Re: [PHP] revised query problem (sorry)

2003-10-28 Thread Curt Zirzow
* Thus wrote Pablo Gosse ([EMAIL PROTECTED]): > Yours: > > $query="SELECT payment > FROM payment > WHERE payment.dln='".$_POST["dln"]."' > = users.dln='".$_POST["dln"]."' > and payment.payment='".$_POST["payment"]."'"; > > Mine: > > $query="SELECT payment > FROM payment > WHERE payment.dln

RE: [PHP] revised query problem (sorry)

2003-10-28 Thread Jay Blanchard
[snip] $query="SELECT payment FROM payment WHERE payment.dln='".$_POST["dln"]."' = users.dln='".$_POST["dln"]."' and payment.payment='".$_POST["payment"]."'"; Will this work? [/snip] Aside from what Chris said (excellent advice!) the query above will not work because the 4rth line = users.d

RE: [PHP] revised query problem (sorry)

2003-10-28 Thread Pablo Gosse
Yours: $query="SELECT payment FROM payment WHERE payment.dln='".$_POST["dln"]."' = users.dln='".$_POST["dln"]."' and payment.payment='".$_POST["payment"]."'"; Mine: $query="SELECT payment FROM payment WHERE payment.dln='".$_POST["dln"]."' AND users.dln='".$_POST["dln"]."' and payment.pa