mail-disclaimer.html > -Original Message- > From: Fabian Raygosa [mailto:[EMAIL PROTECTED]] > Sent: 29 March 2001 01:11 > To: Paulson, Joseph V. "Jay"; [EMAIL PROTECTED] > Subject: Re: [PHP] Easy HTML PHP question > >

Re: [PHP] Easy HTML PHP question

2001-03-28 Thread Fabian Raygosa
For images i think its different, i don't think you can force the image name that value instead the value gets turned into "button_x" and "button_y" with relation to where the mouse clicked on the image. In any event try using GET method instead of POST method to see whats displayed on the url st