Re: [PHP] alzheimers and confused

2001-11-18 Thread Joe Stump
if(!eregi("\.jpg$",$image) || !eregi("\.jpeg$",$image)) die("ERROR: doesn't appear to be a JPeg image!"); --Joe On Fri, Nov 16, 2001 at 09:45:07PM -0500, jtjohnston wrote: > OK kids, I'm not 19 ... my old brain gets tired easily and my wife is > complaining that I stay up too late PHPing :) >

RE: [PHP] alzheimers and confused

2001-11-17 Thread Robert Klinkenberg
It depends on how you exactly formulated the test // if((!strpos($yourimage, ".jpg")) or (!strpos($yourimage, ".jpeg"))) if((!strpos($yourimage, ".jpg")) and (!strpos($yourimage, ".jpeg"))) THe first is if !jpg or !jpeg while the second if statement tests for if !jpg and !jpeg another wa