RE: [PHP] variable issue

2001-11-09 Thread Clint Tredway
Friday, November 09, 2001 2:37 PM To: PHP General Subject: [PHP] variable issue Hey everyone, I need some help with a variable issue. How can I delcare a variable and then if a url variable of the same name is present use that value instead? this is what I have: if(!$dte) { $dte=date("j&

RE: [PHP] variable issue

2001-11-09 Thread Matthew Luchak
2001 2:37 PM To: PHP General Subject: [PHP] variable issue Hey everyone, I need some help with a variable issue. How can I delcare a variable and then if a url variable of the same name is present use that value instead? this is what I have: if(!$dte) { $dte=date("j", time()+$ctime); } els

Re: [PHP] variable issue

2001-11-09 Thread R'twick Niceorgaw
replace the if statement if(!$dte) with if (!isset($dte)) - Original Message - From: "Johnson, Kirk" <[EMAIL PROTECTED]> To: "PHP General" <[EMAIL PROTECTED]> Sent: Friday, November 09, 2001 2:35 PM Subject: RE: [PHP] variable issue > The else cla

RE: [PHP] variable issue

2001-11-09 Thread Johnson, Kirk
The else clause can be removed, since it is not doing anything. What is the error message? Kirk > Hey everyone, I need some help with a variable issue. How can > I delcare a variable and then if a url variable of the same > name is present use that value instead? > > this is what I have: > if

[PHP] variable issue

2001-11-09 Thread Clint Tredway
Hey everyone, I need some help with a variable issue. How can I delcare a variable and then if a url variable of the same name is present use that value instead? this is what I have: if(!$dte) { $dte=date("j", time()+$ctime); } else { $dte=$dte; } and this causing an error in the 'if' expression