> Jon, John, Ifrim, the == worked ... thank you!!
> gotta read up on it now :)
>
> Cameron, dropping the extra () did not work :(
>
> thanks for the suggestions folks!
> andrew
>
Remember that '=' means assign what is on the right to what is on the left,
whereby '==' means is what is on the left
8 AM
> To: '[EMAIL PROTECTED]'; '[EMAIL PROTECTED]'
> Subject: RE: [PHP] parse error driving me nuts ...
>
>
> Instead of
>
> if ((mysql_num_rows($result)) = 1)
>
> try
>
> if ((mysql_num_rows($result)) == 1)
>
>
> HTH
> Jon
>
> hi, can anyone help me spot the parse error?
> It's throwing up on the first "if" line, and for the life of me I cannot
> find it! :)
>
> tia,
> andrew
>
>
> include("db_connect_params.inc");
> $sql="select path from PHOTO where pid =1";
> $link_id = mysql_connect($host, $usr, $pass);
> $result
Try to use == instead of =
Sorin Ifrim
- Original Message -
From: Andrew <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, February 15, 2001 5:33 PM
Subject: [PHP] parse error driving me nuts ...
> hi, can anyone help me spot the parse error?
> It's throwing up on the fir
Instead of
if ((mysql_num_rows($result)) = 1)
try
if ((mysql_num_rows($result)) == 1)
HTH
Jon
-Original Message-
From: Andrew [mailto:[EMAIL PROTECTED]]
Sent: 15 February 2001 15:34
To: [EMAIL PROTECTED]
Subject: [PHP] parse error driving me nuts ...
hi, can anyone help me spot th
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