Because you are wiping out your $sponsor variable in that commented-out
code.
On Sat, 28 Dec 2002, James Brennan wrote:
> I am getting a "Warning: mysql_fetch_row(): supplied argument is not a valid
> MySQL result resource" error only when the commented-out code bellow
> (starting from $id = bb_s
I am getting a "Warning: mysql_fetch_row(): supplied argument is not a valid
MySQL result resource" error only when the commented-out code bellow
(starting from $id = bb_sponsor...) is added. If I omit the code the
resource is recognized as valid. Can anyone explain?
Thanks,
loop
P.S. - I know
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