Damian Brown wrote:
' ;
$link = $link . '' ;
echo $link ; ?>
is not working, I want to output $row[2] as a hyperlink
as it is the refering URL, but the above is just showing blank in the
output, with no link and no text in the output table
You kind of need something betw
Damian Brown wrote:
' ;
$link = $link . '' ;
echo $link ; ?>
is not working, I want to output $row[2] as a hyperlink
as it is the refering URL, but the above is just showing blank in the
output, with no link and no text in the output table
You kind of need something betw
' ;
$link = $link . '' ;
echo $link ; ?>
is not working, I want to output $row[2] as a hyperlink
as it is the refering URL, but the above is just showing blank in the
output, with no link and no text in the output table
--
www.phpexpert.org/truefaith.htm
"True Faith is n
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