On Saturday 15 November 2003 02:38, Teren wrote:
> Sorry, i copied a little extra stuff from console. This is what it is,
> Anyways, it works fine if I put 0 in for 1 on line 9 where it uses the
> rand(), but it include 0 and I can't have 0. Is there some way to fix that?
> If you need to see the d
Teren wrote:
> Anyways, it works fine if I put 0 in for 1 on line 9 where it
> uses the rand(), but it include 0 and I can't have 0.
Why not just change the following:
> if($ran == $sh) {
> $add = "no";
> }
to:
> if($ran == $sh || $ran == 0) {
> $add = "no";
>
lmes" <[EMAIL PROTECTED]>
To: "Teren" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Friday, November 14, 2003 1:28 PM
Subject: Re: [PHP] Random Function
> You're code doesn't make sense. You're looking for 3 random numbers,
between
> 1 and 3 i
You're code doesn't make sense. You're looking for 3 random numbers, between
1 and 3 inclusive. Umm.. 1,2,3.
Do you want them in a random order, or something?
Maybe the upper limit of rand() and how many numbers you're looking for
($n), should be different??
---John Holmes...
- Original Mes
4 matches
Mail list logo
