RE: [PHP] nested if in a for statement

2002-12-17 Thread Edward Peloke
iables and this is causing it to pass. -Original Message- From: Tim Ward [mailto:[EMAIL PROTECTED]] Sent: Tuesday, December 17, 2002 4:14 PM To: James Brennan; [EMAIL PROTECTED] Subject: Re: [PHP] nested if in a for statement looks ok as long as you are really testing what you mean to.

Re: [PHP] nested if in a for statement

2002-12-17 Thread Kevin Stone
Oops sorry didn't mean to add to the spam. LOL -Kevin - Original Message - From: "Kevin Stone" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, December 17, 2002 2:24 PM Subject: Re: [PHP] nested if in a for statement > Prepare the rubber

Re: [PHP] nested if in a for statement

2002-12-17 Thread Kevin Stone
Prepare the rubber glove... Chang this // $i <= count($userVars) To this // $i < count($userVars); Arrays start at index 0, not 1. -Kevin - Original Message - From: "James Brennan" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, December 17, 2002 2:03 PM Subject: [PHP] neste

Re: [PHP] nested if in a for statement

2002-12-17 Thread Douglas Douglas
I think your error is this: $userVars = array($nameFirst, $nameLast, $pass, $pass2, $auth, $dob_year, $dob_month, $dob_day); for ($i=0; $i <= count($userVars); $i++) { if (empty($userVars[$i])) { echo "please enter all required info";

Re: [PHP] nested if in a for statement

2002-12-17 Thread Tim Ward
looks ok as long as you are really testing what you mean to. As you've written it if any of the variables are an empty string, zero, logical false or not set then the if statement will be true. what is $auth? Tim Ward http://www.chessish.com mailto:[EMAIL PROTECTED] - Original Message - F