RE: [PHP] Date aritmetic

2002-01-02 Thread Martin Towell
o:[EMAIL PROTECTED]] Sent: Thursday, January 03, 2002 2:20 PM To: Carlos Fernando Scheidecker Antunes Cc: PHP-GENERAL Subject: Re: [PHP] Date aritmetic Not mentioning that you could've taken a look at http://www.php.net/manual/en/ref.datetime.php yourself, here goes: $days_diff=(mktime(0,0,0,$mon

RE: [PHP] Date aritmetic

2002-01-02 Thread Martin Towell
convert both in dates into a time stamp using mktime() subtract the two figures you get back then divide by 86400 (60sec/min * 60min/hr * 24hr/day) -Original Message- From: Carlos Fernando Scheidecker Antunes [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 03, 2002 12:57 PM To: PHP-GE

Re: [PHP] Date aritmetic

2002-01-02 Thread Bogdan Stancescu
Well, actually $days_diff=(mktime(0,0,0,$month2,$day2,$year2)-mktime(0,0,0,$month1,$day1,$year1))/86400; but you probably got that... :-) Bogdan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To con

Re: [PHP] Date aritmetic

2002-01-02 Thread Bogdan Stancescu
Not mentioning that you could've taken a look at http://www.php.net/manual/en/ref.datetime.php yourself, here goes: $days_diff=(mktime(0,0,0,$month2,$day2,$year2)-mktime(0,0,0,$month2,$day2,$year2))/86400; Bogdan Carlos Fernando Scheidecker Antunes wrote: > Hello all, > > I would like to know