Re: [PHP] 'undef' as an argument value

2002-03-12 Thread Jordan S. Jones
function foo ($arg1_required, $arg2_options = "") { if (empty($arg2_optional) { print "not passed"; } else { print "explicit"; } } Or you can go the other route. Jordan "Rodent Of Unusual Size" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTE

Re: [PHP] 'undef' as an argument value

2002-03-11 Thread Rodent of Unusual Size
"Johnson, Kirk" wrote: > > http://www.php.net/manual/en/function.func-num-args.php will > return the number of arguments passed to the function. Bingo! That will do the trick.. Thanks *very* much! -- #kenP-)} Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ Author, developer, op

RE: [PHP] 'undef' as an argument value

2002-03-11 Thread Johnson, Kirk
bject: Re: [PHP] 'undef' as an argument value > > > Rick Emery wrote: > > > > function foo($arg1_required, $arg2_optional="") > > if ($arg2_optional=="") { > > print "not passed"; > > } > > el

Re: [PHP] 'undef' as an argument value

2002-03-11 Thread Rodent of Unusual Size
Rick Emery wrote: > > function foo($arg1_required, $arg2_optional="") > if ($arg2_optional=="") { > print "not passed"; > } > else { > print "explicit"; > } > } No, I said 'undef' because I mean 'undefined'. The argument can have *any* value; I need to know when

RE: [PHP] 'undef' as an argument value

2002-03-11 Thread Rick Emery
function foo($arg1_required, $arg2_optional="") if ($arg2_optional=="") { print "not passed"; } else { print "explicit"; } } -Original Message- From: Rodent of Unusual Size [mailto:[EMAIL PROTECTED]] Sent: Monday, March 11, 2002 3:17 PM To: [EMAIL PROTECTED